Is 25/40 proportional to 15/24

Answers

Answer 1

Answer: Cross Multiply. 25 * 24 and 40 * 15
Yes, they are proportional

Answer 2

Answer: YES THEY ARE YOU JUST CROSS MULTIPLY THEM DIAGNAL AND THEN MAYBE DIVIDED IT BOTH THEN THERE ARE PROPORTIONAL.

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Hannah just bought a new camera. In January she took 14 pictures. The number of pictures she took doubled each month for three months. A. how many pictures did hannah take in march? Write and solve an expression with an exponent to show how many pictures she took.

B. In April, Hanna took 1/2 the number of pictures she took in March. Her brother Jack thinks she took the same number of pictures in April that she did in February. Hannah knew he was incorrect. Write and solve an expression to show why Hannah is right.

Answers

January = 14 pictures

Number of pictures she took doubled each month for three months.
February : 14 x 2 =   28
March : 28 x 2 =   56
April   : 56 x 2 = 112

A) March: 14 x 2² = 14 x 4 = 56 pictures

B) April : 56 pictures * 1/2 = 28 pictures

I think the same way Jack does.

Answer:

42 pictures

Step-by-step explanation:

What fraction is equivalent to 7.25?

Answers

The fraction equivalent to 7.25 is 7 and 25/100

The decimal .25 could be written as $(1)/(4)$ . So a fraction equivalent to 7.25 would be 7 $(1)/(4)$ .

If you want a mixed fraction, multiply 7 with the denominator and add it to the numerator. Then divide the new value by the denominator.
So 7 $*$ 4 = 28.
28 + 1 = 25.
$(25)/(4)$ .

The answer is $(25)/(4)$ .

Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3 A.x=-1,x=3
B.x=-1,x=-3,y=0
C.x=1,x=-3,y=0
D.x=-1,x=-3

Answers

Answer:

B. x = -1, x = -3, y = 0

Step-by-step explanation:

$g(x)=(x-2)/(x^2+4x+3)\n\nvertical\ asymptote:\n\nx^2+4x+3=0\nx^2+x+3x+3=0\nx(x+1)+3(x+1)=0\n(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\n\n\boxed{x=-1\ \vee\ x=-3}\n\nhorizontal\ asymptote:\n\n\lim\limits_(x\to\pm\infty)(x-2)/(x^2+4x+3)=\lim\limits_(x\to\pm\infty)(x^2\left((1)/(x)-(2)/(x^2)\right))/(x^2\left(1+(4)/(x)+(3)/(x^2)\right))=\lim\limits_(x\to\pm\infty)((1)/(x)-(2)/(x^2))/(1+(4)/(x)+(3)/(x^2))=(0)/(1)=0\n\n\boxed{y=0}$

BRAINLIEST IF CORRECT PLEASE USE WORK!What is the x-intercept of the line with this equation 1/3x+y=−15 ?

Enter your answer in the box.

Answers

y-ordinate of x-intercept is 0 .Putting y = 0 in the equation we get 1 3 x + 0 = − 15 or 1 3 x = − 15 or x = − ( 3 ⋅ 15 ) = − 45 ∴ x=intercept is ( − 45 , 0 ) graph{-1/3x-15 [-80, 80, -40, 40]}[Ans]

Hope this helped.

Your answer:

x-intercept is ( -45 , 0 )

Answer:

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (−45,0)

y-intercept: (0,−15)

What is 19-23 and why