What is the complement of pie/4

Answers

Answer 1
Answer: complement is adds to 90 degrees=360/4
2pi=360
divid both sides by 4
pi/2=90 degrees

so
pi/4+comlement=pi/2
pi/4+complement=2pi/4
minus pi/4 both sides
comlement=pi/4

the comlement i pi/4

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Suppose ∠A and ∠B are complementary angles, m∠A = (3x + 5)°, andm∠B = (2x – 15)°. Solve for x and then find m∠A and m∠B.
Five years ago, Rhea put $20,000 into savings. Now it's worth $30,000. Which of the following statements is true for this situation?

Which expression has a value of 15 when

Answers

The expression has a value of 15 when you divide by 2.

Answer:

thx

Step-by-step explanation:

Which angle measure less than or equal to 360° is equivalent to an angle of 17π over 4

Answers

Hello,

17/4π rad = (4π+π/4  )rad

17/4 π mod 2π = π/4 (rad) or 45°

A car dealership lowered all of its car prices by 15%. Given the above information, what was the original price of a car now priced at £9500?

Answers

9,500 is 15% less than the original price.
So it must be 85% of the original price.

£9,500 = 0.85 P

Divide each side by 0.85 :

P = £9,500 / 0.85 = £11,176.47
the original price would be 9500+(0.15*9500)=10925

Solve 2cos x+2cos 2x=0 on the interval [0,2pi)

Answers

2cosx+2cos2x=0 \n -2sin^2x+2cos^2x+2cosx=0 \n -2(1-cos^2x)+2cos^2x+2cosx=0 \n -2+2cos^2x+2cos^2x+2cosx=0 \n 4cos^2x+2cosx-2=0 \n t=cos x \n 4t^2+2t-2=0 \n \Delta=4+32=36 \n t_1= (-2-6)/(8)=-1 \n t_2= (-2+6)/(8)= (1)/(2) \n cos x=-1 \lor cos x= (1)/(2) \n x=-\pi \lor x= (5\pi)/(3)

1. Which of the following is equivalent to x5y2/xy2 when x ≠ 0 and y ≠ 0? A. x6y5
B. x5y
C. x4y
D. x4

Answers

x5y2/xy2=x5   .y2/x  . y2, simplifying by y², it becomes x5/x, simplify by x, we found x5/x= x4
the answer is 
D. x4

How do you factor 80y^2-4y-4? or is it prime?

Answers

80y^2-4y-4\n\na=80;\ b=-4;\ c=-4\n\n\Delta=b^2-4ac\n\n\Delta=(-4)^2-4\cdot80\cdot(-4)=16+1280=1296 > 0\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(1296)=36\n\ny_1=(4-36)/(2\cdot80)=(-32)/(160)=-(1)/(5);\ y_2=(4+36)/(2\cdot80)=(40)/(160)=(1)/(4)


80y^2-4y-4=80(y+(1)/(5))(y-(1)/(4))\n\n\n80(y+(1)/(5))(y-(1)/(4))=4\cdot5\cdot4\cdot(y+(1)/(5))(y-(1)/(4))=4(5y+1)(4y-1)




80y^2-4y-4=80y^2-4y-16y+16y-4=80y^2-20y+16y-4\n\n=20y(4y-1)+4(4y-1)=(4y-1)(20y+4)
80y^2-4y-4=4(20y^2-5y+4y-1)=4[5y(4y-1)-(4y-1)]=\n \n=4(4y-1)(5y-1)