The length of a rectangle is represented by the function L(x) = 5x. The width of that same rectangle is represented by the function W(x) = 2x2 − 4x + 13. Which of the following shows the area of the rectangle in terms of x?(L ⋅ W)(x) = 10x3 − 4x + 13
(L ⋅ W)(x) = 10x3 − 20x2 + 65x
(L + W)(x) = 2x2 + 1x + 13
(L + W)(x) = 2x2 − 9x + 13

Answers

Answer 1
Answer: A= l x w
5x * 2x^2 - 4x + 13
10x^3 - 20x^2 + 65x
Answer 2
Answer:

The function that represents the area of the rectangle is: B. (L × W)(x) = 10x³ - 20x² + 65x.

What is the Area of a Rectangle?

Area of a rectangle = (length × width)

Applying the area of a rectangle formula, the area of the rectangle would be:

(L × W)(x) = 5x(2x² - 4x + 13)

Apply the distributive property

(L × W)(x) = 10x³ - 20x² + 65x

The area in terms of x is: (L × W)(x) = 10x³ - 20x² + 65x.

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Given the following functions f(x) and g(x), solve (f + g)(3) and select the correct answer below:f(x) = 2x + 21

g(x) = x − 24

Answers

Answer:

Let f(x) and g(x) be the function then;

(f+g)(x) = f(x)+g(x)

Given the functions:

f(x) = 2x+21

g(x) = x-24

Solve for : (f+g)(3)

(f+g)(3) = f(3)+g(3)           .....[1]

Put x = 3 in f(x) and g(x) we have;

f(3) = 2(3)+21 = 6+21 = 27

and

g(3) = 3-24 = -21

Substitute these values in [1] we have;

(f+g)(3) =27 +(-21) = 27-21 = 6  

Therefore, the value of (f+g)(3)  is 6


(f+g)(x) = 2x+21 +x-24= 3x -3now put x=3 in order to find (f+g)(3)(f+g)(3) = 3(3) -3= 9-3= 6, i hope this helps 

Find all complex solutions of x^2=i

Answers

Simple...

it's saying x^(2) =i?

To find the answer just take the root of both sides and solve.

\sqrt{ x^(2) } = √(i)

But, remember, there's the positive side of the answer...and the negative side of the answer...

x=√(i) ,- √(i)

Thus, your answer.

True or false the law of cosines can only be applied to acute triangles.

Answers

Answer:

False

Step-by-step explanation:

Law of cosines:

If you know two sides and an included angle, or all the three sides of the triangle, then law of cosines can be applied as:

c^2=a^2+b^2-2abcosC where C is an included angle.

Acute triangle:

A triangle whose all the three angles are less than 90 degrees.

Thus, it is not necessary that the law of cosines will be applied to only acute triangles. Law of cosines can be applied to any triangle as to use it, we only need two sides and an included angle.

Thus, the given statement that is the law of cosines can only be applied to acute triangles is false.

Answer:

False

Step-by-step explanation:

The answer is false

An organization founded by businesses in a specific industry for the purpose of collaboration between companies is called a(n):

Answers

Answer:                                  

The answer is trade association.                

Step-by-step explanation:              

Such organizations are founded to encourage trade and collaboration between companies. These are also known as industry trade group or business association and is funded by businesses that operate in a particular industry.          

trade association... and next time label this is in the correct subject

Michael is 4 times as old as Brandon and is also 27 years older than Brandon. Please answer CORRECTLY !!!! Will mark brainliest !!!!!!

Answers

Answer:

108

Step-by-step explanation:

Mike's current age, be M

Then Brandon's is: M - 27

Also, M = 4(M - 27)

M = 4M - 108

M - 4M = - 108

- 3M = - 108

True or false? The equation (x y)^2 is always equal to x^2 y^2.

Answers

Hello!

Answer:

\Large \boxed{\sf True}

Step-by-step explanation:

→ We want to find if the expression (xy)² is equal to x²y².

→ Let's simplify the expression:

→ We know that \sf (a * b)^n is equal to \sf a^nb^n.

In our expression:

\sf a = x\nb = y\nn = 2

→ So the expression is equal to:

\sf x^2 y^2

Conclusion:

The expression (xy)² is equal to x²y².

So the answer is true.

Answer:

True

Step-by-step explanation:

(xy)²

= xy × xy

= x × x × y × y

= x² × y²

= x²y² ← True