Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?

Answers

Answer 1
Answer:

Answer:

x^2-3x-5

Step-by-step explanation:

The standard quadratic equations are given in the form of

ax^2+bx+c

Comparing the values of a , b and c and putting a=1 , b=-3 and c=-5 in the equation we get our quadratic polynomial as

x^2-3x-5

Answer 2
Answer: c-b=-2a If that is a possibility.

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-4 (5x - 1)+ -11 (2x + 4)

Answers

Answer:

−42x−40

Step-by-step explanation:

Choose the most precise measurement?
A. 8 mL
B. 12 mL
C.1 mL
D. 0.05 mL

Answers

D. 0.05 is most precise as it is has the greatest number of numbers after the decimal place.

Suppose that the equation of motion for a particle (where s is in meters and t in seconds) is s = 5 t^2 - 8 t + 3
find the acceleration at the instant when the velocity is at 0

Answers

Differentiate equation
v = 10t - 8
Differerentiate again
a = 10

Accelleration will always be 10m/s^-2

Please can anyone solve 9n-10=4n+10

Answers

yes

remember you can do anything to an equaiton as long as you do it to boh sides
ad try to get unknown to one side
9n-10=4n+10
minus 4n both sides
9n-4n-10=4n-4n+10
5n-10=0+10
add 10
5n+10-10=0+10+10
5n+0=20
5n=20
divide both sies by 5
5n/5=20/5
5/5n=4
1n=4
n=4
9n-10=4n+10
+10           +10
9n=4n+20
-4n     -4n
5n =20
/5     /5
n=4

Three-toed sloths have four legs. How many toes would 25 sloths have?

Answers

300

3 * 4 = 12

12* 25 = 300

Hope this helps! :D

Given the Function:f(x) = -2e^x find f(x), if x=3
So far what I manage to grasp with this equation is
replacing the "x" with 3 So: f(3)= -2e^(3)
The answer ( using the scientific calculator) gave me -6
I have no Idea what are the other steps to this equation.

Answers

f(x)=-2e^x
x=3
f(3)=-2e^3
pemdas so exponents first
e^3
e=2.718281828454590
cube that
20.0855

now we have
-2 times 20.0855=-40.1711

answer should be -40.1711
(I see what you did wrong, if -6=-2 times e^3, divide -2, 3=e^3, maybe you just put -2 times 3 by mistake)
okay e^3 is 20.08553692 x -2 = 4.017107385
maybe you had your calculator on the wrong mode or entered it wrong