How many moles of solute are present in 50.0mL of 0.20m KNO3?

Answers

Answer 1

Answer:

The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.

Molarity can be defined as the moles of solute in a litre of solution. The solution of potassium nitrate has been prepared to be of Molarity 0.2 M. The moles of solute present in the solution can be calculated as:

Molarity = moles $*$ volume (L)

The given volume = 50 ml

1000 ml = 1 L

50 ml = 0.05 L

Molarity of the solution = 0.2 M

The moles of solute:

0.2 = moles $*$ 0.05

Moles of Potassium nitrate = 4

The moles of potassium nitrate present in the 50 ml of 0.2M solution has been 4 moles.

For more information about the moles of solute, refer to the link:

brainly.com/question/1414530

Answer 2

Answer: Volume = 50.0 mL in liters : 50.0 / 1000 = 0.05 L

n = M x V

n = 0.20 x 0.05

n = 0.01 moles of solute

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Answers

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Answers

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Answers

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