Factor this expression completely. 8r6 + 27s12

Answers

Answer 1
Answer:

The factor of the expression 8r⁶ + 27s¹² can be (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸) after using the identity a³+b³ = (a+b)(a²-ab+b²).

What is an expression?

It is defined as the combination of constants and variables with mathematical operators.

It is given that:

= 8r⁶ + 27s¹²

The above expression can be written as:

8r⁶ + 27s¹² = (2r²)³+(3s⁴)³

After applying the identity:

a³+b³ = (a+b)(a²-ab+b²)

= (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸)

Thus, the factor of the expression 8r⁶ + 27s¹² can be (2r²+3s⁴)(4r⁴-6r²s⁴+9s⁸) after using the identity a³+b³ = (a+b)(a²-ab+b²).

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Answer 2
Answer:

Answer:

a^3+b^3=(a+b)(a²-ab+b²)

8r^6+27s^12=(2r²)^3+(3s^4)^3=(2r²+3s^4)(4r^4-6r²*s^4+9s^8)


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Solve x2 – 12x + 11 = 0 by completing the square.Question 7 options:

x = –1


No Real Solutions


x = 11 and x = 1


x = 11

Answers

The solution to the quadratic equation x² - 12x + 11 = 0 is x = 11 and x = 1.

What is the solution to the quadratic equation?

Given the quadratic equation in the question:

x² - 12x + 11 = 0

To solve the quadratic equation x² - 12x + 11 = 0 by completing the square, first the constant term to the other side of the equation:

x² - 12x + 11 = 0

x² - 12x + 11 - 11 = 0 - 11

x² - 12x = -11

Next, find the value that is equal to the square of half of b:

( b/2 )² = ( -12/2 )² = (-6)²

Add (-6)² to each side of the equation:

x² - 12x + (-6)² = -11 + (-6)²

x² - 12x + 36 = -11 + 36

x² - 12x + 36 = 25

Factor the perfect trinomial sqaure:

( x - 6 )² = 25

Solve for x:

x - 6 = ±√25

x - 6 = ±5

x = 6 ± 5

Hence, x = 6 - 5 = 1

And x = 6 + 5 = 11.

Therefore, the values of x are 1 and 11.

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Answer:

Step-by-step explanation:

x^2 – 12x + 11 = 0

(x-11)(x-1)

x= 11, 1 completing the square

A solution containing 30% insecticide is to be mixed with a solution containing 50% insecticide to make 200 L of a solutions containing 42% insecticide. How much of each solution should be used?

Answers

Let x L of solution 1 is used 
and 2nd solution is (200-x)L

According to question,
30% of x + 50% of (200-x) = 42% of 200L
0.3x + 0.5(200-x) = 84
0.3x - 0.5x + 100= 84
0.2x = 16
x=80

Therfore 80L of solution 1 and 120L of solution 2 is mixed. 

on Tuesday elena completed 20 item of her math homework in 36 minute. at that same rate how long will it take her to complete 35 item for Wednesday math homework A.71 minute b.63 minute c. 41 minute d. 35 minute

Answers

H=Homework item(s)

-----------------

20H=36

So what is 35H?

--------------------

20H=36

H=36/20

H=18/10=9/5

----------------------

When H=9/5,

35H

=35*9/5

=315/5

=63

----------------------

* The answer is 63 minutes.

You arrive at a bus stop at 10 a.m., knowing that the bus will arrive at some time uniformly distributed between 10 and 10:30. What is the probability that you will have to wait longer than 10 minutes? If, at 10:15, the bus has not yet arrived, what is the probability that you will have to wait at least an additional 10 minutes?

Answers

Answer:

a) the probability of waiting more than 10 min is 2/3 ≈ 66,67%

b) the probability of waiting more than 10 min, knowing that you already waited 15 min is 5/15 ≈ 33,33%

Step-by-step explanation:

to calculate, we will use the uniform distribution function:

p(c≤X≤d)= (d-c)/(B-A) , for A≤x≤B

where p(c≤X≤d) is the probability that the variable is between the values c and d. B is the maximum value possible and A is the minimum value possible.

In our case the random variable X= waiting time for the bus, and therefore

B= 30 min (maximum waiting time, it arrives 10:30 a.m)

A= 0 (minimum waiting time, it arrives 10:00 a.m )

a) the probability that the waiting time is longer than 10 minutes:

c=10 min , d=B=30 min --> waiting time X between 10 and 30 minutes

p(10 min≤X≤30 min) = (30 min - 10 min) / (30 min - 0 min) = 20/30=2/3 ≈ 66,67%

a) the probability that 10 minutes or more are needed to wait starting from 10:15 , is the same that saying that the waiting time is greater than 25 min (X≥25 min) knowing that you have waited 15 min (X≥15 min). This is written as P(X≥25 | X≥15 ). To calculate it the theorem of Bayes is used

P(A | B )= P(A ∩ B ) / P(A) . where P(A | B ) is the probability that A happen , knowing that B already happened. And P(A ∩ B ) is the probability that both A and B happen.

In our case:

P(X≥25 | X≥15 )= P(X≥25 ∩ X≥15 ) / P(X≥15 ) = P(X≥25) / P(X≥15) ,

Note: P(X≥25 ∩ X≥15 )= P(X≥25) because if you wait more than 25 minutes, you are already waiting more than 15 minutes

-   P(X≥25) is the probability that waiting time is greater than 25 min

c=25 min , d=B=30 min --> waiting time X between 25 and 30 minutes

p(25 min≤X≤30 min) = (30 min - 25 min) / (30 min - 0 min) = 5/30 ≈ 16,67%

-  P(X≥15) is the probability that waiting time is greater than 15 min --> p(15 min≤X≤30 min) = (30 min - 15 min) / (30 min - 0 min) = 15/30

therefore

P(X≥25 | X≥15 )= P(X≥25) / P(X≥15) = (5/30) / (15/30) =5/15=1/3  ≈ 33,33%

Note:

P(X≥25 | X≥15 )≈ 33,33% ≥ P(X≥25) ≈ 16,67%  since we know that the bus did not arrive the first 15 minutes and therefore is more likely that the actual waiting time could be in the 25 min - 30 min range (10:25-10:30).

An amusement park has 11 roller coasters. In how many ways can you choose 4 of the roller coasters to ride during your visit to the park?

Answers

4!=4*3*2*1=24
11!=11*10*9*8*7*6*5*4*3*2*1=39916800
7!=7*6*5*4*3*2*1=5040
n choose k
how many ways are there to choose k rollercoasters from n choices?

\left(\begin{array}{ccc}n\nk\end{array}\right)=(n!)/(k!(n-k)!)

\left(\begin{array}{ccc}11\n4\end{array}\right)=(11!)/(4!(11-4)!)=(39916800)/(24(7)!)=(39916800)/(24(5040))=(39916800)/(120960)=330



330 ways






There are 34 balls in a bucket. The balls are numbered from 1 to 34. One ball is randomly selected from the bucket. What is the probability that ball #13 is chosen?

Answers

Answer:

1/34

Step-by-step explanation:

To find the probability that a specific number is chosen

P ( number 13) = 1/ total number of balls

                        = 1 /34

Answer:

1/34

Step-by-step explanation:

There is one 13 ball and there are 34 balls total.

1/34 is the answer. :)