Which statement best compares the energy involved in melting with the energy involved in boiling for a given liquid?A....Energy is removed from the particles in each change, but more energy is removed in melting than in boiling because the attractions are weaker.
B....Energy is removed from the particles in each change, but more energy is removed in boiling than in melting because the attractions are weaker.
C....Energy is added to the particles in each change, but boiling requires more energy than melting because the attractions must be completely overcome.
D....Energy is added to the particles in each change, but melting requires more energy than boiling because the attractions must be completely overcome.
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I hope this helps. Let me know if anything is unclear.
C. Energy is added to the particles in each change, but boiling requires more energy than melting because the attractions must be completely overcome.
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To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of O:C=2:1
molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus, number of moles can be calculated as follows:
n=\frac{m}{M}
calculating ratio,
O:C=\frac{2 g}{16 g/mol}:\frac{1 g}{12 g/mol}=\frac{1}{8}:\frac{1}{12}=12:8=3:2
thus, molecular formula will be C_{2}O_{3}
Final answer:
If the ratio of oxygen to carbon by mass is 2.00:1.00, the formula of the oxide of carbon is CO₂ (carbon dioxide). This is because CO₂ has twice as much oxygen per amount of carbon as compared to CO (carbon monoxide). This situation adheres to the law of multiple proportions.
Explanation:
This question revolves around the concept of stoichiometry in chemistry, particularly in relation to the law of multiple proportions and finding the formula of an oxide of carbon given specific mass ratios.
Firstly, in carbon monoxide (CO), the ratio of oxygen to carbon by mass is 1.33:1.00.
However, when the ratio of oxygen to carbon by mass increases to 2.00:1.00, we are now dealing with a compound that contains twice as much oxygen per amount of carbon. In essence, this would be carbon dioxide (CO₂). The mass ratio of oxygen to carbon in CO₂ is indeed 2:1 (32 g/mol oxygen: 12 g/mol carbon).
This situation illustrates the law of multiple proportions - in this case, the two oxides of carbon (CO and CO₂) contain elements combined in ratios of small whole numbers.
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Answer:
3.56L will be the obtained volume
Explanation:
0.3 M → Molarity
These are the moles of solute (for this case, the solute is KOH) that are contianed in 1L of solution
We dissolved 60 g of solute, so let's determine the moles:
60 g . 1 mol/ 56.1 g = 1.07 moles
Molarity(mol/L) = Mol / Volume(L)
Let's replace data: 0.3M = 1.07 mol / Volume(L)
0.3 mol/L = 1.07 mol / volume
Volume = 1.07 mol / 0.3mol/L = 3.56 L
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Answer:
Just go out there and be yourself brother!
Explanation:
If she doesn't like you, she doesn't like the real you, therefore you don't deserve her! lol
Au3+ + 3e− Au
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Hydrogen is the first element, and has an A.N. of 1. Also, its very interesting how it doesn't need 8 valence electrons to be stable.
The second element is Helium, which has an A.N (atomic number) of two.
The first element of the periodic table is hydrogen (H), and the second element is helium (He).
Hydrogen, with atomic number 1, is the first element in the periodic table. It is the lightest and the most abundant element in universe. Hydrogen is a colorless, odorless gas and is the building block for all other elements.
Helium, with atomic number 2, is the second element in the periodic table. It is also a gas, but unlike hydrogen, it is inert and does not readily react with other elements. Helium is known for its low density, which makes it lighter than air, and it is commonly used for filling balloons and as a cooling medium in various scientific and industrial applications.
So, the first element of the periodic table is hydrogen (H), and the second element is helium (He).
To know more about periodic table here
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Answer : The atmospheric pressure of water if boiling at 81 °C will be 369 mmHg.
Explanation : The vapor pressure of boiling water can be calculated using the Antoine Equation:
log P = A - ,
where P is the pressure in mmHg,
A = 8.07131,
B = 1730.63
C = 233.426
and T = temperature in °C (81°C)
Substituting the given values, we get,
Log P = 8.07131−
Therefore, Log P =8.07131 − 5.5041 = 2.567.
Now, P = =369 mmHg.
Hence, the atmospheric pressure will be 369 mmHg.