MATHEMATICS HIGH SCHOOL

Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.Part A: Find the average rate of change of each section. (4 points)
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)

Answers

Answer 1
Answer: Average rate of change from x = 0 to x = 1 is (f(1)-f(0))/(1-0)= (5(1)-5(0))/(1)=5
Average rate of change from x = 2 to x = 3 is (f(3)-f(2))/(3-2)= (5(3)-5(2))/(1)=15-10=5
The average rate of change of both sections are equal.

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(01.05 MC)Which fraction is equivalent to 4 over negative 9?

Davies knows that the area of his square-shaped bag is 81 feet^2. what is the length of any side of the bag?

Answers

if it's a square all sides are 9 feet...9x9=81

How do you solve 2(10-6x)=x-8x
Show work

Answers

2(10)-2(6x)= x-8x 
20-12x=x-8x 
   +12x+12x

20=13x-8x
20=5x 
4=x
Hey, Lizzy147! 
1st. Distribute 2 to 10 and -6x
20-12x=x-8x 
2nd. Move -12x to the other side.
20=13x-8x
Simple math.
20=5x 
x=4

Please help! I will Upvote!Find a solution to the following system of equations.
−2x + y = −3
−x + 2y = 3

A- (–3, –9)
B- (3, 3)
C- (–21, –9)
D- (0, 2)

Answers

B (3,3)Put 3 in the x spot and 3 in the y spot. Solve for both equations that way.

Write and evaluate the expression. Then, complete the statements.ten less than the quotient of thirty and a number

Evaluate when t= 2

A 2-column table with 5 rows. Column 1 is labeled Key Words with entries ten, less than, quotient, thirty, a number. Column 2 is labeled replace with entries 10, minus, divided by, 30, t.

First, write the expression
.

Second,
2 in for the variable, t.

Third,
by using

.

The answer is
.

Answers

Answer:

The Answer is 5

Step-by-step explanation:

First, write the expression  

30/t – 10  

.

Second,  

substitute

2 in for the variable, t.

Third,  

simplify

by using  

order of operations

.

The answer is  

5

.

Answer:

Step-by-step explanation:

  •  30/t – 10  .
  • Second,  substitute2 in for the variable,
  • .Third,  simplify by using  order of operations.
  • The answer is  5

What is the loss percentage incurred by a company when it buys an asset for rs. 1,50,000 and sells it for rs. 75,500?

Answers

The loss percentagea company incurs when buying an asset for rs. 1,50,000 and selling it for rs. 75,500 is 49.7%.

The loss percentage is calculated by subtracting the selling price from thepurchase price , then dividing that result by the purchase price, and finally multiplying by 100 to get the percentage format. In this case, it's a business scenario involving the purchase and sale of an asset, so the formula is appropriate

You can use it as follows:

Loss% = [(1,50,000 - 75,500) / 1,50,000] * 100

When you calculate the expression in the square brackets you get 0.497, or 49.7%.

So, in the provided scenario, the company incurred a loss percentage of 49.7%.

This means that the company lost nearly half of the initial value of the asset when they sold it.

Learn more about the topic of Loss Percentage here:

brainly.com/question/30938251

#SPJ11

Answer:

percentage incurred  [(75,500-150,000)/150000]*100=49,666=49,6%

Step-by-step explanation:

1.15
a fraction that is equal to the decimal​

Answers

i believe it’s 23/20

Answer:

1.15=(23)/(20)

Step-by-step explanation:

1.15=(1.15)/(1)=(11.5)/(10)=(115)/(100)=((23)(5))/((2)(2)(5)(5))=(23)/((2)(2)(5))=(23)/(20)
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