PHYSICS HIGH SCHOOL

It is proposed that future space stations create an artificial gravity by rotating. Suppose a space station is constructed as a 1600-m-diameter cylinder that rotates about its axis. The inside surface is the deck of the space station. What rotation period will provide "normal"gravity?

Answers

Answer 1

Answer:

The rotation period that will provide normal gravity will be 57.12 seconds.

From the information given, the diameter of the cylinder is 1600m. Therefore, the radius will be:

= Diameter / 2.

= 1600 / 2

= 800m

Acceleration due to gravity = 9.8m/s²

Since a = rw², we'll use the subject of the formula to find w and this will be:

w = √g/✓r

w = ✓9.8 / √800

w = 0.11 rad/s

Therefore, the rotation period will be:

T = 2π/w

T = 2π/0.11

T = (2 × 3.142) / 0.11

T = 57.12 seconds

In conclusion, the correct option is 57.12 seconds.

Read related link on:

brainly.com/question/13436796

Answer 2

Answer:

Answer

given,

diameter of the cylinder = 1600 m

radius = 800 m

acceleration due to gravity = 9.8 m/s²

a = r ω²

$\omega = \sqrt{(g)/(r)}$

$\omega = \sqrt{(9.8)/(800)}$

$\omega = 0.11\ rad/s$

we know time period

$T = (2\pi )/(\omega )$

$T = (2\pi )/(0.11)$

T = 57.12 s

Related Questions

The combination of two or more atoms, from the same or different elements, creates a(n)_____
Which is not true about neutron? (a) It is neutral particle (b) It is highly unstable in nature (c) It is present in the nucleus. (d) It contributes to the most of the atom
When the mass of an object increases, the force of gravityincreases.decreases.remains the same.becomes irregular.
A new object has been discovered in the solar system. In your own words, justify how the object can be proved to be a comet.
TRUE OR FALSE : Boyle’s law states that, as the pressure of a gas increases, the volume decreases.

A train moves at a constant velocity of 90 km/h. How far will it move in 0.25h?

Answers

In 0.25h it will move in 22.5 kilometers.

An atom that gains or loses an electron has a net electric charge and is called a/na. proton.
b. ion.
c. electron.
d. neutron. user: which sentence best describes mass movement?
a. the steady pace of air bouncing off a mountain
b. the downhill movement of animals due to heavy snow in their normal home
c. the movement of particles within an atom
d. the downhill flow of soil and rock resulting from gravity

Answers

The answer for the first question is B. Ion.

The answer would be B. Ion.

A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 20.0 m/s. Then the truck travels for 20.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s. (a) How long is the truck in motion? (b) What is the average velocity of the truck for the motion described?

Answers

You can use the equation
V_xf = V_xi + a_x(t)

V_xf = 20.0m/s
V_xi = 0m/s
ax = 2.0t

Thus, solve for t and get 10secondsand then take 5 seconds to break after 20 seconds of drivingso for

a) 10 + 20 + 5 = 35 seconds

for part b)
You can use the formula
Delta x/Delta t = average velocity

Need to find xf, knowing xi = 0

Thus, use the formula
x_f = x_i + V_xi(t) + (1/2)a_x(t)^(2)
x_f = 0 + 0(10) + (1/2)(2.0)(10)^(2)
x_f = 100m

so for the first 10 seconds the truck traveled 100msAt a speed of 20m/s

20m/s = xm/20s20*20 = x
x = 400

thus we have 100+400 = 500mthen it slows down from 500m to x_f

thus I use the equation
x_f = x_i + (1/2)(V_xf + V_xi)t
x_f = 500 + (1/2)(0 + 20)(5)x_f = 500 + 50
x_f = 550

therefore the total distance traveled is 550m

to calculate average velocity
550/35 = 16m/s

thusV_xavg = 16m/s

A 30.0 kg object rests on a flat, frictionless surface. A rope lifts up on the object with a force of 309 N. What is the acceleration of the object?

Answers

total force = Frope - mg = 309-300
total force = ma
9 = 30a

A car traveling with constant speed travels 150 km in 7200s. What is the speed of the car?

Answers

Speed= distance/time
Speed= 150000m/7200s=20.83m/s(cor.to.2d.p.)

A small object with mass m = 0.0900 kg moves along the +x-axis. The only force on the object is a conservative force that has the potential-energy function U(x)=−αx2+βx3, where α=2.00J/m2 and β=0.300J/m3. The object is released from rest at small x. When the object is at x = 4.00 m, what are its (a) speed and (b) acceleration (magnitude and direction)? (c) What is the maximum value of x reached by the object during its motion?

Answers

The conservation of mechanical energy allows to find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Given parameters

The potential energy U = - α x² + β x³ with α= 2 j/m² and β= 0.3 j/m³

The mass of the body m = 0.0900 kg

The distance x = 4.00 m

To find

a) The speed

b) The acceleration

c) The maximum value of the distance

The conservation of mechanical energy is one of the most important concepts in physics, stable that if there is not friction the mechanical energy remains constant at all points.

