MATHEMATICS HIGH SCHOOL

If postage costs $.54 for the first ounce and $.22 for the each additional ounce, calculate the cost of mailing a 10- ounce envelope. A. $2.20 B. $5.08
C. $2.52
D. $5.40

Answers

Answer 1
Answer:

Answer:

Hence, the total cost of mailing 10 ounces is:

$ 2.52

Step-by-step explanation:

If postage costs $.54 for the first ounce and $.22 for the each additional ounce.

i.e. cost of first ounce=$ 0.54.

Now let x denote the number of ounces after the first ounce,

Hence, the cost of x ounces=$ (0.22×x)=$ 0.22 x

Hence, the cost of mailing (x+1) ounces is: $ (0.54+0.22 x)

Now, we have to find the cost of  mailing a 10- ounce envelope.

i.e. after the first ounce we need 9 more ounces.

Hence, the total cost of mailing is calculated as:

=$ (0.54+0.22* 9)\n\n=$ (0.54+1.98)\n\n=$ 2.52\n

Hence, cost of mailing 10 ounces is:

$ 2.52
Answer 2
Answer: 10-first oz=9oz
0.54 for first
0.22 times 9=1.98
total is 1.98+0.54=2.52

C

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Answers

The probability of rolling a 6-sided die and getting a 1 or a prime number is 0.66 or 66%.

What is the probability?

The probability is defined as the ratio of number of favourable outcomes and the the total number of possible outcome.

Assuming the die is numbered 1 to 6.

To answer the question, we first need to know many prime numbers can be represented on the die.  What are the prime numbers equal to 6 or lower?

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brainly.com/question/11234923

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4/6 is the probability, is this what you needed?

How do I find the "Greatest Common Factor" of 7z^11, −56z^9, 63z^8?I think it is "7", but cannot figure out the variable exponent...HELP!!!

Answers

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Solve the following system of equations using substitution.u = 6 + t
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C. t = 14, u = 20
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Answers

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Circle B has an area of 675 sq meters. What is the diameter of Circle B.

Answers

Answer:

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the length and width of a rectangular room are measured to be 3.955 plus-or-minus 0.005 m by 3.050 plus-or-minus 0.005 m. what is the area of the room and its uncertainty in square meters?

Answers

Step-by-step explanation:

To calculate the area of the room, we multiply its length by its width.

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To find the uncertainty in the area, we need to consider the maximum and minimum possible values for both the length and width.

The maximum length = (3.955 m + 0.005 m) = 3.960 m

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Maximum Area = (3.960 m)(3.055 m) = 12.07572 m²

Minimum Area = (3.950 m)(3.045 m) = 12.033 m²

So the area of the room is 12.06275 m² with an uncertainty of +/- 0.04272 m².

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