How does an antenna’s receiving circuit select electromagnetic radio waves of a certain frequency and reject all others?

Answers

Answer 1

Answer:

An antenna’s receiving circuit select electromagnetic radio waves of a certain frequency and reject all others. This is because an antenna IS an electromagnetic radiator that creates an electromagnetic field that scatters from the transmitting antenna to the receiver’s antenna.

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Power is transmitted great distances at ______ voltage and ______ current. a low, medium b high, medium c high, low d low, high

Answers

The correct answer to the question stated above is letter c, high, low.

Power is transmitted great distances at high voltage and low current.

>The reason why electrical energy transmitted at high voltage and low current is : so that huge amount of power can be delivered at long distances by using only small size of wires.

As current flows through a series circuit, it is diminished by the work it performs in the resistance(s). TRUE or FALSE

Answers

As current flows through a series circuit, it is diminished by the work it performs in the resistance(s). TRUE or FALSE

The statement “As current flows through a series circuit, it is diminished by the work it performs in the resistance(s)” is true.

How does the amount, or magnitude, of charge on an object affect its attraction or repulsion of another object?

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The greater the magnitude of the charge on an object, the greater the force of attraction or repulsion exerted by that object on another.

The force between two charges is 1000 N. One has a charge of 2 × 10-5 C, and the other has a charge of 5 × 10-6 C. What is the distance between them?

Answers

Use the Coulomb Law:

$F=k.(q_1.q_2)/(d^2)\n \n 1000=9.10^9.(2.10^(-5).5.10^(-6))/(d^2)\n \n 1000d^2=9.10^9.2.10^(-5).5.10^(-6)\n \n d^2=(9.10^9.2.10^(-5).5.10^(-6))/(10^3)\n \n d^2=(9)/(10^4)\n \n d=\sqrt{(9)/(10^4)}=(3)/(100)=0,03 \ m$

Final answer:

The distance between the charges is calculated using Coulomb's Law and found to be 0.134m or 13.4 cm.

Explanation:

This problem can be solved using Coulomb's Law. The formula for Coulomb's Law is: F = k*(|q1*q2|)/r², where F is the force between the charges, q1 and q2 are the amounts of charge, r is the distance between the charges, and k is Coulomb's constant (approximately 9.00 x 10^9 N*(m²/C²)).

Giving the values, we have, 1000 N = 9.00 x 10^9 N*(m²/C²)*((2 x 10^-5 C) * (5 x 10^-6 C))/r².

Solving for r (the distance between the charges) in this equation, we first divide both sides of the equation by the values on the right, excluding r, which gives us: r² = ((2 x 10^-5 C) * (5 x 10^-6 C) * 9.00 x 10^9 N*(m²/C²))/1000N.

Calculating the values in this equation and then taking the square root of the result gives r = 0.134 m or 13.4 cm which is the distance between the two charges.

Learn more about Coulomb's Law here:

brainly.com/question/506926

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1 poinWhat exercise could you do that works on cardiovascular endurance and
muscular strength?*
Bicep Curls
Dips
Stairs
Squats
O Other:

Answers

stairs!

stairs are a great cardiovascular endurance exercise, and also help muscular strength in the legs and core.

hope this helps!

Speed / 16.0 m/s 12.0- 8.0 4.0 0 0 0.5 1.0 1.5 time / seconds 2.0 2.5 3.0 calculate the distance that the car travels in the first 0.5 seconds calculate the distance that the car travels in the first 0.5 seconds

Answers

Answer: 8 m

Explanation:

From the equation distance = velocity * time, we can find the distance from a velocity vs. time graph by finding the area under the curve, since we get that area from multiplying velocity and time together.

For the first 0.5 seconds, the velocity is 16 m/s and the change in time is 0.5.

16 * 0.5 = 8 m.

Learn more about the relationship between distance and velocity here: brainly.com/question/29409777

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