Em = K + U

Where Em mechanical energy, K the kinetical energy ang U the potential energy.

a) Let's find the velocity using the conservation of mechanical energy

Starting point. Where the mass is released.

Em₀ = U (0)

Final point. When for a distance of x = 4 m here we have potential and kinetic energy.

$Em_f$ = K + U (4)

They indicate that the only force is conservative, therefore mechanicalenergy is conserved

Em₀ = $Em_f$

0 = ½ m v² + U (4)

½ m v² = -U (4)

v² = 2 / m (αx² - β x³)

Let's calculate

v² = $(2)/(0.09)$ (2 4² - 0.3 4³)

v = $√(284.44)$

v = 16.9 m / s

b) Acceleration is requested at this point.

We use that potential energy and force are related

F = $- ( dU)/(dx)$

We carry out the derivatives

F = 2αx - 3βx²

Let's calculate

F = 2 2 4 - 3 0.3 4²

F = 1.6 N

Now we use Newton's second law that relates the net force with the product of the mass and the acceleration of the body.

F = ma

a = $(F)/(m)$

a = $(1.6)/(0.09)$

a = 17.8 m / s²

c) At maximum displacement.

Let's use conservation of mechanical energy

Starting point. Where x = 0 is released

Emo = U (0) = 0

Final point. Point of maximum elongation, kinetic energy is zero

$Em_f$ = U (xmax)

Energy is conserved

Em₀ = $Em_f$

$0 = U(x_(max))$

-αx² + βx³ = 0

x² (-α + βx) = 0

the solutions of this equation is:

x = 0

-α + βx = 0

x = $(\alpha)/(\beta )$

Let's calculate

x = $(2)/(0.3)$

x = 6.67 m

In conclusion using the conservation of mechanical energy we can find the results for the questions of the motion of mass in a conservative force are;

a) the velocity at x = 4 m is: v = 16.9 m / s

b) The acceleration at x = 4m is: a = 17.8 m / s²

c) The maximum elongations is: x = 6.67 m

Learn more here: brainly.com/question/2615468

Answer:

a) v= 284.44 $(m)/(s^(2))$

b) a=17.78 $(m)/(s^(2) )$

c) x=6.67m

Explanation:

a).

$U(x)=-\alpha *x^(2) +\beta*x^(3)\n\alpha=2(J)/(m^(2))\n\beta=0.3(J)/(m^(2))\nU(0)+V(0)=U(4)+V(4)\nU(0)=-\alpha *0^(2) +\beta*0^(3)=0\nU(0)=0\nV(0)=0\n0=U(4)+V(4)\nU(4)=-\alpha *4^(2) +\beta*4^(3)\nU(4)=-2*4^(2)+0.3*(4^(3))\nU(4)=-12.8 J\n0=-12.8J+V(4)\n12.8=(1)/(2)*m*(v_(4))^(2) \n v_(4)^(2) =(2*12.8J)/(0.09kg)\n v_(4)^(2)=284.44$

$v_(4)=√(284.44)\nv_(4)=16.8 (m)/(s)$

b).

$F_(x)=(dU)/(dt)\nF_(x)=2*\alpha*x-3*\beta *x^(2) \nF_(4)=2*2*4-3*0.3*(4)^(2)\nF_(4)=1.6N\nF_(4)=m*a\na=(F_(4))/(m)=(1.6N)/(0.09kg)\na=17.7 (m)/(s^(2) )$

c).

$F_(x)=m*ax\nax=(F_(x))/(m) \nax=(4x-0.9x^(2))/(0.09kg)\n(dVx)/(dt)= (4x-0.9x^(2))/(0.09kg)\n\int\limits^x_x {(1)/(0.09)*(4x-0.9x^(2)) } \, dx\n (Vx^(2) )/(2)=22.2x^(2) -3.3x^(3)$

Value x,0

$Vx^(2) =44.4x^(2) -6.6x^(3)\n Vx=\sqrt{44.4x^(2) -6.6x^(3)}$

Inside the square root is the value of maximum value of x

$44.4x^(2) -6.6x^(3)=0\nx^(2)(44.4-6.6x)=0\n x=0$ but that value is not real so:

$44.4-6.6x=0\n6.6x=44.4\nx=(44.4)/(6.6)\n x=6.67m$

Other Questions

List five factors that may affect the rate of a chemical reaction

What is the capital of prince edward island

A 10-kilogram bicycle is traveling at a speed of 2 m/s. what is the bikes kinetic energy?

Choose the best answer for each situation. a scientist with the epa examining water for contamination writes down that there was an iridescent sheen on the surface of the water. what type of data did the scientist record? a scientist needs to know the temperature of the water every 5 m along 3 km of the river. what tool would the scientist use?