Subtract the quotient of 18 and 2 from the sum 22 and 9
Answers
Quotient, implies division, so the quotient of 18 and 2 is 6:
18/2=6
Sum implies addition, so the sum of 22 and 9 is 31:
22+9=31
Now we can subtract the quotient of 18 and 2, '6', from the sum of 22 and 9, '31'.
31-6=25
Answer=25
Answer:22
Step-by-step explanation:
Quotient, implies division, so the quotient of 18 and 2 is 6:
18/2=9
Sum implies addition, so the sum of 22 and 9 is 31:
22+9=31
Now we can subtract the quotient of 18 and 2, '6', from the sum of 22 and 9, '31'.
31-6=25
Answer=22
Related Questions
Order the fractions from least to greatest 3/5, 7/8, 5/6
Help !! Geometry I need to find the measure of each angle in the figure.
1) 5x-2y=4. 2) 3x-5y=13 x-2y=53x+y=9
The atomic number of an element B is 17. The number of electrons in its ion B will be:(a) 17 (b) 18. (c) 19. (d) 20.answer with explanation
ASAP!!!
Answers
Answer:
x=11
Step-by-step explanation:
Since both angles are congruent, 2x-10=12, so x=11
Answer:
×=11
Step-by-step explanation:
2x-10=12
2×=22
×=11
2(11)-10
22-10=12
Answers
Answer:
6.3
Step-by-step explanation:
You want to add 1, 5, and 70 up. Then you would get 76. Next you want to divide 76 into 12. And there you go, 6.3 is the answer
(I hoped this helped. This was a bit confusing to me and difficult but i wanna try to be useful for once lol..)
Answer:
5.83
Step-by-step explanation:
70 / 12
Answers
The expression which would determine the probability that both digits are even which is required for bicycle lock is (4P1)(3P1)/(9P2).
What do you understand by the term permutation?
The permutation is the arrangement of the things or object in a systematic order, in all the possible ways. The order of arrangement in permutation is in linear.
A bicycle lock requires a two-digit code of numbers 1 through 9, and any digit may be used only once. The probability of choosing 2 digits from 9 is,
There are total 4 even numbers {2,4,6,8}. The probability of choosing first digit's even from 4 even numbers is,
For the second digit to be even is,
Thus, the favorable outcome is, and total outcome is
. Thus, the expression which would determine the probability that both digits are even is,
Thus, the expression which would determine the probability that both digits are even which is required for bicycle lock is (4P1)(3P1)/(9P2).
Learn more about the permutations here;
#SPJ3
The correct answer is:
A. P(both even) =
The expression would determine the probability that both digits are even.
Answers
a = apples
8m + 3a = 18 Equation 1
3m + 5a = 14.50 Equation 2
Lets multiply equation 1 by 5 and equation 2 by 3
The new equations are:
45m + 15a = 90
9m + 15a = 43.5
Subtract them and get:
36m = 46.5
m = 1.30 Divide both sides by 36
Substitute m into equation 2 (either is fine, but choose the easier one)
3(1.30) + 5a = 14.5
3.9 + 5a = 14.6 Expand the bracket
5a = 10.6 Minus both sides by 3.9
a = 2.12 Divide both sides by 5
Mangoes cost $1.30
Apples cost $2.12 (more like $2.10)
I feel that my working out is wrong, but that is how you work out the answer.
Answers
For each of those ...
The second chair can be any one of the remaining 14.
For each of those ...
The third chair can be any one of the remaining 13.
For each of those ...
The fourth chair can be any one of the remaining 12.
Number of ways to fill the 4 chairs = (15 x 14 x 13 x 12) = 32,760 .
But ...
Each set of 4 people can be seated in (4 x 3 x 2 x 1) = 24 orders.
So each group of 4 people is represented 24 times among the 32,760.
If the order doesn't matter, you're really asking how many different
groups of 4 people can occupy the front row.
That's (32,760) / (24) = 1,365 sets of 4 members, in any order.
John, Kathy, Alex, Mia
John, Alex, Kathy, Mia
John, Alex, Mia, Kathy
John, Mia, Alex, Kathy
John, Mia, Kathy, Alex
Alex, John, Kathy, Mia
Alex, John, Mia, Kathy
There are many more, but my guess would be 16 combinations. Test for yourself if you don't think thats right!