MATHEMATICS HIGH SCHOOL

(02.07 MC)A box is 50 cm long. Which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)

1.02 feet
1.17 feet
1.64 feet
4.15 feet

Answers

Answer 1
Answer: The answer is 1.64 feet. 1.64 x 12 = 19.68 inches

19.68 x 2.54 cm= 49.9872 cm

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What is the fewest number of sides a polygon can have?

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if the range of the function f(x)=x/4 is {28,30,32,34,36}, what is its domain?a. {112, 120, 128, 136, 144}b. {118, 122, 124, 132, 145}c. {110, 118, 122, 124, 137}d. {111, 124, 128, 132, 146}

Answers

f(x)=(x)/(4)\to y=(x)/(4)\to x=4y\n\ny\in\{28;\ 30;\ 32;\ 34;\ 36\}\n\n4\cdot28=112\n4\cdot30=120\n4\cdot32=128\n4\cdot34=132\n4\cdot36=144\n\nAnswer:D=\{112;\ 120;\ 128;\ 136;\ 144\}\to\fbox{a.}

Please help asap its due in one minuteLarry’s Landscaping charges $235 for spring cleanups and $30 for weekly lawn maintenance. Joe’s Landscaping charges $185 for spring cleanups and $35 for weekly lawn maintenance. The system that models this situation is given, where c is the cost of lawn maintenance and w is the number of weeks.
c = 235 + 30w
c = 185 + 35w
The solution to the system is (10, 535).
Which interpretation correctly describes the solution to the system of equations?
a. Larry’s Landscaping will charge more money on the tenth week by charging $535.
b. Joe’s Landscaping will charge more money on the tenth week by charging $535.
c. The cost for lawn maintenance is the same, $535, for both landscaping companies after 10 wk.
d. A customer can have his or her lawn maintained for a maximum of 10 wk. The customer will pay a total of $535.

Answers

The first thing you would do is substitute the 10 in for 'w' and 535 in for 'c'. 
535 = 235 + 30(10)
535 = 185 + 35(10)
Then, you would just solve the equations.
535 = 235 + 30(10)
30(10) = 300
300 + 235 = 535 
So the first equation is true, and we know for a fact that Larry's Landscaping charges $535 for a spring cleaning and weekly yard maintenance for 10 weeks.
On to the next equation.
535 = 185 + 35(10)
35(10) = 350
185 + 350 = 535
So, the second equation is true also. And we also know for a fact that Joe's Landscaping charges $535 for a spring cleaning and weekly yard maintenance for 10 weeks. 
So, now that we know that they will end up charging the same amount of money for a spring cleaning and weekly yard maintenance, the only answer that fits that is C. The cost for lawn maintenance is the same, $535, for both landscaping companies after 10 weeks.
Hope this helps!
535 for both in ten weeks sorry if I am lake took a while to think.

Sam and Jeremy have ages that are consecutive odd integers.The product of their ages is 783. Which equation could be used to
find Jeremy’s age, j, if he is the younger man?
(1) j^2 + 2 = 783 (3) j^2 + 2j = 783
(2) j^2 - 2 = 783 (4) j^2 - 2j = 783

Answers

j, j+2 - consecutive odd integers
j - Jeremy's age
j+2 - Sam's age
The product of their ages is 783.

j(j+2)=783 \nj^2+2j=783

The answer is (3).
consecutive odd integers are 2 awya from each other
1,3,5,7,9...
since jeremy iis younger, he is 2 less than sam
j
s=j+2

sj=783
in terms of j
(j+2)j=783
distribute
j^2+2j=783

the answe ris the 3rd equation

Solve for x.
x/9 =14

(A) 126
(B) 130
(C)139
(D)146

Answers

Answer:

(A) 126

Step-by-step explanation:

x/9 =14

Multiply each side by 9

x/9*9 =14*9

x =126

3. The side of a square is 20 cm long. What is the circumference of the circle when … a. The circle is inscribed within the square?
b. The square is inscribed within the circle?

Answers

Answer:

a. 20π cm.

b. 20(√2)π cm,

Step-by-step explanation:

a. The diameter (d) of the circle = side of the square = 20 cm.

So the circumference =  π d = 20π cm.

b. In this case the diameter = the length of the diagonal of the square.

The diagonal = diameter of the circle =sqrt ( 20^2 + 20^2) = √800 = 20√2.

So the circumference = πd = 20(√2)π.

what they said above..
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