How to increase numbers

Answers

Answer 1

Answer: Hi There! :)

How to increase numbers?

Multiply by a percentage

Answer 2

Answer: Add or multiply another number with that number

Related Questions

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One yardstick for measuring how steadily—if slowly—athletic performance has improved is the mile run. In 1958, the local record for the running of a certain distance was 3 minutes, 59.3 seconds, or 239.3 seconds. In the half-century since then, the record has decreased by 0.5 seconds per year.
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What is the standard form of two and twelve hundredths

Answers

2.12 that's the answer

A) Calculate the magnitude of the angle a in the diagram above. b) Find the length of OT

Answers

Answer:

angle a = 53.13 degrees and OT = 5cm

Step-by-step explanation:

Tan A = 4/3

A = 53.13

Solve. Q - 7 5/6 = 6 1/2

Answers

$Q - 7 (5)/(6) = 6 (1)/(2) \n \n Q - 7 (5)/(6) + 7 (5)/(6) = 6 (1)/(2) + 7 (5)/(6) \n \n Q = 6 (1*3)/(2*3) + 7 (5)/(6) \n \n Q = 6 + 7 + (3)/(6) + (5)/(6) \n \n Q = 13 + (8)/(6) = 13 + (6)/(6 ) + (2)/(6) = 14 (2)/(6 ) = 14 (1)/(3)$

Two equations are given below:a – 3b = 4
a = b – 2

What is the solution to the set of equations in the form (a, b)? (5 points)

(–2, –2)
(–3, –1)
(–9, –7)
(–5, –3)

Answers

a - 3b = 4
a = b -2

(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b = 4 + 2
-2b = 6
b = 6/-2
b = -3

a = b - 2
a = -3 -2
a = -5

to check: a = -5 ; b = -3 ⇒ (-5,-3)
a - 3b = 4
-5 - 3(-3) = 4
-5 + 9 = 4
4 = 4

A system in a noisy environment transmits 11111 or 00000 when 1 or 0 are transmitted to decrease the probability of error. Suppose the probability that one of the 5 transmitted bits is corrupted from 1 to 0 is 0.3 and the probability that a bit is corrupted from 0 to 1 is 0.1. Given that the probability that the system transmits a 0 or a 1 is equally likely, if 01101 was received what is the probability that a 1 was transmitted.

Answers

Answer: The probability that a 1 was transmitted is (0.3)²(0.7)³ which = 0.031

Step-by-step explanation:

The attachment below simply explains how to solve it using Bayer's rule

If cos Θ = negative two over five and tan Θ > 0, what is the value of sin Θ? negative square root / 21 negative square root / 21 over 5 square root / 21 over 5 square root of 21 over 2

Answers

Answer: The correct option is (B) negative square root 21 over 5.

Step-by-step explanation: Given that for an angle $\theta$ ,

$\cos \theta=-(2)/(5),~~~\tan \theta>0.$

We are to find the value of $\sin \theta.$

We know that

Cosine is negative in Quadrant II and Quadrant III.

Tangent is positive in Quadrant 1 and Quadrant III.

So, the given angle $\theta$ lies in the Quadrant III.

We will be using the following trigonometric identity:

$\cos^2\theta+\sin^2\theta=1.$

We have

$\cos \theta=-(2)/(5)\n\n\n\Rightarrow √(1-\sin^2\theta)=-(2)/(5)\n\n\n\Rightarrow 1-\sin^2\theta=(4)/(25)\n\n\n\Rightarrow \sin^2\theta=1-(4)/(25)\n\n\n\Rightarrow \sin^2\theta=(21)/(25)\n\n\n\Rightarrow \sin \theta=\pm(√(21))/(5).$