Which is bigger 45% or 5/11

Answers

Answer 1

Answer: 5/11 > 4/100

quick note :

45% as a fraction can be :

45/100 or 9/20

40/100 or 4/10 or 2/5

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Sinhx = 8/15 what are the other hyperbolic functions?

Answers

cosh^2x - sinh^2x = 1

coshx = sqrt( 1 + sinh^2x)

= sqrt(1 + (8/15)^2) = 17/15

for tanh

just divide

sinhx/coshx = tanhx = 8/17

for sech , cosech, coth << just flip the original as normal trigonometric functions

A garden is in the shape of a rectangle and has a perimeter of 58 yards. The length of the garden is 5 more than twice the width. Find the dimensions of the garden.

Answers

Let the width be w
Length= 2w+5
Perimeter= 2(length+width)
58=2(2w+w+5)
58=2(3w+5)
3w+5=29
3w=24
Width=8yards
Length=2(8)+5
=21yards

p= sum of the sides = 2l+2wopposite sides are the samex=width2x+5= length2x+ 2(2x+5)=58remove( )2x+ 4x+10=58combine like terms6x+10= 58subtract 10 from both sides6x=48divide by 6x=8 width2 x 8+5= 21 lengthhope this helps

Find the inverse of each function1) g (x)= 3+(x-1)^3
4) f (x)=x^3+2
5) f (n)= 5 square root of (-n+1/2)

Answers

to find the inverse
1. replace f(x) or g(x) or f(n) with y
2. switch places of x and y
3. solve for y
4. replace y with f⁻¹(x) or g⁻¹(x) or f⁻¹(n)

1.
g(x)=3+(x-1)^3
replace
y=3+(x-1)^3
switch
x=3+(y-1)^3
solve
x=3+(y-1)^3
subtract 3
x-3=(y-1)^3
cube root both sides
$\sqrt[3]{x-3}$ =y-1
add 1
$\sqrt[3]{x-3}$ +1=y
switch y with g⁻¹(x)
g⁻¹(x)= $\sqrt[3]{x-3}$ +1

4. f(x)=x^3+2
replace with y
y=x^3+2
switch x and y
x=y^3+2
solve for y
x=y^3+2
subtract 2
x-2=y^3
cube roo both sides
$\sqrt[3]{x-2}$ =y
replace with f⁻¹(x)
f⁻¹(x)= $\sqrt[3]{x-2}$

5.
f(n)=5 $√(-n+1/2)$
replace
y=5 $√(-n+1/2)$
switch n and y
n=5 $√(-y+1/2)$
solve for y
n=5 $√(-y+1/2)$
divide both sides by 5
n/5=n= $√(-y+1/2)$
square both sides
$(n^2)/(25)$ =-y+1/2
subtract 1/2 from both sides
$(n^2)/(25)$ - $(1)/(2)$ =-y
multiply both sides by -1
- $(n^2)/(25)$ + $(1)/(2)$ =y
replace with f⁻¹(n)
f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

1. g⁻¹(x)= $\sqrt[3]{x-3}$ +1
4. f⁻¹(x)= $\sqrt[3]{x-2}$
5. f⁻¹(n)=- $(n^2)/(25)$ + $(1)/(2)$

Anna had a solid wooden dowel with a length of 12 inches and a diameter of 1 inch, as shown below. She cut a two-inch portion out of the dowel as indicated. What was the volume, to the nearest tenth of a cubic inch, of the portion of the dowel that Anna cut out?

Answers

Answer:

Volume of the portion = 1.6 cubic inches

Step-by-step explanation:

Since, wooden dowel is in the shape of a cylinder,

Formula to be used to find the volume of the part Anna has cut from the dowel will be,

Volume = πr²h

Where r = radius of the cylinder or part of the wooden dowel

h = length of the portion

By substituting the values in the formula,

Volume = π(0.5)²(2)

= 0.5π

= 1.57 in³ ≈ 1.6 cubic inch

Therefore, volume of the portion will be 1.6 in³.

What are two numbers that multiply to -20 and add up to 1?

Answers

  xy = -20
x + y = 1

x + y = 1
x - x + y = -x + 1
y = -x + 1

xy = -20
x(-x + 1) = -20
  x(-x) + x(1) = -20
-x² + x = 20
-x² + x + 20 = 0
-1(x²) - 1(-x) - 1(-20) = 0
  -1(x² - x - 20) = 0
-1 -1
x² - x - 20 = 0
x = -(-1) ± √((-1)² - 4(1)(-20))
2(1)
x = 1 ± √(1 + 80)
2
x = 1 ± √(81)
2
x = 1 ± 9
2
x = 0.5 ± 4.5
x = 0.5 + 4.5 or x = 0.5 - 4.5
x = 5      or      x = -4

  x + y = 1
  5 + y = 1
- 5 - 5
y = -4
(x, y) = (5, -4)
or
x + y = 1
  -4 + y = 1
+ 4   + 4
y = 5
(x, y) = (-4, 5)

The two numbers that add up to 1 and multiply to -20 are -4 and 5.

Find the perimeter of thepolygon if ZB = ZD.
11.5 cm
B
D
12.5 cm
13.5 cm