CHEMISTRY HIGH SCHOOL

4.00 × 1023 molecules of H3PO4 have an approximate mass of

Answers

Answer 1

Answer:

Answer : The approximate mass of $H_3PO_4$ is 65 grams.

Explanation :

First we have to calculate the moles of $H_3PO_4$ .

As, $6.022* 10^(23)$ molecules of $H_3PO_4$ present in 1 mole of $H_3PO_4$

So, $4.00* 10^(23)$ molecules of $H_3PO_4$ present in $(4.00* 10^(23))/(6.200* 10^(23))=0.664$ mole of $H_3PO_4$

Now we have to calculate the mass of $H_3PO_4$ .

$\text{Mass of }H_3PO_4=\text{Moles of }H_3PO_4* \text{Molar mass of }H_3PO_4$

Molar mass of $H_3PO_4$ = 98 g/mole

$\text{Mass of }H_3PO_4=0.664mole* 98g/mole=65.072g\approx 65g$

Therefore, the approximate mass of $H_3PO_4$ is 65 grams.

Answer 2

Answer: 1 mole --------- 6.02 x 10²³ molecules
? mole --------- 4.00 x 10²³ molecules

moles = (4.00 x 10²³) x 1 / 6.02 x 10²³

moles = ( 4.00 x 10²³) / ( 6.02 x 10²³ )

= 0.6644 moles

Molar mass H₃PO₄ = 98.0 g/mol

mass = 0.6644 x 98.0 = 65.1112 g

hope this helps!

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As an atom becomes an ion, its mass number(1) decreases(2) increases(3) remains the same

Answers

As an atom becomes an ion, its mass number $\boxed{\left( 3 \right){\text{ remains the same}}}$

Further explanation:

The smallest unit of an element is called an atom. It is also known as the building block of matter. An atom is generally represented as $_{\text{Z}}^{\text{A}}{\text{X}}$ , where X is the symbol of the element, A is its atomic mass or mass number and Z is its atomic number.

The number of protons present in the atomic nucleus is termed as the atomic number (Z) whereas the total number of nucleons present in the nucleus of an atom is called mass number or atomic mass (A).

When electrons are either gained or lost from the neutral atom, it results in the formation of ions. Cations are the positively charged ions that are formed due to the removal of electrons from the neutral atom. Anions are the negatively charged ions that result from the addition of electrons to the neutral atom.

Since the formation of either type of ion requires gain or loss of electrons but mass number is the total number of protons and neutrons present in the atomic nucleus, the mass number remains the same when ions are formed from their respective ions. Therefore option (3) is the correct answer.

Consider an example of a sodium atom whose atomic number is 11 so it has an electronic configuration of $1{s^2}2{s^2}2{p^6}3{s^1}$ . It loses one electron to form its monovalent ion, ${\text{N}}{{\text{a}}^ + }$ which has the configuration of $1{s^2}2{s^2}2{p^6}$ . The number of electrons in Na is 11 while that in ${\text{N}}{{\text{a}}^ + }$ is 10. But both the species have same number of protons and neutrons in them. So the mass number remains unchanged if an atom forms its ions.

Learn more:

1. Component of John Dalton’s atomic theory: brainly.com/question/2357175

2. Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: atom, matter, atomic nucleus, proton, electron, neutron, cations, anions, Na, 11, Na+, electronic configuration.

Becoming an ion involves gaining or losing electrons
Electrons have a relative mass of 0
So adding or removing them doesn't change the mass of the atom
So the answer is (3) remains the same

Find the grams of iron in 79.2 g of Fe2O3.

Answers

First you find the RFM (Relative Formula Mass) of Fe2O3
Fe2 = 56 x 2
= 112
O3 = 16 x 3
= 48

112 + 48 = 160

Moles = mass/RFM
   = 79.2/160
   =0.495

Then you rearrange the formula
Mass= moles x RFM
      = 0.495 x 112
      = 55.44 g
(To find mass of Iron have to use RFM of total iron in the substance example Fe2 ^^)

Which atomic model was proposed as a result of J. J. Thomson’s work?

Answers

J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. He then proposed the Plum Pudding Model.

The atomic model was proposed as a result of J. J. Thomson’s work was the plum pudding model.

Hope I helped : )

The acidity or alkalinity of an unknown aqueous solution is indicated by its

Answers

The acidity or alkalinity of an unknown aqueous solution is indicated by its pH value. pH value determines whether something is acidic or alkaline.

The marathon covers 26 miles, 285 yards. Express this distance in kilometers.(1 km= 0.6214 miles, 1 inch = 2.54 centimeters)
Show calculation steps

Answers

Answer:

Conversion gives 42,107 km in total

Explanation:

A marathon covers 26 miles and 285 yards.

If 1 kilometer is 0.6214 miles, then how many kilometers are 26 miles, then:

1 km = 0.6214 miles

X = 26 miles

X = 41,841 km

Now if 1 yard is 36 inches, how many inches is 285 yards?

1 yard = 36 inches

285 yards = X

X = 10260 inches

If an inch is equal to 2.54 cm, how many centimeters are 10260 inches?

1 inch = 2.54 cm

10260 cm = X

X = 26060.4 cm

And 26060.4 cm is 0.260604 km

Finally, the sum of the distance would be:

41.841 km + 0.260604 km = 42.107 km

Determine the mass of hydrogen chloride needed to react completely with 12.8 g of aluminum to produce aluminum chloride and hydrogen gas.

Answers

Taking into account the reaction stoichiometry, 51.84 grams of HCl is required to react completely with 12.8 g of aluminum to produce aluminum chloride and hydrogen gas.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 2 moles
HCl: 6 moles
AlCl₃: 2 moles
H₂: 3 moles

The molar mass of the compounds is:

Al: 27 g/mole
HCl: 36.45 g/mole
AlCl₃: 133.35 g/mole
H₂: 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 2 moles ×27 g/mole= 54 grams
HCl: 6 moles ×36.45 g/mole= 218.7 grams
AlCl₃: 2 moles ×133.35 g/mole= 266.7 grams
H₂: 3 moles ×2 g/mole= 6 grams

Mass of HCl required

The following rule of three can be applied: If by reaction stoichiometry 54 grams of Al react with 218.7 grams of HCl, 12.8 grams of Al react with how much mass of HCl?

$mass of HCl=(12.8 grams of Alx 218.7 grams of HCl)/(54 grams of Al)$

mass of HCl= 51.84 grams

Finally, 51.84 grams of HCl is required to react completely with 12.8 g of aluminum to produce aluminum chloride and hydrogen gas.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

first write out the eqn, and balance it.

next, take 12.8g/mr of aluminium
this will give u the mols of aluminium

next, take the ratio of HCL and Al, compare and find the mols of HCL.

take the mols of HCL/mr of HCL to give u mass

doneee

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