Farmingdale is located 8 mi due west of Cambridge. Bayville is located due east of Cambridge, and Louisville is located due north of Cambridge. Louisville is 17 mi from Farmingdale and 24 mi from Bayville.How far is Bayville from Cambridge? Round to the nearest tenth of a mile.

Answers

Answer 1

Answer: Bayville is 18.7 mi from Cambridge.

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Solve the question: 12y = 132. A. Y = 144 B. Y = 1/11 C. Y = 11/12 D. Y = 11
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There are 8 players in a chess tournament. after the tournament each player has to shake hands with e

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There are 8 players in a chess tournament. After the tournament each player has to shake hands with every other player. Which number sentence below is the best way to show the number of handshakes?
Answer :
7+6+5+4+3+2+1= 28

Solve for all values of x by factoring.
x^2+6x+4= -2x+4

Answers

Answer:

0,-8

Answer explanation:

x^2+6x+4=-2x+4

or, x^2+6x+4+2x-4=0

or, x^2+8x=0

Therefore, x(x+8)=0

Either,

x=0

or,

x+8=0

x=-8

hence,x=0, -8

Melanie invested $3,800 in an account paying an interest rate of 2% compoundedquarterly. Sebastian invested $3,800 in an account paying an interest rate of 2%
compounded monthly. After 6 years, how much more money would Sebastian have in
his account than Melanie, to the nearest dollar?

Answers

Answer:

101

Step-by-step explanation:

Answer:101

Step-by-step explanation:

11Select the correct answer.
The elimination method is ideal for solving this system of equations. By which number must you multiply the second equation to eliminate the
yavariable, and what is the solution for this system?
x + 3y - 42
2x-y-14
OA. Multiply the second equation by-3. The solution is x = 12. y - 9.
ов.
Multiply the second equation by-2. The solution is x-12. y = 10.
OC.
Multiply the second equation by 2. The solution is x - 15, y = 9.
OD
Multiply the second equation by 3. The solution is x - 12. = 10.
Reset
Next

Answers

Answer:

D. Multiply the second equation by 3. The solution is x = 12, y = 10

Step-by-step explanation:

Given:

x + 3y = 42 (first equation)

2x - y = 14 (second equation)

To solve by elimination, starting with elimination of the y-variable, multiply the second equation by 3 to get a third equation.

2x - y = 14 (2nd eqn.) × 3

6x - 3y = 42 (3rd equation)

Add the 3rd equation and the 1st equation together.

x + 3y = 42 (first equation)

6x - 3y = 42 (3rd equation)

7x = 84

7x/7 = 84/7

x = 12

To find y, substitute x = 12 in the first equation

x + 3y = 42 (first equation)

12 + 3y = 42

12 + 3y - 12 = 42 - 12

3y = 30

3y/3 = 30/3

y = 10

Solution is x = 12, y = 10

2. The height of a triangle is 5 m less than its base. The area of the triangle is 42 m2. Find the length of the base.(Points : 1)

Answers

Let's start with what we know

Area:
$42 = (1)/(2)bh$ where 42 is the area, b = base, and h = height

Height:
Since we know the height is 5 less than the base, we can write that as an equation.
$h = b - 5$

Now let's go and plug $h = b - 5$ into $42 = (1)/(2)bh$

$42 = (b)/(2)(b-5)$
Let's distribute b over (b-5)

$42 = ( b^(2) - 5b )/(2)$
Let's move 42 over to the right side to make a quadratic formula

$0 = (1)/(2) b^(2) - (5)/(2)b - 42$

Let's plug that into the quadratic equation, which is:

$\frac{-b +/- \sqrt{ b^(2) - 4ac } }{2a}$
And we can now plug the pieces in to calculate b

$\frac{- (-(5)/(2)) +/- \sqrt{ (-(5)/(2))^(2) - 4 ((1)/(2))(-42) } }{2 ((1)/(2)) }$
$\frac{(5)/(2) +/- \sqrt{ (25)/(4) +84 } }{1 }$
${(5)/(2) +/- \sqrt{ (361)/(4) } }$
${(5)/(2) +/- { (19)/(2) }$
Since we can't have a negative value for b (a base can't be negative meters), let's add:

${(5)/(2) + { (19)/(2) }$
${ (24)/(2) }$
$12 = b$

So the base of the triangle is 12m

Answer:

took the quiz and it is correct the answer is 12

The graph of the function f(x) = (x + 2)(x − 4) is shown.Which describes all of the values for which the graph is negative and increasing?

all real values of x where x < −2
all real values of x where −2 < x < 4
all real values of x where 1 < x < 4
all real values of x where x < 0

Answers

The function is negative below the zeros which would be from -2 to 4.
It would be increasing from the vertex to the zero,4.
So the answer would be 1 < x < 4

The values for which the graph is negative and increasing are all real values of x where 1 < x < 4.

Given

The graph of function;

$\rm f(x) = (x + 2)(x - 4)$

What is a graph?

A graph goes from being negative to positive (or the other way around) by passing through the x-axis. in other words when f(x) = 0.

Then,

$\rm f(x) = (x + 2)(x - 4)=0\n\nx+2 =0\ x=-2\n\nx-4=0\ x=4$

For increasing and decreasing for anything other than a quadratic and linear function you need calculus.

The function is negative below the zeros which would be from -2 to 4.

It would be increasing from the vertex to zero,4.

Hence, the values for which the graph is negative and increasing are all real values of x where 1 < x < 4.

To know more about Graph click the link given below.

brainly.com/question/3001106

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