7. Alice holds a black belt in Taekwondo and her fist has a mass of 0.5 kg. Her fist obtains a velocity of 5 m/s in 0.1 seconds from rest. Evaluate the average net force applied to the fist.

Answers

Answer 1
Answer:

Answer: 25 N

Explanation:

the fist hit by the black belt Alice in the Taekwondo has been given to have a mass of 0.5 kg which acquires a velocity of 5 m/s in a time of 0.1 sec, therefore, the average net force which is being applied to the fist can be calculated by the following method,

Given,   mass m=0.5 kg, velocity v=5 m/s, time t=0.1 sec

As we know that, acceleration

a=(v-u)/(t)=(5-0)/(0.1)=50 \mathrm{m} / \mathrm{s}^(2)

Thereby,

\text { Force }=\text { mass } * \text { acceleration }=0.5 * 50=25 N

Answer 2
Answer:

Answer:

25N

Explanation:

Find acceleration first

A=v-u/t

acceleration = 5/0.1s =50m/s^2

then find net force using f=mass x acceleration, which iin this case is 25N


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"Contact" means "touching".  A contact force can't act on an object unless
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What effect would the temperature have on the time kept by a pendulum clock if the pendulum rod increase in length with an increase in temperature

Answers

As we know the time period of pendulum is given by the equation

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L = length of the pendulum

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Thermal expansion increases the pendulum period, and the clock will lose time

Further explanation

Simple Harmonic Motion is the motion of an object (repetitive movement) through its equilibrium point where the frequency of vibrations / oscillation per second is constant

The motion that occurs in the pendulum is one example of simple harmonic motion

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  • Deviation (y): the object's distance from the balance point
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Whereas the relationship T and f:

\displaystyle T=(1)/(f)\n\nf=(n)/(t)

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Formula used:

\large{\boxed{\bold{T=2\pi \sqrt{(L)/(g) }}}\rightarrow (1)/(f)=2\pi \sqrt{(L)/(g) }

From this formula shows that the period is proportional to the length of the pendulum rod.The longer the pendulum rod , the greater the amount of time in one vibration

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Your shopping cart has a mass of 65 kilograms, In order to accelerate the shopping cart down an aisle at 0.3 m/sec2, what force would you need to use or apply to the cart?

Answers

remember Newton's second law: F=ma

to get the force in newtons, mass should be in kg and acceleration in m/s^2

conveniently, we don't need to convert units

we just need to multiply the two to get the force

65* 0.3 = 19.5 kg m/s^2 or N

if significant digit is an issue, the least number if sig figs is 1 so the answer would be 20 N

Final answer:

To accelerate a shopping cart with a mass of 65kg at a rate of 0.3 m/sec2, you would need to exert a force of 19.5 Newtons, according to Newton's second law of motion.

Explanation:

The subject of this problem is physics, specifically the concept of force, mass, and acceleration within the domain of Newton's second law of motion. The law states that the force needed to accelerate an object is equal to the mass of the object multiplied by the desired acceleration.

Given the mass of the cart is 65 kilograms and the acceleration is 0.3 m/sec2, you can calculate the required force using the formula:
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So, Force = 65 kg * 0.3 m/sec2 = 19.5 Newtons. Therefore, you would have to exert a force of 19.5 Newtons to accelerate the shopping cart at the specified rate.

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