How do you solve for sinxcos2x+cosxsin2x=0 ?
Answers
Answer 1
Answer:
LHS is nothing but (using sin (a+b) = sin a cos b + cos a sin b)
sin (x+2x) = sin 3x = 0
so 3x = npi
or
x = npi/3
sin (x+2x) = sin 3x = 0
so 3x = npi
or
x = npi/3
Answer 2
Answer:
The answer is x = n p i divided by 3
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Find point-slope.(3/2, -1/2)(-2/3, 1/3)x1: 3/2x2: -2/3y1: -1/2y2: 1/3to find slope:m= y2-y1/x2-x1point-slope:y-y1=m(x-x1)
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Answers
The answer for 14 x 2645 = 37,030
A. Greater than
B. Less than
C. Equal to
Answers
now, an OCTAgon, has OCTA=8, sides
an HEXAgon, has HEXA=6, sides
check what their external angles are, and compare :)
Answers
you first expand the brackets so
14y-15-10y
then you put the like terms together so you do 14y-10y= 4y
4y-15 which is the answer
14y-15-10y
then you put the like terms together so you do 14y-10y= 4y
4y-15 which is the answer
14y - 5(3-2y)
Distribute what's in the parenthesis
14y- (15+10y)
Combine like terms
24y-15
Distribute what's in the parenthesis
14y- (15+10y)
Combine like terms
24y-15
Answers
First factor the equation
(x-10)(x+2) = 0
Then solve for (x-10) and (x+2)
x=10
x=-2
(x-10)(x+2) = 0
Then solve for (x-10) and (x+2)
x=10
x=-2
(warning: this is quite long :P)
the steps are:
Looking at the expression x² +8x-20,we can see that the first coefficient is 1, the second coefficient is 8 and the last term is -20.
Now multiply the first coefficient (1) by the last term (-20) to get (1)·(-20)=-20.
Now the question is: what two whole numbers multiply to -20 (the previous product).
factors of -20:
1,2,4,5,10,20
-1, -2, -4, -5, -10, -20
note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up to multiply to -20.
1*(-20) = -20
2*(-10) = -20
4*(-5) = -20
(-1)*(20*) = -20
(-2)*(10* = -20
(-4)*(5) = -20
now let's add up each pair of factors to see if one pair adds to the middle coefficient:
first number second number sum
1 -20 1+(-20)=-19
2 -10 2+(-10)=-9
4 -5 4+(-5)= -1
-1 20 -1 +20= 19
-2 10 -2+10=8
-4 5 -4+5=1
From the table above, we can see that the two numbers -2 and 10 multipy to -20 and add up to 8.
Now replace the middle term 8x with -2x+10x. Remember, -2 and 10 add up to 8. so this shows us that -2x+10x=8x.
x²+-2x+10x -20 Replace the second term 8x with -2x +10x.
(x²-2x)+(10x-20) Group the terms into two pairs.
x(x-2x)+(10x-20) Factor out the GCF x from the first group.
x(x-2)+10·(x-2) Factor out 10 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
(x+10)·(x-2) Combine like terms. Or factor out thge common term x-2.
-----
ANSWER:
So, x² + 8·x -20 factors to (x+20)·(x-2.
In other words, x² + 8·x-20=(x+10)·(x-2)
THIS IS HARD TO UNDERSTAND, BUT HOPE THIS HELPED YOU! AND HOPE YOU GET IT TOO!!!
:D
Hope it helps :)
the steps are:
Looking at the expression x² +8x-20,we can see that the first coefficient is 1, the second coefficient is 8 and the last term is -20.
Now multiply the first coefficient (1) by the last term (-20) to get (1)·(-20)=-20.
Now the question is: what two whole numbers multiply to -20 (the previous product).
factors of -20:
1,2,4,5,10,20
-1, -2, -4, -5, -10, -20
note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up to multiply to -20.
1*(-20) = -20
2*(-10) = -20
4*(-5) = -20
(-1)*(20*) = -20
(-2)*(10* = -20
(-4)*(5) = -20
now let's add up each pair of factors to see if one pair adds to the middle coefficient:
first number second number sum
1 -20 1+(-20)=-19
2 -10 2+(-10)=-9
4 -5 4+(-5)= -1
-1 20 -1 +20= 19
-2 10 -2+10=8
-4 5 -4+5=1
From the table above, we can see that the two numbers -2 and 10 multipy to -20 and add up to 8.
Now replace the middle term 8x with -2x+10x. Remember, -2 and 10 add up to 8. so this shows us that -2x+10x=8x.
x²+-2x+10x -20 Replace the second term 8x with -2x +10x.
(x²-2x)+(10x-20) Group the terms into two pairs.
x(x-2x)+(10x-20) Factor out the GCF x from the first group.
x(x-2)+10·(x-2) Factor out 10 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
(x+10)·(x-2) Combine like terms. Or factor out thge common term x-2.
-----
ANSWER:
So, x² + 8·x -20 factors to (x+20)·(x-2.
In other words, x² + 8·x-20=(x+10)·(x-2)
THIS IS HARD TO UNDERSTAND, BUT HOPE THIS HELPED YOU! AND HOPE YOU GET IT TOO!!!
:D
Hope it helps :)
Answers
The best way to solve this is to write it out part by part.
The first part is "the sum of 8 and 3," which is (8+3)
The second part is "...times a number," so we have n(8+3)
Lastly, "...is 23," means n(8+3) = 23, so here's the equation. In order to solve for n, divide both sides by (8+3) so 23/(8+3) which is 23/11. So the "number" is 23/11.
The first part is "the sum of 8 and 3," which is (8+3)
The second part is "...times a number," so we have n(8+3)
Lastly, "...is 23," means n(8+3) = 23, so here's the equation. In order to solve for n, divide both sides by (8+3) so 23/(8+3) which is 23/11. So the "number" is 23/11.
Let the number be x
8+3x=23
3x=23-8
3x=15
x=5
The number is 5
8+3x=23
3x=23-8
3x=15
x=5
The number is 5
Answers
The first time you look at this, you would think that you can just cancel the
(m+2) off of each side. But then you're left with (m+3) = (m-2), and there's
no solution for this. So you have to go back and do it the hard way.
Expand each side of the equation. (Clear the parentheses.)
m² + 5m + 6 = m² - 4
Subtract m² from each side:
5m + 6 = -4
Subtract 6 from each side:
5m = -10
Divide each side by 5:
m = -2
(m+2) off of each side. But then you're left with (m+3) = (m-2), and there's
no solution for this. So you have to go back and do it the hard way.
Expand each side of the equation. (Clear the parentheses.)
m² + 5m + 6 = m² - 4
Subtract m² from each side:
5m + 6 = -4
Subtract 6 from each side:
5m = -10
Divide each side by 5:
m = -2