What is the molarity of .00000093 grams of epinephrine in one liter?

Answers

Answer 1
Answer:

Answer:

5.076 * 10 ⁻¹² M

Explanation:

molarity of a solution is given as -

Molarity (M)  =  ( w / m ) / V ( in L)

where ,  

m = molecular mass ,

w = given mass ,  

V = volume of solution ,

From the question ,

w = given mass of epinephrine = 0.00000093 g

V = 1 L

Since , the molecular mass of epinephrine = m = 183,204 g/mol

M = ?

In order to determine the molarity of epinephrine , the above formula is used , by putting the respected values ,

Molarity (M)  =  ( w / m ) / V ( in L)  

M = ( 0.00000093 g / 183,204 g/mol ) / 1 L

M = 5.076 * 10 ⁻¹² M


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A reaction will be spontaneous only at low temperatures if both ΔH and ΔS are negative. For a reaction in which ΔH = −320.1 kJ/mol and ΔS = −86.00 J/K · mol. Determine the temperature (in °C) below which the reaction is spontaneous.
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The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this temperature? a. 383 J/(mol·K) b. 0.0115 J/(mol·K) c. 86.9 J/(mol·K) d. 0.087 J/(mol·K) e. 11.5 J/(mol·K)

Answers

Answer: The correct answer is Option c.

Explanation:

Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

The value of standard Gibbs free energy is 0 for equilibrium reactions.

To calculate \Delta S^o_(vap) for the reaction, we use the equation:

\Delta S^o_(vap)=(\Delta H^o_(vap))/(T)

where,

\Delta S^o_(vap) = standard entropy change of vaporization

\Delta H^o_(vap) = standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol    (Conversion factor: 1 kJ = 1000 J)

T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

\Delta S^o_(vap)=(30700J/mol)/(353.3K)=86.9J/(mol.K)

Hence, the correct answer is Option c.

Final answer:

The change in entropy (ΔS°vap) of benzene at its normal boiling point can be calculated using the enthalpy of vaporization (ΔH°vap) and the temperature (T). The ΔS°vap for benzene at 353.3 K is 0.087 J/(mol·K).

Explanation:

The enthalpy of vaporization (ΔH°vap) of a substance is related to the change in entropy (ΔS°vap) by the equation ΔS°vap = ΔH°vap / T, where T is the temperature in Kelvin. We are given that the enthalpy of vaporization of benzene at its normal boiling point (T = 353.3 K) is 30.7 kJ/mol. Plugging these values into the equation, we can calculate ΔS°vap to be 30.7 kJ/mol / 353.3 K = 0.087 J/(mol·K).

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Nf3 Rotate the molecule until you have a feeling for its three-dimensional shape. How many atoms are bonded to the central atom?

Answers

Answer:

Three atoms are attached to the central atom in NF3.

Explanation:

The central atom is always regarded as the atom having the least electronegativity in a molecule or ion. We can decide on what atom should be the central atom by comparing the relative electro negativities of the atoms in the molecule or ion.

If we consider NF3, we can easily see that nitrogen is less electronegative than fluorine, hence nitrogen is the central atom in the molecule. We can also observe from the molecular model that three atoms of fluorine were attached to the central atom. Hence there are three atoms attached to the central atom in the molecule NF3.

Is scandium a transition metal?​

Answers

Answer:no

Explanation:

Answer:

Scandium is a transition metal

Explanation:

Vinegar, the commercial name for acetic acid, HC2Hs02, is a monoprotic organic acid. A 5% (w/v) solution of vinegar is used to titrate a sample of an antacid that contains CaCO3 is the only basic component. If one antacid tablet contains 800 mg of CaCOs in it, then calculate how many milliliters of vinegar should be required to completely neutralize the CaCO3 present in one tablet of antacid?

Answers

19.2 g of vinegar solution

Explanation:

Here we have the chemical reaction between acetic acid (CH₃COOH) and calcium carbonate (CaCO₃):

2 CH₃COOH +  CaCO₃ → (CH₃COO)₂Ca + CO₂ + H₂O

number of moles = mass / molecular weight

number of moles of CaCO₃ = 0.8 / 100 = 0.008 moles

Knowing the chemical reaction, we devise the following reasoning:

if       2 moles of CH₃COOH react with 1 moles of CaCO₃

then X moles of CH₃COOH react with 0.008 moles of CaCO₃

X = (2 × 0.008) / 1 = 0.016 moles of CH₃COOH

mass = number of moles × molecular weight

mass of acetic acid (CH₃COOH) = 0.016 × 60 = 0.96 g

Now to find the volume of vinegar acid (solution of acetic acid) with a concentration of 5% (weight/volume) we use the following reasoning:

if there are         5 g of acetic acid in 100 mL of vinegar solution

then there are   0.96 g of acetic acid in Y mL of vinegar solution

Y = (0.96 × 100) / 5 = 19.2 g of vinegar solution

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weight/volume concentration

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Which indicator will be the same color in hydrochloric acid as it is in pure water?1.methyl orange
2.phenolphthalein
3.bromcresol green

Answers

Phenolphthalein
In acid it is colourless and in water also colourless

HELPPP PLEASEEE....How does a glass of juice become cold when you add ice to it?
aThe ice makes the glass colder so the juice becomes colder.
bThe ice cools the glass of juice because the slow moving particles in the ice cause the particles of the juice to slow down.
cIce is colder than the juice. The cold travel from cold to warm until both items are the same temperature.
dThe juice is warmer than the ice. Heat travels in one direction until both items are the same temperature.

Answers

Answer:

C.

Explanation:

The other ones just don't make sense as answers to the question

Answer:

B

Explanation:

ice molecules move slowly and cluster tightly together, they produce a low amount of heat