The total energy of a 0.050 kg object travelling at 0.70 c is:A) 2.10 × 107 J

B) 3.06 × 107 J

C) 2.46 × 1015 J

D) 6.30 × 1015 J

E) 8.82 × 1015 J

Answers

Answer 1

Answer:

1.1025×10^15Joules

No correct option

Explanation:

The type of energy possessed by the object is kinetic energy. Kinetic energy is the energy due to virtue of an object motion.

KE = 1/2MV² where;

M is the mass of the car = 0.05kg

V is the velocity of the car

Since the car is traveling at 0.7c (c is the speed of light)

speed = 0.7c { 0.7(3×10^8)}

Speed = 2.1×10^8

Substituting this values in the formula given we have;

KE = 1/2×0.05×(2.1×10^8)²

KE = 1.1025×10^15Joules

No correct option.

Answer 2

Answer: What is the unit c denotes here

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A container holding 1.2 kg of water at 20.0 °C is placed in a freezer that is kept at –20.0 °C. The water freezes and comes into thermal equilibrium with the interior of the freezer. a) How much heat is extracted from the water in thisprocess?
b) What is the minimum amount of electrical energy required bythe refrigerator to carry out this process if it operates betweenreservoirs at temperatures of 20.0 °C and -20.0 °C?

Answers

Answer:

(a) $Q=556464\ J$

(b) 556464 joule

Explanation:

Given:

mass of water, $m_w=1.2\ kg$

initial temperature of water, $T_i=20^(\circ)C$

final temperature of frozen water, $T_f=-20{}^(\circ)C$

The conversion of water of 20.0 °C to the ice of –20.0 °C will comprise of three steps:

cooling of water to 0 °C $Q_w$
formation of ice at 0 °C from the water of 0 °C $Q_L$
further cooling of ice of 0 °C to -20 °C $Q_i$

We have,

Latent heat of fusion of ice, $L=3.4* 10^5\ J.kg^(-1)$

specific heat of water, $c_w=4186\ J.kg^(-1).^(\circ)C^(-1)$

specific heat of ice, $c_i=2000\ J.kg^(-1).^(\circ)C^(-1)$

(a)

Now, total heat lost in the process:

$Q=Q_w+Q_L+Q_i$

$Q=m_w(c_w. \Delta T_w+L+c_i.\Delta T_i)$

where:

$\Delta T_i\ \&\ \Delta T_w$ = change in temperature of ice and water respectively.

$\Rightarrow Q=1.2(4186* 20+3.4* 10^5+2000* 20)$

$Q=556464\ J$ is the total heat extracted during the process.

(b)

So, 556464 joule is the minimum electrical energy (by the law of energy conservation under no loss condition) required by refrigerator to carry out this process if it operates between the reservoirs at temperatures of 20.0 °C and -20.0 °C, because for a refrigerator to work in a continuous cycle it is impossible to transfer heat from a low temperature reservoir to a high temperature reservoir without consuming energy in the form of work. Here 556464 joule is the heat of the system to be eliminated.

Final answer:

The amount of heat extracted from the water involves the sum of heat lost as it cools and then freezes. The minimum energy needed by the refrigerator to do this is given by the formula for Carnot efficiency.

Explanation:

To answer these questions, we'll need to understand some fundamental principles of thermodynamics.

a) The heat Q taken from the water will be the sum of the heat released during cooling of the water until 0.0°C, and the heat released during freezing at 0.0°C. The heat loss as the water cools can be calculated using Q = mcΔt where m=mass of water, c=specific heat of water, and Δt=change in temperature. The heat loss as water freezes can be calculated using Q = mlf where lf is the latent heat of fusion. Adding these two quantities gives the total heat extracted.

b) The minimum energy needed by the refrigerator, W, is given by the Carnot efficiency formula, W = Q*(T_hot - T_cold)/T_hot, where T is in Kelvin. This would tell you how much energy the refrigerator needs to remove the heat from the water and cool it down to the freezer temperature.

Learn more about Thermodynamics here:

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A 55kg female bungee jumper fastens one end of the cord (made of elastic material) to her ankle and the other end to a bridge. Then she jumps off the bridge. As the cord is stretching it exerts an elastic force directed up on her. Calculate her acceleration at the instant the chord exerts an elastic force of 825N [up] on her.

Answers

Downward force = gorce of gravity (her weight) = 55 x 9.8 = 539 newtons / / / Upward force = 825 newton. / / / Net force = 825 - 539 = 286 newtons upward. / / / F = m a / / / a = f / m = 286 / 55 = 5.2 meters per second squared Upward. / / / Note: We don't know the length of her fall before the bungee kicks in. At the moment we're dealing with, when her acceleration is 5.2 m/s-squared Upward, her velocity can very well be Downward.

When the jumper jumps off , there is always a force of gravity acting on her which is 55*9.8 =539N downwards. (Considering the acceleration due to gravity to be 9.8)
Since the question says that the force exerted by cord is 825N upwards , it is obvious that the pseudo force of acceleration must act downwards and the jumper must be moving upwards.
Assume the acceleration at that instant be 'a' .
Pseudo force = mass * acceleration = 55*a
Since the body is in dynamic equilibrium , all forces must cancel out.
Hence ,
539 +55*a = 825
=> 55*a = 825-539 = 286
=> a = 286/55 = 5.2
So , acceleration at that instant was 5.2 m/s²

Which of the following cannot be transmitted through avacuum?
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b. UV rays
C. Laser
d. X-rays
e. microwave

Answers

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Answers

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On a spending spree in Malaysia, you buy an ox with a weight of 28.9 piculs in the local unit of weights: 1 picul = 100 gins, 1 gin = 16 tahils, 1 tahil = 10 chees, and 1 chee = 10 hoons. The weight of 1 hoon corresponds to a mass of 0.3779 g. When you arrange to ship the ox home to your astonished family, how much mass in kilograms must you declare on the shipping manifest? (Hint: Set up multiple chain-link conversions.)

Answers

Answer:

1747.41 kg

Explanation:

If 1 piculs = 100 gins,

Then 28.9 piculs = (28.9 × 100) gins = 2890 gins.

Also,

If 1 gin = 16 tahils

then 2890 gins =( 16 × 2890 ) = 46240 tahils

Also,

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Also,

If 1 chee = 10 hoons

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Also,

If 1 hoon = 0.3779 g,

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The mass in kg that i will declare in the shipping manifest = (1747409.6/100 )kg = 1747.41 kg

Why do deer depend on plants to survive

Answers

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