If a force of 65 N is exerted on a 45 kg sofa and the sofa is moved 6.0 meters, how much work is done in moving the sofa? 17,550 J 171.990 J 390 J none of the above

Answers

Answer 1
Answer:

Answer:

The answer to your question is:   W = 390 J

Explanation:

Work is the transfer of energy when a body is moved from one place to another.

Data

Force = 65 N

mass = 45 kg

distance = 6 meters

work = ? J

Formula

W = F x d

Process

                   W = 65 N x 6 m

                   W = 390 J

Answer 2
Answer:

Answer: 390 J

Explanation:

i got it right on my exam :D


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The horsepower (hp) that a shaft can safely transmit varies jointly with its speed, in revolutions per minute (rpm), and the cube of the diameter. If the shaft of a certain material 3 inches in diameter can transmit 46 hp at 100 rpm, what must the diameter be in order to transmit 74 hp at 175 rpm?

Answers

Answer:

diameter ≅  3 inches

Explanation:

HP=k*s*d^(3)

Use a constant factor, k

Let Hp = horsepower

Let s = speed in rpm

Let d = diameter in inches

to find constant k, using

Hp=46

S=100

d=3 in

46=k*100*3^(3) \n\n46=k*100*27\n46=2700k\nk=(46)/(2700) \nk=0.017\n\n

 

To find diameter when;

Hp=74

S=175

k=0.017

d=d inches

74=0.017*175*d^(3) \n\n74=2.975*d^3\nd^3=(74)/(2.975) \nd=\sqrt[3]{24.87}   \nd=2.9 inches\n\n  d≅ 3 inches

An object has a mass of 48g and a volume of 6cm cubed (like a little 3 above the m) Calculate the density of this object

Answers


       Density  =  (mass) / (volume)

                    =  (48 g)  /  (6 cm³)
 
                    =  (48 / 6)  (g / cm³)

                    =          8 g/cm³ 
                    
i hope this helps The density (d) of a material is its mass (m) divided by its volume (V). ... Calculatethe density of an object that has a mass of 25.0g and the volume is 10.5ml. ... 3.Calculate the mass for the following object. If you know that the object 

When air is blown across the top of an openwater bottle, air molecules in the bottle vibrate
at a particular frequency and sound is produced.
This phenomenon is called
(1) diffraction (3) resonance
(2) refraction (4) the Doppler effect

Answers

When air is blown across the top of an open water bottle, air molecules in the bottle vibrate at a particular frequency and sound is produced in a process called "refraction". 

Answer:

resonance

Explanation:

Resonance is when the frequency matches another objects natural frequency causing it to vibrate.

Matter behaving like a wave rather than like a particle is best illustrated by which phenomenon?

Answers

The photoelectric effect is about electrons being ejected from metals when light is shined on metals. The electrons do not behave like waves in the photoelectric effect. Black body radiation is all about the radiation emitted by warm bodies and not about those bodies behaving like waves. The emission spectra of atoms is all about what light is given off by atoms when electrons in those atoms jump down to lower energy levels from higher levels. That also has nothing to do with matter behaving as a wave. Interference is classically defined as the generation of a new wave with an amplitude modulated according to the waves that interfere to form that new wave. Note its emphasis on the wave part.

Explain the relationship between motion and frame of reference.

Answers

force is the agent which causes a change in the velocity of an object and thereby to acellerate it inertia on he other hand is a property which realtes to an intrinsic of a body  to resist any change in its state rest or of emotion uniform or non uniform 

Magnesium is a metal that is commonly used in products that needed to be light weight. Suppose a 2.00kg piece of magnesium has 8160 j of entertainment added to it it's temperature increases 4K what is the specific heat of magnesium

Answers

Given that,

Mass of magnesium, m = 2 kg

Heat added to it, Q = 8160 J

Increase in temperature, \Delta T=4\ K

To find,

The specific heat of magnesium.

Solution,

Th formula that is used to find the heat required to raise the temperature in terms of specific heat is given by :

Q=mc\Delta T\n\nc=(Q)/(m\Delta T)\n\nc=(8160\ J)/(2\ kg* 2\ K)\n\nc=2040\ J/kg-K

So, the specific heat of magnesium is 2040\ J/kg-K.