Need help solving problem number 41

Answers

Answer 1

Answer: ok rmemeber
√(a/b)=(√a)/(√b)
and
√ab=(√a)(√b)
and
(a^m)/(a^n)=a^(m-n)
so

ignore 11 for now, we will get to that at end

$\sqrt{ (49a^(5))/(4a^(3))}$ =
$\frac{\sqrt{49a^(5))}{\sqrt{4a^(3)}}$ =
$\frac{(√(49))(\sqrt{a^(5)})}{(\sqrt{4)(\sqrt{a^(3)}}$ =
$((7)(a^(2) √(a)) )/((2)(a √(a)) )$ =
$(7a^(2) √(a) )/(2a √(a) )$ =
$(7a)/(2)$

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how much would $120 invested at 6% interest compounded monthly be worth after 21 years? round to the nearest cent
How many integers exist for the value of n such that n²-19n+91 is perfect square?
Y=8 when x=20 find y when x= 30
Thank you, please show me the steps.

the chi-square test compares a. the difference in means for two groups at a time. b. the difference in means for more than two groups. c. the variance of one group with the variance of others. d. the difference between expected and observed frequency counts

Answers

Answer:

Step-by-step explanation:

The correct answer is d. the chi-squaretest compares the difference between expected and observed frequency counts.

The chi-square test is a statistical test used to analyze the distribution of categorical data. It compares the observed frequency counts of a categorical variable with the expected frequency counts.

The expected frequency counts are calculated based on a null hypothesis, which assumes that there is no significant difference between the observed and expected frequencies.

The test statistic for the chi-square test is calculated as the sum of the squared differences between the observed and expected frequency counts, divided by the expected frequency counts.

The resulting value is compared to a chi-square distribution with a certain number of degrees of freedom to determine the p-value and assess the significance of the observed difference.

Therefore, options a, b, and c are incorrect because they describe other types of statistical tests that are used to compare means or variances between groups, while the chi-square test is specifically designed for analyzing categorical data.

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Bodhi has a collection of 175 dimes and nickels. The collection is worth $13.30. Which equation can be used to find n, the number of nickels in the collection?

Answers

Let

n-------> the number of nickels

d-------> the number of dimes

we know that

$1\ nickel=\$0.05$

$1\ dime=\$0.10$

$0.05n+0.10d=13.30$ -----> equation A

$n+d=175$

$d=175-n$ -------> equation B

substitute equation B in equation A

$0.05n+0.10(175-n)=13.30$ ------> equation that can be used to find n

Solve for n

$0.05n+17.5-0.10n=13.30$

$17.5-13.30=0.10n-0.05n$

$0.05n=4.2$

$n=84\ nickel$

find the value of d

$d=175-n$

$d=175-84=91\ dimes$

therefore

the answer is

The equation that can be used to find n is $0.05n+0.10(175-n)=13.30$

The number of nickels in the collection is $84\ nickel$

n + d = 175 .... d = 175 - n
0.05n + 0.10d = 13.30

0.05n + 0.10(175 - n) = 13.30 <== and u would just solve for n

Use decomposition to find the area of the figure 3cm,5m,7cm, the area is _____.

Answers

To find the area of the figure with dimensions 3 cm, 5 m, and 7 cm, you can decompose it into two rectangles and then calculate their areas separately.

1. First, consider the rectangle with dimensions 3 cm (length) and 7 cm (width):
Area of the first rectangle = Length × Width = 3 cm × 7 cm = 21 square cm.

2. Now, consider the second rectangle with dimensions 5 m (length) and 7 cm (width). To make the units consistent, convert 5 meters to centimeters (1 meter = 100 cm):
5 m = 5 × 100 cm = 500 cm
Area of the second rectangle = Length × Width = 500 cm × 7 cm = 3500 square cm.

3. Finally, add the areas of both rectangles together:
Total Area = Area of first rectangle + Area of second rectangle = 21 square cm + 3500 square cm = 3521 square cm.

So, the area of the figure is 3521 square cm.

Express each number in standard form
-9.5x10-3
This is 10 to the -3 power

Answers

$-9.5*10^(-3)=-9.5*0.001=-0.0095$

The perimeter of a face of a cube is 16 mm. What is its volume?1.64 mm3
2.128 mm3
3.512 mm3
4.4096 mm3

Answers

16 is divided by 4 because square has 4 sides
16:4= 4mm
then you search the volume
4 x 4 x 4= 64mm3

Consider the function y = 1.065(4), which represents thegrowth of capital in a bank account.

The annual interest is

___%, and the bank compounds the interest_____

The balance of the account will

grow____

Answers

The annual interest rate is 6.5%, and the bank compounds the interest annually. The balance of the account will grow exponentially over time.

The given function y = 1.065(4) represents the growth of capital in a bank account, where the initial balance is 4 and the growth rate is 6.5% per year. To calculate the annual interest rate, we can use the formula A = P(1 + r/n)^(nt), where A is the final amount, P is the initial principal, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the time in years.

In this case, the final amount after one year is 4 * 1.065 = 4.26. Substituting the values in the formula, we get 4.26 = 4(1 + r/1)^(1), which simplifies to 1 + r = 1.065. Solving for r, we get r = 0.065 or 6.5%.

The bank compounds the interest annually, which means that the interest is added to the account balance at the end of each year. As the balance grows, the interest earned in the subsequent years will be higher. This results in exponential growth of the account balance over time. After n years, the account balance will be B = P(1 + r)^n, where P is the initial balance, r is the annual interest rate, and n is the number of years.

For example, after 5 years, the account balance will be B = 4(1 + 0.065)^5 = 5.39. After 10 years, the account balance will be B = 4(1 + 0.065)^10 = 7.27. As we can see, the account balance grows significantly over time due to the effect of compounding interest.

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