Astrophysics and planetar Astrophysics and planetary science are considered subspecialties of y science are considered subspecialties of

Answers

Answer 1

Answer:

Astrophysics and planetar Astrophysics and planetary science are considered subspecialties of Astronomy. Astronomy is the study of the sun, moon, planets, stars, comets, gas, galaxies, dust and other bodies and phenomena.

Note

Astrophysics - properties of space

Planetary Science - planet formation

I hope this helps, Regards.

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The complete combustion of ethanol, C₂H₅OH (FW = 46.0 g/mol), proceeds as follows: $C_2H_5OH(l) + 3O_2(g) \rightarrow 2CO_2(g) + 3H_2O(l)$ ; ΔH = −555 kJ What is the enthalpy change for combustion of 15.0 g of ethanol?

Answers

Answer: 181 kJ

Explanation:

The balanced chemical reaction is;

$C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2Ol)$ $\Delta H=-555jJ$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(15.0g)/(46.0g/mol)=0.326moles$

According to stoichiometry:

1 mole of $C_2H_5OH$ on complete combustion give= 555 kJ

Thus 0.326 moles of $C_2H_5OH$ on complete combustion give= $(555)/(1)* 0.326=181kJ$

Thus the enthalpy change for combustion of 15.0 g of ethanol is 181 kJ

Which of the following is the smallest volume? A. 2500 mL B. 250 cm3 C. 2.5 x 10-2 L D. 25 m3

Answers

The answer is c. 2.5*10-2 L. The unit cm3 is equal to mL. m3 is equal to 10^3 L. L is equal to 1000 mL. So after you change all the number to the same unit, you can get the result.

Final answer:

Among the given figures, 2.5 x 10-2 L (or 25 mL when converted to milliliters) is the smallest volume.

Explanation:

The student is asked to compare and determine the smallest volume between 2500 mL, 250 cm3, 2.5 x 10-2 L, and 25 m3. First, let's convert all volumes into a common unit, the milliliter (mL).

2500 mL = 2500 mL (already in mL),
250 cm3 = 250 mL (since 1 cm3 equals 1 mL),
2.5 x 10-2 L = 0.025 L = 25 mL (since 1 L equals 1000 mL),
25 m3 = 25 x 1,000,000 L = 25 x 1,000 x 1,000,000 mL = 25,000,000,000 mL.

From this comparison, we can see that 2.5 x 10-2 L or 25 mL is the smallest volume among the given figures.

Learn more about Volume conversion here:

brainly.com/question/35097419

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A cylinder with a movable piston contains a sample of gas having a volume of 6.0 liters at 293 K and 1.0 atmosphere. What is the volume of the sample after the gas is heated to 303 K, while the pressure is held at 1.0 atmosphere?(1) 9.0 L (3) 5.8 L
(2) 6.2 L (4) 4.0 L

Answers

The volume of sample when the gas is heated to 303 K is $\boxed{{\text{(2)6}}{\text{.2 L}}}$

Further explanation:

Charles’s law:

Charles’s work showed that at constant pressure, the volume-temperature relationship for a fixed amount of gas is linear. In other words, Charles’s law can be stated that at constant pressure, the volume occupied by a fixed amount of a gas is directly proportional to its absolute temperature (Kelvin). This relationship is known as Charles’s law.

The mathematical representation of Charles’s law is,

${\mathbf{V}}\propto{\mathbf{T}}$ [P and n are constant]

Where,

⦁ V is volume occupied by the fixed quantity of gas.

⦁ T is the temperature of a gas.

⦁ P is the pressure of a gas.

⦁ n denotes the number of moles of gas.

The relationship can also be expressed as,

$\frac{{\text{V}}}{{\text{T}}} = {\text{constant}}$ [P and n are constant]

Or it can also be expressed as follows:

$\frac{{{{\text{V}}_{\text{1}}}}}{{{{\text{T}}_{\text{1}}}}} = \frac{{{{\text{V}}_{\text{2}}}}}{{{{\text{T}}_{\text{2}}}}}$ …… (1)

Here,

${{\text{V}}_1}$ is the initial volume of gas.

${{\text{V}}_2}$ is the final volume of gas.

${{\text{T}}_1}$ is the initial temperature of the gas.

${{\text{T}}_2}$ is the final temperature of the gas.

Rearrange equation (1) to calculate ${{\text{V}}_2}$ .

