Determine whether the value is from a discrete or continuous data set. Area of a park is 9.5 acres Is the value from a discrete or continuous data set? Discrete Continuous O

Answers

Answer 1
Answer:

Answer: The value is from discrete data set.

Step-by-step explanation:

Since we have given that

Discrete data set is the data set which can be measured in numbers.

Continuous data set is the data set which can take any value within an interval.

As we have mention that

Area of a park = 9.5 acres

So, it is the exact number so, it can be measured in numbers.

so, it is discrete data set.

Hence, the value is from discrete data set.


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Use the following four coordinates to determine which one has a distance of 5 units from point A (2, 6). (5 points) (5, 2) (2, 5) (6, 7) (7, 5)

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A right triangle with legs measuring 3 units and 4 units has a hypotenuse measuring 5 units.

You need to find a point which has a difference in x and y of 3 and 4 or 4 and 3 from the point A(2, 6).

Look at (5, 2) and compare with A(2, 6).

Difference in x: 5 - 2 = 3

Difference in y: 6 - 2 = 4

Since the differences in x and y are 3 and 4, the hypotenuse will measure 5.

Answer: (5, 2)

Quadrilateral Practice Test, I’ll give brainliest to the correct answer with explanation

Answers

Answer:

120 Degrees

Step-by-step explanation:

Angle T and R are vertical angles meaning they are equal so combine the equations: 31x - 4 = 29x + 4, then solve using inverse operations

subtract 31x from both sides to get -4 = -2x + 4

Then subtract 4 from both sides to get -8 = -2x, now that we have isolated the variable we have to divide by -2 on both sides getting us x = 4, then plug in the four to the equation for angle R getting you 29 times 4 which equals 116 + 4 = 120

Find the number of positive integers not exceeding 108 that are not divisible by 5 or by 7.

Answers

Answer:

75

Step-by-step explanation:

The set of positive integer not exceeding 108 divisible by 5 is

D_5=\{5 \quad 10 \quad 15 \quad 20 \quad 25 \quad 30\quad 35 \quad 40 \quad 45 \quad 50 \quad 55 \quad 60 \quad 65\n \quad 70 \quad 75 \quad 80 \quad 85 \quad 90 \quad 95 \quad100 \quad 105\}

and the set of positive integer not exceeding 108 divisible by 7 is

D_7=\{7 \quad 14 \quad 21 \quad 28 \quad 35 \quad 42 \quad 49 \quad 56 \quad 63 \quad 70 \quad 77 \quad 84 \quad 91 \quad 98 \quad 105\}

Moreover, there are exactly three positive numbers not exceedng 108 that are divisible by both 5 and 7, i.e,

D_5 \cap D_7=\{37 \quad 70 \quad 105\}.

Also note that the size of D_5 is \#D_5=21 , the size of D_7 is \#D_5=15 and \# D_7 \cap D_5 = 3.

On the other hand, If a positive integer not exceding 108 is not divisible by 5 or 7, then it doesn't belong to any of this sets. Therefore, the number of positive interges not exceding 108 that are not divisible by 5 or 7 is equal to

108 -(\#D_7 + \# D_5 - \# D_7 \cap D_5)=108 -(21+15-3)=75

What is the y value of the line when x = -1

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I cannot answer that question because I need to equation

The volume of an object is given as a function of time by V = A + B t + C t4 . Find the dimension of the constant C

Answers

Answer:

The dimensions of constant C are of [L^(3)T]^(-4)

Step-by-step explanation:

It is given that

V(t)=A+Bt+Ct^(3)

Since the dimensions of volume are [L^(3)]

Each of the term shall have a dimension of [L^(3)] since they are in addition.

Thus for third term we can write

Thus we have

[L^(3)]=[C][T^(4)]\n\n\therefore [C]=[L^(3)][T^(-4)]

Considere as mesas com 4 cadeiras, com 6 cadeiras e com 8 cadeiras. ©Shutterstock/jenjira Com base nessa sequência de imagens, qual expressão indica a quantidade de cadeiras utilizadas ao colocarmos n mesas lado a lado?

Answers

Responder:

C. Tₙ = 2n + 2

Explicación paso a paso:

De la pregunta, la secuencia de imágenes, cuya expresión indica es 4 cadeiras, 6 cadeiras, 8 cadeiras ...

Se puede ver la secuencia una progresión aritmética de la forma 4, 6, 8 ... Para obtener la expresión que indica la cantidad de cadenas utilizadas o colocaremos n tablas una al lado de la otra, tendremos que encontrar el enésimo término de la secuencia que usa la fórmula para encontrar el enésimo término de una secuencia aritmética.

El enésimo término de un AP se expresa como Tₙ = a + (n-1) d donde;

a es el primer término

n es el número de términos es la diferencia común

De la secuencia generada, a = 4, d = 6-4 = 8-6 = 2

Tₙ = 4+ (n-1) 2

abre el paréntesis

Tₙ = 4 + 2n-2

Tₙ = 2n + 4-2

Tₙ = 2n + 2

Por lo tanto, la expresión que indica la cantidad de cadenas utilizadas o colocaremos n tablas una al lado de la otra es 2n + 2