The model rocket is in the air for 0 seconds according to the given equation, which implies an immediate impact upon launch.
In this mathematical scenario, the model rocket's height p(x) over time x (elapsed seconds) is given by the quadratic equation p(x) = 16x^2 + 32x. The total amount of time the rocket is in the air will be the point when the rocket returns to ground level. This occurs when p(x) = 0, which represents the rocket's height being zero feet above the ground.
We can find out when this occurs by solving the quadratic equation for x. We can rearrange the quadratic equation to 16x^2 + 32x = 0. Factoring out 16x gives us 16x(x + 2) = 0. Solving for x will give two potential solutions: x = 0 (the initial launch point) and x = -2. However, since time cannot be negative in this context, we discard the -2 and our answer is x=0 s, the total time the model rocket will be in the air after being launched is 0 seconds.
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A) 6 souvenir brochure
B) 10 souvenir brochure
C) 12 souvenir brochure s
D) 18 souvenir brochure
6 souvenir brochures must be purchased in order Which is the correct answer would be an option (A)
A linear equation is defined as an equation in which the highest power of the variable is always one.
The slope-intercept form is y = mx+c, where the slope is m and the y-intercept is c.
For the functions, we have that:
The set-up fee is the admission fee.
The price per souvenir brochure is the slope.
Hence the functions are given by:
R(x) = 10 + 6.25x
S(x) = 13 + 5.75x
We have been given the total cost at Concert R and Concert S to be the same.
So R(x) = S(x).
⇒ 10 + 6.25x = 13 + 5.75x
⇒ 0.5x = 3
⇒ x = 3/0.5
⇒ x = 6.
Therefore, 6 souvenir brochures must be purchased in order for the total cost at Concert R and Concert S to be the same.
Learn more about the Linear equations here:
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Answer:
6 souvenir brochure
Step-by-step explanation:
K12 <3
miles, m
neither c, calories or m, miles
both c, calories and m, miles
To find the percentage of observations between two values in a normal distribution, we can convert the values to z-scores and use a z-table to find the corresponding areas. In this case, the percentage of observations between 0.372 and 0.428 is 68.26%.
To find the percentage of observations that will lie between 0.372 and 0.428 in a normal distribution with a mean of 0.40 and standard deviation of 0.028, we need to find the area under the curve between these two values.
Using a standard normal distribution table or z-table, we can convert the values to z-scores by subtracting the mean and dividing by the standard deviation. The z-score for 0.372 is (0.372 - 0.40) / 0.028 = -1, and the z-score for 0.428 is (0.428 - 0.40) / 0.028 = 1.
By looking up the corresponding area for these z-scores in the z-table, we find that the area to the left of -1 is 0.1587 and the area to the left of 1 is 0.8413. To find the percentage between -1 and 1, we subtract the smaller area from the larger area: 0.8413 - 0.1587 = 0.6826 or 68.26%.
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