${{\text{V}}_{\text{2}}} = \frac{{{{\text{V}}_{\text{1}}}{{\text{T}}_{\text{2}}}}}{{{{\text{T}}_{\text{1}}}}}$ …… (2)

The value of ${{\text{V}}_1}$ is 6 L.

The value of ${{\text{T}}_1}$ is 293 K.

The value of ${{\text{T}}_2}$ is 303 K.

Substitute these values in equation (2).

$\begin{aligned}{{\text{V}}_{\text{2}}}&=\frac{{\left({{\text{6 L}}}\right)\left( {{\text{303 K}}}\right)}}{{\left( {{\text{293 K}}}\right)}}\n&={\text{6}}{\text{.20477 L}}\n&\approx{\mathbf{6}}{\mathbf{.2 L}}\n\end{aligned}$

So option (2) is the correct answer.

Learn more:

1. Law of conservation of matter states: brainly.com/question/2190120

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: Charles’s law, volume, temperature, pressure, volume temperature relationship, absolute temperature, constant pressure, relationship, V directly proportional to T, ideal gas, ideal gas equation number of moles, moles, P, n, V, T, volume of gas, 6.2 L, 303 K, 293 K, 6 L.

The volume of the sample after the gas is heated to 303 K is 6.2 L

The correct answer to the question is Option (2) 6.2 L

From the question given above, the following data were obtained:

Initial volume (V₁) = 6 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 303 K

Pressure = constant

Final volume (V₂) =?

Using the Charles' law equation, we can obtain the final volume of the gas as follow:

$(V_(1))/(T_(1)) = (V_(2))/(T_(2))\n\n(6)/(293) = (V_(2))/(303)\n\n$

Cross multiply

293 × V₂ = 6 × 303

293 × V₂ = 1818

Divide both side by 293

$V_(2) = (1818)/(293)\n\n$

V₂ = 6.2 L

Therefore, the volume of the sample after the gas is heated to 303 K is 6.2 L

The correct answer to the question is Option (2) 6.2 L

Learn more: brainly.com/question/16927784

What are synonyms for the word control?

Answers

Answer:

Rule, oversee, discipline

Explanation:

hope it helped!

Thesaurus.com is great for answers like this but a few common ones are power, command, authority, jurisdiction, and sway

When forces attracting solvent particles to each other are broken what is provided for a solution. 1. Energy for the solute to precipitate
2. Space for the solute in the solvent
3.Inertia for the solute to move into the solvent
4. Nothing is provided

Answers

The correct answer among the choices given is option 2. When forces attracting solvent particles to each other are broken, space is provided for the solute in the solvent. This is one of the steps in the dissolving process of a solute in a solvent.

Answer: Option (2) is the correct answer.

Explanation:

A solution consists of a solute and a solvent. A solute is present in less amount as compared to the solvent in a solution.

When forces attracting solvent particles are broken down then particles of the solvent move away from each other.

As a result, spaces will be formed between the solute particles and solvent molecules can easily react with it.

Thus, we can conclude that when forces attracting solvent particles to each other are broken then space for the solute in the solvent is provided for a solution.

Given the balanced equation representing a reaction:H+(aq) + OH-(aq) ==> H2O(l) + energy
In this reaction there is conservation of
(1) mass, only
(2) mass and charge, only
(3) charge and energy, only
(4) charge, energy, and mass

Answers

Answer: option (4) charge, energy, and mass.

Justification:

1) Charge, energy, and mass are always conserved in every chemical reaction.

Charge, energy and mass are not created nor destroyed, but can be transferred.

2) The charge can only be transferred by the motion of electrons, so the charge can move and end up on a different atom, but when you add up all the charge is conserved.

The charge balance is verified in the given equation since:

left side right side

(1+) + (1-) = 1 - 1 = 0 0

∴ The total charge of the reactants equals the total charge of the products.

3) As for energy, the right side shows the "apparition" of some energy. That means that the reaction is exothermic, i.e. it releases energy.

The energy released is the net result of the difference in the potencial chemical energy of the bonds of the products and the reactants.

The reactants have more chemical energy stored than the reactants, so potential energy was transformed into heat energy.

4) As for the mass, its conservation is verified when you check that there are the same number of particles of each spieces: two particles of hydrogen in the reactand side, such as in the products; and the particles of oxygen are one in the reactants and one in the products.

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