Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger's infamous Nordvand, mountaineer Carlos Ragone's rock anchor gave way and he plummeted 516 feet to land in snow. Amazingly, he suffered only a few bruises and a wrenched shoulder. Assuming that his impact left a hole in the snow 3.6 ft deep, estimate the magnitude of his average acceleration as he slowed to a stop (that is while he was impacting the snow).

Answers

Answer 1
Answer:

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.174 ft/s²

Equation of motion

v^2-u^2=2as\n\Rightarrow v=√(2as+u^2)\n\Rightarrow v=√(2* 32.174* 516+0^2)\n\Rightarrow v=182.218\ ft/s

v^2-u^2=2as\n\Rightarrow a=(v^2-u^2)/(2s)\n\Rightarrow a=(0^2-182.218^2)/(2* 3.6)\n\Rightarrow a=-4611.58\ ft/s^2

Magnitude of acceleration while stopping is 4611.58 ft/s²


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Which of these 23rd chromosomecombinations is likeliest to result in a
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Answers

Sorry if I’m wrong but I think it’s XO since o is not a sex chromosome

A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y-direction. You want to balance the magnetic force with an electric force so that the proton will continue along a straight line. The electric field should be in the ______ direction.

Answers

Answer:

Negative z-direction.

Explanation:

We need to determine the direction of the magnetic force. Since the velocity of the proton is in the positive x direction, and the magnetic field is in the positive y direction, we know by the vectorial formulaF=q(v* B) (or, alternatively, with the left hand rule) that the magnetic force points in the positive z-direction (also taking into account that the charge is positive), so the electric field should be in the negative z-direction to balance it.

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade?

Answers

Incomplete question.The complete question is here

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.

Answer:

F= 0.034 N

Explanation:

Given Data

Outer=2 cm

Edge of blade=21 cm

Mass=7.7 g

Length of blade=21 cm

The last 2cm is treated as if they were at a point 20cm from the center of rotation

To Find

Force=?

Solution

Convert the given frequency to angular frequency

ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)

ω= 3/2*π rad/sec

Now to find centripetal force.

F = m×v²/r

F= m×ω²×r

Put the data

F = 0.0077 kg × (3/2×π rad/sec)²× 0.20 m

F= 0.034 N

The 2-Mg truck is traveling at 15 m/s when the brakes on all its wheels are applied, causing it to skid for 10 m before coming to rest. The total mass of the boat and trailer is 1 Mg. Determine the constant horizontal force developed in the coupling C, and the friction force developed between the tires of the truck and the road during this time.

Answers

Answer:

constant horizontal force developed in the coupling C = 11.25KN

the friction force developed between the tires of the truck and the road during this time is 33.75KN

Explanation:

See attached file

Final answer:

The total force resisting the motion of the car, boat, and trailer is 990 N. The friction force developed between the tires of the truck and the road can be calculated using the equation Ffriction = μN.

Explanation:

To determine the constant horizontal force developed in the coupling C, we need to calculate the total force resisting the motion of the car, boat, and trailer. We can use Newton's second law, which states that force equals mass times acceleration (F = ma). The mass of the car, boat, and trailer combined is 1800 kg (1100 kg + 700 kg). The acceleration is 0.550 m/s². Therefore, the total force resisting the motion is 990 N (1800 kg * 0.550 m/s²).

To determine the friction force developed between the tires of the truck and the road during this time, we need to consider the force of friction. The force of friction can be calculated using the equation Ffriction = μN, where μ is the coefficient of friction and N is the normal force. In this case, the normal force is equal to the weight of the truck, which can be calculated as the mass of the truck times the acceleration due to gravity (9.8 m/s²). Assuming the coefficient of friction is 0.62 (as given in the example), the friction force can be calculated as Ffriction = 0.62 * (1800 kg * 9.8 m/s²).

Determine whether the following statements are true and give an explanation or counterexample.(A) If the acceleration of an object remains constant, its velocity is constant.
(B) If the acceleration of object moving along a line is always 0, then its velocity is constant.
(C) It is impossible for the instantaneous velocity at all times a(D) A moving object can have negative acceleration and increasing speed.

Answers

Answer:

Explanation:(A)if a body is accelerating then it's velocity can't be constant since an object is said to be accelerating if it is changing velocity (B)if the acceleration of an object moving along a line is 0 then it's velocity will be constant since there is no change in direction or speed(C)No.it is not possible for a moving body to have an instantaneous velocity at all times since instantaneous velocity is the velocity of a body at a certain instant of time..(D)Yes a moving object can have a negative acceleration and increasing speed,it can also have a positive acceleration with decreasing speed.

3.what does this stand for ??

Answers

Answer:

see below

Explanation:

The triangle stands for the change in

We would change the change in x

Answer:

ΔThis is the symbol of Delta which means Change

and x is length/distance/position.

Thus,Δxstands for Change in length/distance/position.

-TheUnknownScientist