MATHEMATICS HIGH SCHOOL

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle.

Answers

Answer 1

Answer:

Answer:

$1.998\n$

Step-by-step explanation:

Given

Width of the rectangle $= 2^{(1)/(5) } \n$

Length of the rectangle $= 16^{(1)/(5) } \n$

The area of rectangle

$= Length * width\n$

= $2^{(1)/(5) } * 16^{(1)/(5) } \n= 1.148 * 1.741\n 1.998\n$

Answer 2

Answer: Hello,

It 's difficult to translate that in french.

l=16 ^(1/5)
w=2^(1/5)
Area=32^(1/5)=(2^5)^(1/5)=2 (in²)

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What are the trigonometric ratios

Answers

The trig ratios are a set of numbers that are properties
of every angle.

When the angle is in a right triangle, they can be defined
like this:

Sine (sin) of the angle: (opposite leg) divided by (hypotenuse)
Cosine (cos) of the angle: (adjacent leg) divided by (hypotenuse)

Tangent (tan) of the angle: (opposite leg) divided by (adjacent leg)
Cotangent (cot) of the angle: (adjacent leg) divided by (opposite leg)

Secant (sec) of the angle: (hypotenuse) divided by (adjacent leg)
Cosecant of the angle: (hypotenuse) divided by (opposite leg).

The size of the right triangle doesn't matter, only the ratios of
pairs of sides. That will always be the same number for the
same angle, no matter how big or small the triangle is.

There's no easy way to calculate the numbers for an angle.
You just have to look them up, using tables in books, or online
(try 'cosine 29' on Google), or on most hand-calculators.

The trigonometric ratios are special measurements of a right triangle (a triangle with one angle measuring 90 ° ). Remember that the two sides of a right triangle which form the right angle are called the legs, and the third side (opposite the right angle) is called the hypotenuse.

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y equals negative 0.04x squared plus 8.3x plus 4.3, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter. (1 point)
208.02 m
416.03 m
0.52 m
208.19 m

Answers

ok

y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate

set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x= $\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}$
a=-0.04
b=8.3
c=4.3
x= $\frac{-8.3+/- \sqrt{8.3^(2)-4(-0.04)(8.3)} }{2(-0.04)}$
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m

Rhian sat a Maths test and an English test. In the Maths test she scored 14/17. In the English test she scored 31/39

Answers

MATH- 14x100/17= 82.3%
LA- 31x100/39 = 79%

82.3%>79%
She did better in the math class.

what is the question?

Prove that

(1 + cot A + tan A) (sin A - cos A) = sin A tan A - cot A cos A

Answers

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

tan A = $(sinA)/(cosA)$ , cot A = $(cosA)/(sinA)$

Consider the left side

(1 + cotA + tanA)(sinA - cosA)

each term in the second factor is multiplied by each term in the first factor.

1(sinA - cosA) + cotA(sinA - cosA) + tanA(sinA - cosA)

= sinA - cosA + cosA - $(cos^2A)/(sinA)$ + $(sin^2A)/(cosA)$ - sinA ( collect like terms )

= $(sin^2A)/(cosA)$ - $(cos^2A)/(sinA)$

= ( sinA × $(sinA)/(cosA)$ ) - ( $(cosA)/(sinA)$ × cosA )

= sinAtanA - cotAcosA

= right side ⇒ proven

Identify the turning point of the function f(x)=x^2-2x+8 by writing its equation in vertex form.Show work

Answers

$f(x)=x^2-2x+8 \n \n To \ convert \ the \ standard \ form \ y = ax^2 + bx + c \n \n of \ a \ function \ into \ vertex \ form \n \n y = a(x - h)^2 + k \n \n Here \ the \ point \ (h, k) \ is \ called \ as \ vertex \n \n h=(-b)/(2a) , \ \ \ \ k= c - (b^2)/(4a)\n \n a=1 ,\ b=-2 , \ c = 8$

$h=(-b)/(2a)=(-(-2))/(2 )=(2)/(2)=1 \n\n k=c - (b^2)/(4a) =8 - ( (-2)^2)/(4 ) = 8-1 = 7 \n \n y= (x-1)^2 + 7 \n \n So \ the \ turning \ point \ is \ (1,7)$

A store is selling candy for $8 for 16 bags. How much will it cost if you need to have 84 bags?

Answers

16 bags are $8. However, you need more than 16 bags; you need 84.

So the first thing you do is divide 84 by 16 which is 5.25. This means that if 16 bags are $8, then you need to multiply the price and quantity by 5.25 to work out how much it is for 84 bags:

$8 = 16 bags

Multiply by 5.25:

$8 * 5.25 = 16 bags * 5.25

$42 = 84 bags

Therefore, it’ll cost $42 to buy 84 bags.

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