What are the values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0?a = 2, b = 4, c = 3

a = 2, b = 4, c = –3

a = –2, b = 4, c = 3

a = –2, b = 4, c = – 3

Answers

Answer 1
Answer: If you would like to find the values of a, b, and c in the quadratic equation, you can do this using the following steps:

ax^2 + bx + c = 0
-2x^2 + 4x - 3 = 0
a = -2
b = 4
c = -3

The correct result would be a = –2, b = 4, c = – 3.
Answer 2
Answer:

Final answer:

The values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0 are: a = -2, b = 4, and c = -3.

Explanation:

The values of a, b, and c in the quadratic equation –2x^2 + 4x – 3 = 0 are:

a = -2

b = 4

c = -3

In a quadratic equation in the form ax^2 + bx + c = 0, the coefficients a, b, and c represent different values. In this equation, -2 is the coefficient of the x^2 term, 4 is the coefficient of the x term, and -3 is the constant term.

Learn more about Quadratic Equations here:

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Answers

Hello,

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Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a constant rate of 1.5 m/s, how fast is the area of the spill increasing when the radius is 30 m?

Answers

Answer:

The area of the oil spill is increasing at a rate 180 π m²/s, when the radius is 30 m.

Step-by-step explanation:

Derivative Rule:

  • (d)/(dx)x^n=nx^(n-1)
  • (d)/(dx)(y^n)=ny^(n-1)(dy)/(dx)

Given that

The radius of the oil spill increases at a rate 1.5 m/s.

i.e (dr)/(dt)= 1.5\ m/s

We need to find the rate of area increase i.e (dA)/(dt) .

We know,

The area of the oil spills A = \pi r^2  ( since it spreads in circular pattern)

\therefore A=\pi r^2

Differentiating with respect to t

(dA)/(dt)=\pi. 2r(dr)/(dt)

Plug the value of (dr)/(dt) =1.5 \ m/s

(dA)/(dt)=\pi. 2r(3\ m/s)

\Rightarrow (dA)/(dt)=6\pi r \ m/s

Plug r= 30 m

\Rightarrow (dA)/(dt)=6\pi (30\ m) \ m/s

         =180 π m²/s

The area of the oil spill is increasing at a rate 180 π m²/s, when the radius is 30 m.

Choose the correct product of (2x + 10)2.4x2 − 100
4x2 + 40x + 100
4x2 + 100
4x2 − 40x + 100

Answers

Answer: 4x² + 40x +100

(2x+10)(2x+10)
4x2 + 20x + 20x +100
4x2 + 40x + 100

Answer:

(2x+10)^2=4x^2+40x+100

Step-by-step explanation:

Given the expression

(2x+10)^2

we have to simplify the above expression.

By identity

(a+b)^2=a^2+2ab+b^2

Put a=2x and b=10

(2x+10)^2=(2x)^2+2(2x)(10)+10^2

(2x+10)^2=4x^2+40x+100

Option B is correct.

Plot the following points on the grid and calculate the slope of the line that passes through them (-2, -3) and (4, 5): a) 1 b) 2 c) 3 d) 4"

Answers