Solve for c ab+c=5
c=5/ab
c=5-ab
c=5+ab

Answers

Answer 1
Answer: The answer is the second choice. c=5-ab
Answer 2
Answer:

Answer:

c=5-ab is the correct one.

Step-by-step explanation:


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Starting time is 2:46 pm elapsed time is 15 minutes what is the ending time
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If t+8=-12 what's the value of t + 1
Six times the sum of a number and eight is 30. Find the number

Find the are of a triangle (picture provided)

Answers

Answer:

B

Step-by-step explanation:

Use the Heron's formula for the area of the triangle:

A=√(p(p-a)(p-b)(p-c)),

where a, b, c are lengths of triangle's sides and p=(a+b+c)/(2).

Since a=11.5,\ b=13.7,\ c=12.2, then

p=(11.5+13.7+12.2)/(2)=18.7.

Hence,

A=√(18.7(18.7-11.5)(18.7-13.7)(18.7-12.2))=√(18.7\cdot 7.2\cdot 5\cdot 6.5)=\n \n=√(11\cdot 1.7\cdot 9\cdot 4\cdot 0.2\cdot 5\cdot 5\cdot 1.3)=30√(11\cdot 1.7\cdot 0.2\cdot 1.3)=30√(4.862)\approx 66.1\ un^2.

Answer:

Choice b is correct.

Step-by-step explanation:

We have given the sides of triangle.

a = 11.5, b = 13.7 and c  = 12.2

We have to find the area of the triangle.

The formula to find the area of the triangle when three sides are given is:

A = √p(p-a)(p-b)(p-c)

where p = (a+b+c) / 2

p = (11.5+13.5+12.2)/2

p = 18.7

A = √18.7(18.7-11.5)(18.7-13,7)(18.5-12.2)

A = 30√4.862 units²

A≈ 66.1 units²

What is the factored form of the polynomial? x2 - 15x + 36

Answers

Answer:

(x-12)(x-3)

Step-by-step explanation:

We have been given an polynomial x^2-15x+36 and we are asked to factor our given polynomial.

We will factor our given polynomial by splitting the middle term in two numbers such that the numbers add up-to -15 and their product will be equal to 36.

We know that -12 and -3 add up-to -15 and their product is 36. So splitting the middle term of our given polynomial we will get,

x^2-12x-3x+36

x(x-12)-3(x-12)

(x-12)(x-3)

Therefore, the factored form of our given polynomial is (x-12)(x-3).

The factored form of the polynomialx^2 - 15x + 36 is (x - 3)(x - 12).

To find the factored form of the polynomial x^2 - 15x + 36, we can look for two binomials that, when multiplied, give us the original polynomial.

The general form of a quadratic polynomial in factored form is (x - r_1)(x - r_2).

where r_1 and r_2 are the roots of the polynomial.

Now, find two numbers whose product is 36 and whose sum is -15.

The numbers that satisfy these conditions are -3 and -12,

since (-3) * (-12) = 36 and

(-3) + (-12) = -15.

Therefore, we can factor the polynomial as:

x^2 - 15x + 36

x^2 - 12x-3x+36

x(x-12)-3(x-12)

= (x - 3)(x - 12)

So, the factored form of the polynomialx^2 - 15x + 36 is (x - 3)(x - 12).

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Isolate c
a=b(1/c-1/d)

Answers

A= b(1/c - 1/d)
A/b = 1/c -1/d
A/b + 1/d = 1/c
(A/b + 1/d) 1 = c

Answer: c = b/(a + 1).

Step-by-step explanation:

a = b(1/c - 1/d)

Expand RHS by first finding LCM

a = b((d — c)/cd)

a = (bd — bc)/cd

Then cross multiply

acd = bd — cd

Collect the terms having c to the LHS

acd + cd = bd

Factorise cd out of LHS

( a+ 1)dc = bd

c = bd/(a + 1)d

c = b/(a + 1).

What is the value of |–46| ?A.
–46







B.
46

Answers

the answer is B that symbol means absolute value and it manes the distance from zero.
The answer is B. The answer is always the positive version of the number.

If eric practiced the piano 8hrs a week, if he practices 1/4 of that how many hours is that?

Answers

divide 8 by 4 and you get 2 hours
Work:

It is fourths, so divide
8 ÷ 4
That gives you 2

Answer:

2 hours

Himpunan penyelesaian dari pertidaksamaan | 2x + 1| ≤ 3 adalah.....a. { -1 ≤ x ≤3 }
b. { -2 ≤ x ≤ 2}
c. { -2 ≤ x ≤ 1 }
d. { -1 ≤ x ≤ 1 }
e. { 0 ≤ x ≤ 1 }
Tolong caranya...

Answers

| 2x + 1| \leq3 \n2x+1\leq3\wedge2x+1\geq-3\n2x\leq2 \wedge 2x\geq-4\nx\leq1 \wedge x\geq-2\n-2\leq x \leq1 \Rightarrow C

Final answer:

The solution to the given inequality, |2x + 1| ≤ 3, is the set { -2 ≤ x ≤ 1 }, which corresponds to answer choice (c). This is achieved by solving two separate inequalities, 2x + 1 ≤ 3 and - (2x + 1) ≤ 3.

Explanation:

The subject of the question is Mathematics, specifically a High School algebra topic on solving absolute inequalities. The student's question is asking us to solve the inequality |2x + 1| ≤ 3. To do this, we need to create and solve two separate inequalities: 2x + 1 ≤ 3 and - (2x + 1) ≤ 3.

Solving 2x + 1 ≤ 3 gives us 2x ≤ 2 and x ≤ 1 . Solving - (2x + 1) ≤ 3 gives us -2x - 1 ≤ 3 , then -2x ≤ 4 , and finally x ≥ -2 . Combining these answers gives us the solution set { -2 ≤ x ≤ 1 }, which corresponds to answer choice (c).

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