Solve the equation 3x + 6y = 18 for y

Answers

Answer 1

Answer: y= -x/2 + 3 Move all terms that don't have "y" to the right side to solve it

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Increase 48m by 20%? Help Please I'm Useless At Math<3

Answers

We have 48 meters.
We need to increase it by 20%.
That means we have 48 and then we increase it by 20%.

That can be expressed as:
48 + (48 * 20%)

Now, another way to write that would be:

48 * 120%

Now, 120% is nothing but 120/100. This can even be simplified to 1.2.

48 * 120%
= 48 * 1.2
= 57.6

48m increased by 20% is 57.6m.

You multiply 48m with 20% and add that to 48m.
20% can be written as 20/100.

$48m*(20)/(100)+48m$

$(48m*20)/(100)+48m$

$(960m)/(100)+48m$

$9.6m+48m$

${\boxed{57.6m}$

Which word describes a triangle with three angles, if each angle measures less than 90°?

Answers

Answer:

acute triangle

Step-by-step explanation:

A triangle with all angles less than 90 degrees has all angles that are acute.

Acute angles are less than 90 degrees

What is the value of (–7 + 3i) – (2 – 6i)?–9 + 9i
–9 – 3i
–5 – 3i
–5 + 9i

(-7 + 3i) - (2 - 6i) = -7 + 3i - 2 + 6i = (-7 + (-2)) + (3i + 6i) = -9 + 9i

This is how I worked it out^ Was I correct?

Answers

-9+9i is in fact correct so A is right
:)

The answer is correct. If you have a graphing calculator, there is an "i" button, so the calculator does all your work for you and is a good way to check your answers.

Jonas is planning out his route for an upcoming race. He uses negative numbers to represent points before the finish line and positive numbers to represent points after the finish line. On Jonas's map, there is a bridge at -91 \dfrac34−91 4 3 minus, 91, start fraction, 3, divided by, 4, end fraction meters, and his wife is watching him at 14 \dfrac1214 2 1 14, start fraction, 1, divided by, 2, end fraction meters. What does 000 meters represent? Choose 1 answer: Choose 1 answer:

Answers

Answer:

(C)The finish line

I need the answer for -3x-3=4x+3

Answers

Answer:

$\huge\boxed{x=-\frac{6}7}$

Step-by-step explanation:

To solve this problem, use the fact that you can perform any operation(with a few exceptions) to both sides of an equation, to isolate the variable.

Simply subtract 3 from both sides to get:

-3x - 3 - 3 = 4x + 3 - 3

-3x - 6 = 4x

Then add 3x to both sides to get:

-3x + 3x - 6 = 4x + 3x

-6 = 7x

Then divide both sides by 7 to get:

-6 / 7 = 7x / 7

-6/7 = x

Hope it helps :) and let me know if you want me to elaborate

Answer:

-6/7

Step-by-step explanation:

You can use your calulater

step 1: turn it on

Step 2: press 2nd button

step 3: press the number-solve button

step 4:type the equations just like it is writed

Step 5: usef<>d button

and you get your answer -6/7

Find an equation of the line satisfying the given conditions

Through (6,4); perpendicular to 3X + 5Y =38

Answers

To answer this, we will need to know:

• The slope of the equation we are trying to get
• The point it passes through using the

First, we will need to find the slope of this equation. To find this, we must simplify the equation $3x+5y=38$ into $y=mx+b$ form. Lets do it!

$3x+5y=38$
= $5y = -3x+38$ (Subtract 3x from both sides)
= $y= -(3)/(5)x+ (38)/(5)$ (Divide both sides by 5)

The slope of a line perpendicular would have to multiply with the equation we just changed to equal -1. In other words, it would have to equal the negative reciprocal.

The negative reciprocal of the line given is $(5)/(3)$ .

Now that we know the slope, we have to find out the rest of the equation using the slope formula, which is:

$(y-y _(1) )/(x- x_(1) )=m$

Substituting values, we find that:

$(y-4)/(x-6)= (5)/(3)$

By simplifying this equation to slope-intercept form (By cross-multiplying then simplifying), we then get that:

$y= (5)/(3)x-6$ , which is our final answer.

Thank you, and I wish you luck.

$(6,4); 3x + 5y =38 \ subtract \ 3x \ from \ each \ side \n \n 5y = -3x + 8 \ divide \ each \term \ by \ 5 \n \n y = -\frac{3} {5}x + (38)/(5)\n \n The \ slope \ is :m _(1) = - (3)/(5) \n \n If \ m_(1) \ and \ m _(2) \ are \ the \ gradients \ of \ two \ perpendicular \n \n lines \ we \ have \ m _(1)*m _(2) = -1$

$m _(1) \cdot m _(2) = -1 \n \n -(3)/(5) \cdot m_(2)=-1 \ \ / \cdot (-(5)/(3)) \n \n m_(2)=(5)/(3)$

$Now \ your \ equation \ of \ line \ passing \ through \ (6,4) would \ be: \n \n y=m_(2)x+b \n \n4=(5)/(\not3^1) \cdot \not 6^2 + b$

$4=5 \cdot 2+b\n \n4=10+b \n \nb=4-10\n \nb=-6 \n \n y = (5)/(3)x -6$

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