What is the total amount that First Consumer Bank will receive after lending Jane $7,000 for three years at an interest rate of 5 percent, compounded annually?

Answers

Answer 1

Answer: Given:
principal = 7,000
interest rate = 5% compounded annually
term = 3 years

A = P (1 + r/n)^nt

A = future amount to be received by First Consumer Bank
P = loan principal
r = rate
n = number of times compounded in a year
t = term

A = 7,000 ( 1 + 5%/1)^1x3
A = 7,000 (1.05)³
A = 7,000 (1.157625)
A = 8,103.375

First Consumer Bank will receive 8,103.375 from Jane after lending 7,000 for 3 years compounded annually at 5%.

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Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95% confidence interval which was (19.1, 28.9). What is the margin of error?A) 2.5 years
B) 4.9 years
C) 5 years
D) 6.7 years

Answers

The correct answer for the question that is being presented above is this one: "D) 6.7 years." Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95% confidence interval which was (19.1, 28.9). The margin of error is 6.7 years

Answer: it’s b

Step-by-step explanation:

Just did it

Solve each equation
x^2+6x+9=1

Answers

x= -4 and x=-2

x^2+6x+9=1
(x+3)^2=1
x+3=+/-1
x+3=-1 / x-3=1
x=-4
x=-2

Answer:x=-2,-4

Step-by-step explanation:

Liquid A has a density of 0.7g/cm^3liquid B has a density of 1.6g/cm^3

140g of liquid A is and 128g of liquid B are mixed to make liquid C

work out the density of liquid C

Answers

density is defined as mass per unit volume

in this case liquids A and B with 2 different densities are mixed and we are asked to find the density of the liquid C

liquid A has a density of 0.7 g/cm³

mass of liquid A added is 140 g

therefore volume of liquid A added is - 140 g / 0.7 g/cm³ = 200 cm³

liquid B has a density of 1.6 g/cm³

mass of liquid B added is 128 g

volume of liquid B added is - 128 g / 1.6 g/cm³ = 80 cm³

the total mass of liquid C after adding liquid A and B = 140 g + 128 g = 268 g

total volume in liquid C - 200 cm³ + 80 cm³ = 280 cm³

density of liquid C = mass / volume

= 268 g / 280 cm³ = 0.957 g/cm³

density of liquid C - 0.957 g/cm³

$\rho = (m)/(V) \Rightarrow V=(m)/(\rho)$
ρ - density, m - mass, V - volume

Liquid A:
$\rho=0.7 \ (g)/(cm^3) \nm=140 \ g \n\n V=(140 \ g)/(0.7 \ (g)/(cm^3))=200 \ cm^3$

Liquid B:
$\rho=1.6 \ (g)/(cm^3) \nm=128 \ g \n\n V=(128 \ g)/(1.6 \ (g)/(cm^3))=80 \ cm^3$

Liquid C:
$m=140 \ g + 128 \ g=268 \ g \nV=200 \ cm^3 + 80 \ cm^3=280 \ cm^3 \n \n\rho=(268 \ g)/(280 \ cm^3) \approx 0.96 \ (g)/(cm^3)$

The density of liquid C is approximately 0.96 g/cm³.

A strip of wood 66 inches long is to be cut into 51/2-inch pieces. How many pieces can be cut?

Answers

So basically 25.5 inch pieces. If that is true then maybe 2 pieces can be cut.

M(x) =5
Find m(2)
I have no idea how to do this help me

Answers

Answer:

Step-by-step explanation:

All this is saying is when there is one x value it is equal to 5

so, applying that logic, 2 fives is equal to 2*5=10

so when x=2, it is equal to 10

Hope this helps you out!!!

if x = 5 then m(2)= 10

What is the sum of 2/5 and 2/4

Answers

Okay you want to find the common factor right? So then 2/5 fifth and 2/4 fourth have only 20 in common. So 2/5 times 4 is? 8/20 do not simplify so then 2/4 times five is 10/20 so then 8+10=18/20 simplify and you get 9/10.

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