MATHEMATICS MIDDLE SCHOOL

Simpilfy:
5x - 2y +3x

Answers

Answer 1
Answer: It would be 0 bc 

5x-2y=0
then 0+3x=0

So the answer is 0
  Hope this helps:)

Related Questions

Shady grove is 40 miles away. Middletown is 1/5 of the way there and Parkview is 2/5 of the way.7. How many miles away is Middletown? _______8. How many miles away is Parkview? ________9. Ocean city is 42 miles away from home. We have gone 35 miles. What fraction of the distance have we gone.________answer this asap due tomorrow and first one gets brainlest answer
How to draw 30/4 as a mixed number
Help thx.............. :)
In Loma, Montana, on January 15, 1972, the temperature increased 103 degrees in a 24-hour period. If the lowest temperature on that day was -54 degrees Fahrenheit, what was the highest temperature?
Does (-15, -691) make the equation y = -51x - 74 true?​

Write an expression for the sequence of operations described below.Raise the quotient of 8 and v to the 2nd power

Do not simplify any part of the expression.

Answers

quotient refers to division:

(8/v)² ⇒ (8/v)(8/v) = 8*8 / v*v = 64/v²

When you raise a fraction to a power, you multiply the fraction by itself according to the power raised.

Then, do the usual steps of multiplying fractions.
1) multiply numerators.
2) multiply denominators
3) simplify fraction produced.

Sean's mom asks him how long his homework will take. He tells her that he needs to read for 25 minutes and also do some math problems that will take m minutes. All together, his homework will take h minutes. Write an equation for the number of minutes Sean's homework will take h, if his math problems take m minutes

Answers

Answer:  The required equation is h=25+m.

Step-by-step explanation:  Given that Sean's mom asks him how long his homework will take.

He tells her that he needs to read for 25 minutes and also do some math problems that will take m minutes. All together, his homework will take h minutes.

We are to write an equation for the number of minutes Sean's homework will take h, if his math problems take m minutes.

Since Sean needs to read for 25 minutes and do some math problem for m minutes, so total time that Sean will take will be

25+m.

Also, since Sean takes h minutes altogether to complete his homework, so the equation is written as

25+m=h\n\n\Rightarrow h=25+m.

Thus, the required equation is h=25+m.

Answer:

h=25+m

Step-by-step explanation:

Hope this helped I did it on Khan Academy

What is the value of x?​

Answers

Answer:

X=123213132312

Step-by-step explanation:
The answer is 211
Because you add them

I don't get area and the distributive property

Answers

area is just the length multiplied by the width 
and distributive property is multiplying the number outside of the brackets with the numbers inside the brackets 
like this
3(5+4)
u would do  3x5=15
and then 3x4=12
which is 15+12=27 
what about area and distributive property? example question maybe?

Laketown had 215 inches of snowfall last year, but only 155 inches this year. What was the percent decrease in snowfall for Laketown to the nearest percent? A. 28% B. 39% C. 72% D. 139%I think A

Answers

Okay, so FIRST you would subtract 215 - 155, which is 60, and THEN divide it by 215, so 60 divided by 215 = 0.27, and rounded that is 0.28, then you move the decimal two places to the right to make it a percentage so your answer would be A., 28%
I hope I helped! =D

*lets do this step by step*

1st. subtract 
215 - 155 = 60 

2nd. divide
60 ÷ 215 = 0.2790697674 

3rd. we round 
0.2790697674 = 0.28 

answer? A.) 0.28 

hope this helps:)
and don't forget 2
MARK ME BRAINLIEST! :D

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. The box plot compares the monthly average temperature (in degrees Fahrenheit) recorded in the towns of Springwood and Meadows from April to October. Match each phrase to its correct value. the median of the temperatures at Springwood _______


the median of the temperatures at Meadows: ______


the interquartile range of the temperatures at Springwood:_______


the interquartile range of the temperatures at Meadows:_______


the difference of the medians as a multiple of their average interquartile range:_______

Answers

Hello,

The median of the temperatures at Springwood is 86. (median is at the middle).

the median of the temperatures at Meadows is 73. (median is at the middle).

The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).

The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).

the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.

Answer: The median of the temperatures at Springwood is 86.    

The median of the temperatures at Meadows is 73.  

The interquartile range of the temperatures at Meadows is 12.  

The interquartile range of the temperatures at Springwood is 14.

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians  = 1 x (Average interquartile range)

Step-by-step explanation:

In a box - whisker plot , the vertical line in box represents the median value.

The left end of box denotes Lower quartile and the right end of the box Upper quartile.

By considering the given picture,

For Meadows ,

Median = 73

The median of the temperatures at Meadows is 73.                           (1)

Lower quartile = 68

Upper quartile = 80

Interquartile range = Upper quartile- Lower quartile

Interquartile range=80-68 = 12

The interquartile range of the temperatures at Meadows is 12.     (2)

For Springwood,

Median = 86

The median of the temperatures at Springwood is 86.                 (3)

Lower quartile = 77

Upper quartile = 91

Interquartile range = Upper quartile- Lower quartile

= 91-77 = 14

The interquartile range of the temperatures at Springwood is 14.         (4)

Difference in medians = 86-73 = 13              [From (1) and (3)]

Average interquartile range = (12+14)/(2)=13    [From (2) and (4)]

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians = 1 x (Average interquartile range)
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