What is elastic potential energy
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Related Questions
What fundamental force is responsible for the settling of Earth's layers?
In which direction should you look to see the setting moon.
Two waves are superposed. One wave has an amplitude of 3 cm, and the other has an amplitude of 4 cm. What is the resultant amplitude?
an object falls from a high building. ignoring air resistance, what will its velocity be after 7 seconds of falling
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Answer:
Two tunnig fork of frequency 520 Hz and 524Hz are vibrated together. It means beats form due to it .
f₁ = 524 Hz
f₂ = 520 Hz
Beat period = 1/number of Bea are formed per unit time
= 1/(f₁ - f₂)
= 1/(524 - 520)
= 1/4 sec
Now, time inveral between successive maximum and minimum intensities = beat period= 1/4 sec
Explanation:
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Answer:
All of the above
Explanation:
According to Newton's second law of motion,
If a certain force is applied on objects of different mass, the lighter object will travel farther and faster. All the options in the question have pairs where one object is lighter than other.
So, Jim can throw a tennis ball farther than a basketball. Jim can throw a can of soda farther than a liter bottle of soda and he can throw a chair farther than a couch.
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The distance between the roof and the ground where the balloon water was dropped is 30.65 meters. This is computed using the free fall formula which state that the height or distance is equal to the time it takes object to hit the ground times the constant gravity. In this case, 2.5 seconds times 9.807 meter per square second will then give us the 30.65 meter.
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√(60 square+80 square)
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Answer:
0.20kg-m^2
Explanation:
Let the linear velocity of the rope(=of pulley) is v m/s
Using kinematic equation
=> v = u + at
=>v = 0 + 4.9a
=>v = 4.9a ------------ eq1
By v^2 = u^2 + 2as
=>v^2 = 0 + 2 x v/4.9 x 1.2
=>4.9v^2 - 2.4v = 0
=>v(4.9v - 2.4) = 0
=>v = 2.4/4.9 = 0.49 m/s
Thus by v = r x omega
=>omega = v/r = 0.49/0.02 = 24.49 rad/sec
BY W = F x s = 50 x 1.2 = 60 J
=>KE(rotational) = W = 1/2 x I x omega^2
=>60 = 1/2 x I x (24.49)^2
=>I = 0.20 kg-m^2
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Answer:
The first one.
Final answer:
If the road becomes wet or crowded, you should slow down and increase your following distance.
Explanation:
If the road becomes wet or crowded, you should slow down and increase your following distance. This is important because wet roads reduce tire traction and increase the risk of sliding and losing control. By slowing down and increasing your following distance, you give yourself more time to react and stop if necessary.
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