Find the upper quartile of this data set: 593, 588, 540, 434, 420, 398, 390, 375A. 427

B. 394

C. 420

D. 564

Answers

Answer 1

Answer: The answer is D. 564
When you put all the numbers in order from least to greatest and find the median which is between 420 and 434, you can then find your upper quartile which would be between 540 and 588 making it D

Answer 2

Answer:

Answer:

564.

Step-by-step explanation:

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Prove that there is a positive integer that equals the sum of the positive integers not exceeding it. Is your proof constructive or nonconstructive :)

Answers

Constructive. To prove that there is a positive integer that equals the sum of the positive integers not exceeding it. A plain and simple example is
1.1 + 2 = 3
2.10 + 50 + 100 =160
3.6x + 8x + 2x = 16 x

Notice that the sum of the numbers is always greater than the addends. This only proves that any positive sum of any two positive addends will not compare and thus the addends not exceeding a greater value than the sum.

PLEASE HELP FAST. WILL MARK AS BRAINLIEST IF GIVEN GOOD ANSWER

Answers

Answer:y=9

Step-by-step explanation:

Which represents the solution(s) of the system of equations, y = x2 – x + 1 and y = x? Determine the solution set by graphing.(1, 1)
(0, 1) and (1, 1)
(0, 0) and (1, 1)
no solutions

Answers

Answer:

$(1,1)$

Step-by-step explanation:

we have

$y=x^(2)-x+1$ -------> equation A

$y=x$ -------> equation B

we know that

The solution of the system of equations is the intersection points both graphs

using a graphing tool

see the attached figure

The intersection both graphs is the point $(1,1)$

therefore

the solution is the point $(1,1)$

Hello,

sol={(1,1)}

Answer A

Help please it's due 11:59 pmSuppose there are two car dealerships, A and B. At A, each member of the sales staff is paid a fixed monthly amount of
$2,000 plus a $200 bonus for each car he or she sells. At B, each salesperson is paid a fixed monthly amount of $2,500 but
does not receive a bonus for each car he or she sells. In which setting will a member of the sales staff be more likely to
work harder? Why is this important?

Answers

They would work harder at A because if they sell 3 cars they would get paid more than if they worked at B

Which expression gives the solutions of -5+2x^2=-6x

Answers

Answer:

The solutions are

$x1=(-6+2√(19))/(4)$

$x2=\frac{-6-2√(19)} {4}$

Step-by-step explanation:

we have

$-5+2x^(2) =-6x$

rewrite the quadratic equation

$2x^(2)+6x-5=0$

The formula to solve a quadratic equation of the form $ax^(2) +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

$2x^(2)+6x-5=0$

$a=2\nb=6\nc=-5$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^(2)-4(2)(-5)}} {2(2)}$

$x=\frac{-6(+/-)√(76)} {4}$

$x=\frac{-6(+/-)2√(19)} {4}$

$x1=(-6+2√(19))/(4)$

$x2=\frac{-6-2√(19)} {4}$

-5 + 2x² = -6x
rearrange the equation to the form ax² + bx + c = 0

=> 2x² + 6x - 5

use the quadratic formula to solve for the value(s) of x $-b ± \sqrt{ (b^(2) - 4ac)/(2a) }$

=> $-6 ± \sqrt{ (6^(2) - 4(2)(-5))/(2(2)) }$

=> $-6 ± \sqrt{ (36 - (-40))/(4) }$

=> $-6 ± \sqrt{ (76)/(4) }$

∴ x = $-6 + √( 19) }$ OR x = $-6 - √(19)$

x = - 1.64 ; x = - 10.36

your fixed expenses are $1,235.78/month. You want to save 5 months' worth for an emergency fund over a year's time. How much must you save each month?