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Write the full ionic equation and net ionic equation for sodium dihydrogen phosphate + calcium carbonate, sodium oxilate + calclium carbonate, and sodium hydrogen phosphate + calcium carbonate

Answers

Answer 1

Answer:

Answer:

Sodium dihydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + 2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Net ionic equation

2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Sodium oxalate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + C₂O₄²⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + CaC₂O₄(s)

Net ionic equation

C₂O₄²⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + CaC₂O₄(s)

Sodium hydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + 2 Na⁺(aq) + CO₃²⁻(aq)

Net ionic equation

HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + CO₃²⁻(aq)

Explanation:

Let's consider two kind of equations:

Full ionic equation: includes all ions and species that do not dissociate in water.
Net ionic equation: includes only ions that participate in the reaction (not spectator ions) and species that do not dissociate in water.

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If 6.81 mol of an ideal gas has a pressure of 2.99 atm and a volume of 94.35 L, what is the temperature of the sample?

Answers

Answer:

504.57 K.

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 6.81 moles

Pressure (P) = 2.99 atm

Volume (V) = 94.35 L

Gas constant (R) = 0.0821 atm.L/Kmol

Temperature (T) =.?

Using the ideal gas equation, the temperature of the ideal gas can be obtained as follow:

PV = nRT

2.99 × 94.35 = 6.81 × 0.0821 × T

282.1065 = 0.559101 × T

Divide both side by 0.559101

T = 282.1065 / 0.559101

T = 504.57 K.

Thus, the temperature of the ideal gas is 504.57 K.

How much heat is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling? Specific heat of water is c=4.184 J/(g oC) a 78.5 kJ b 15.7 kJ c 157 kJ d 1.57 kJ

Answers

The heat that is required to change the temperature of two cups of water (500 g) from room temperature (25◦C) to boiling

C) 157 kJ

Heat

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

Q=m* c* delta T

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat = 500 x 4.184 x 75

Heat = 156900 J

Heat = 156.9 KJ

Heat ~ 157.0 KJ (3.D.P)

Thus, the correct answer is C.

Learn more about "Heat":

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Answer:

Explanation:

Heat required= Mass of water x specific heat capacity of water x change in temperature of water required

$q \: = m * c * delta \: t$

M = 500g

C = 4.184 g°C

Delta T = 100 - 25(room temp) = 75°C

Heat needed= 500 x 4.184 x 75

= 156900 J

= 156.9 KJ

~ 157.0 KJ (3.D.P)

Which phase changes will result in an increase in energy of the substance

Answers

Answer:

when gas condenses to liquid the quantity of energy converts.

Explanation:

two phase changes where the heat in energy is released

potential energy. During a phase change, the heat added (PE increases) or released (PE decreases) will allow the molecules to move apart or come together. Heat absorbed causes the molecules to move farther apart by overcoming the intermolecular forces of

Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.

Answers

Answer:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Explanation:

Hello,

In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.

Best regards.

You have a copper cylinder at room temperature (20ºC). You find that the diameter of the copper cylinder is 3.52 cm and the mass of the cylinder is 94.6754 g. What is the length (h) of the copper cylinder in mm? The density of copper is 8.96 g/cm3. (2 points) 4. You

Answers

Answer:

10.8 mm

Explanation:

Step 1: Calculate the volume (V) of the copper cylinder

The cylinder has a mass of 94.6754 g and a density of 8.96 g/cm³. The volume of the cylinder is:

$94.6754 g * (1cm^(3) )/(8.96g) = 10.6 cm^(3)$

Step 2: Calculate the length (h) of the copper cylinder

The diameter (d) of the copper cylinder is 3.52 cm. We can calculate the length using the following expression.

$V = \pi * ((d)/(2))^(2) * h\nh = (4V)/(\pi * d^(2) ) = (4(10.6cm^(3) ))/(\pi * (3.52cm)^(2) ) = 1.08 cm$

Step 3: Convert the length to millimeters

We will use the relationship 1 cm = 10 mm.

$1.08cm * (10mm)/(1cm) = 10.8 mm$

Which is not a product of the fractional distillation of petroleum?A) Gasoline
B) Jet Fuel
C) steel

Answers

Answer:
Option-C, STEEL is not a product of the fractional distillation of petroleum.

Explanation:
Petroleum is the mixture of Hydrocarbons *carbon and hydrogen containing compounds) present beneath the Earth's surface. Petroleum is formed from the remains of animals and plants beneath earth's surface in an anaerobic conditions.
Petroleum contains from small hydrocarbons (gases) to medium (liquids) and long chain hydrocarbons (Solids). These hydrocarbons are separated from each other by Fractional Distillation method (separation due to difference in boiling points)
Gasoline is a derivative of one of the fraction of petroleum used in internal combustion engines.
Jet Fuel is also derived from Kerosene and Naphtha fractions of petroleum.
While, Steel is inorganic Alloy (mixture of metals) composed of mainly Iron, Carbon and other elements.

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