One linear function, t(x), can be modeled by the values in the table below. A second linear function can be modeled by the equation 3x − 2y + 6 = 0. When comparing the x-intercepts of these lines, which function has the largest x-intercept and what is this value?x t(x)
−2 −15
−1 −10
0 −5
1 0
2 5
t(x) has the largest x-intercept: 1.
3x − 2y + 6 = 0 has the largest x-intercept: 3.
t(x) has the largest x-intercept: −5.
3x − 2y + 6 = 0 has the largest x-intercept: −2.

Answers

Answer 1
Answer:

That answer is wrong. the correct answer is C.

Answer 2
Answer: At x-intercept, y value = 0,
 
For t(x), x = 1 when y = 0, i.e. x-intercept = 1

for 3x - 2y + 6 = 0, when y = 0,
3x - 2(0) + 6 = 0
3x + 6 = 0
3x = -6
x = -6/3 = -2
i.e. x-intercept = -2

Therefore, t(x) has the highest x-intercept of 1.

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What is -5 5/8 + 3 1/2?
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The polynomial of degree 5, P(x) has leading coefficient 1, has roots of multiplicity 2 at x=2 and x=0, and a root of multiplicity 1 at x=-4
Find a possible formula for P(x)

Answers

yes, this is fun

remember the roots of a polynomial is
P(x)=(x-r1)(x-r2)...(x-rn)


so we have 5th degreee, means all exponents shoud add to 5

leading coeficient of 1, that means
P(x)=1x^n+bx^(n-1)...zx^0
means highest power coefience it 1

roots of multiplicity 2 at x=2 and x=0, means those roots show up 2 times each
root at x=2 means (x-2), it has multiplicity 2 so (x-2)^2
root at x=0 means (x-0), it has multiplicyt 2 so (x-0)^2

last one, multiplicity 1 and root at x=-4
(x-(-4))^1=(x+4)


so the polynomial is
P(x)=(x-2)^(2)(x)^(2)(x+4)

Solve this inequality 8z+3-2z<51

Answers

8z - 2z < 51 - 3 
6z < 48 
z < 48/6 
z < 8 
Answer: z < 8
First, let's work on the left hand side of your inequality, the 8z+3-2z
This means, for instance, to see if it can be simplified at all.
Multiply z and 8Multiply z and 1The z just gets copied along.The answer is zz8*z evaluates to 8z8*z+3 evaluates to 8z+3Multiply z and 1The z just gets copied along.The answer is zz2*z evaluates to 2z8z - 2z = 6zThe answer is 6z+38*z+3-2*z evaluates to 6z+3So, all-in-all, the left hand side of your inequality can be written as:6z+3Now, let's work on the right hand side of your inequality, the 51
The right hand side of your inequality can be written as: 51So with these (any) simplifications, the inequality we'll set out to solve is:
6z+3 ‹ 51
Move the 3 to the right hand side by subtracting 3 from both sides, like this:
From the left hand side:
3 - 3 = 0
The answer is 6zFrom the right hand side:
51 - 3 = 48

Now, the inequality reads:
6z ‹ 48 
To isolate the z, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)
around the z on the left side of the inequality.
The last step is to divide both sides of the inequality by 6 like this:
To divide z by 1The z just gets copied along in the numerator.The answer is z6z ÷ 6 = z48 ÷ 6 = 8The solution to your inequality is:
z ‹ 8 t
he answer is 48 
Multiply z and 2

Six boxes of crackers cost $18. At this
price, how much do 15 boxes cost?

Answers

Answer:

6x3=18 and 15x3= 45 so 45 is the answer.

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

18 divided by 6 is 3. and 3 times 15 is 45. And to check it do 45 divided by 15 and you get 3. so 45 is the answer.

If the width and height of a rectangular prism are each shrunk to one seventh of the original size but the length remains the same, what is the formula to find the modified surface area?

Answers

Hey there,

Let's say    'L'=length,  'W'=width, and  'H'=height.

The surface area of a rectangular prism is  

                         A  =  (2LW) + (2WH) + (2LH)  =  2 (LW + WH + LH)

If you shrink the width and height, then the new width is  W/7 
and the new height is H/7.

The new surface area is

                         A = (2 L W/7) + (2 W/7 H/7) + (2 L H/7) .

That's               A = 2 (LW/7 + WH/49 + LH/7) .

or you could write it as      A = 2/7 (LW + WH/7 + LH)

There are many more ways to massage the formula and write it 
in different ways, but I think writing it just that way is OK.

1) which expression is the GCF of the terms of the polynomial?16x^3+28^5y
A)4x^3
B)4x^5y
C)8x^5
D)112x^5y

Answers

First, the statement seems to have an error. The right polynomial must be 16x^3 + 28x^5y.

With that said, we have to find the greatest common divisor of the coefficients and take the common letter with its minimum exponent.

Greatest common divisor of 16 and 28 is determined by facoring both numbers and taking the common factors raised to the minimum power.

16 = 2^4
28 = 2^2 * 7

So, the common factor with the minimum power is 2^2 =4

The common letter with its minimum power is x^3.

So the GCF is 4x^3, i.e. option A)

Can you solve 64x³+y³ by factoring?

Answers

64x^3+y^3=(4x)^3+y^3\n\n=(4x+y)[(4x)^2-4xy+y^2]=(4x+y)(16x^2-4xy+y^2)
a^3+b^3=(a+b)(a^2-ab+b^2)\n-----------------\n64x^3+y^3=(4x)^3+y^3=(4x+y)[(4x)^2-4x\cdot y+y^2]=\n\n=(4x+y)(16x^2-4xy+y^2)