As part of a study of the effects of urbanization, local scientists have taken many data samples over the course of 20 years. The scientists detected increases in local soil erosion, carbon dioxide levels, and air temperatures. What most likely caused these changes?A erosion of topsoil

B altered water flow

C deforestation of woodlands

D decreased water quality

Answers

Answer 1

Answer:

Answer:

Option (C)

Explanation:

In order to set up urbanization in a selected area, initially, a large number of trees are being cut down. This process is commonly known as deforestation.

The deforestation process has various impacts on the environment and the climatic condition at various places. Extensive cutting down of trees leads to the occurrence of rapid soil erosion, where the materials from the topsoil are entirely carried away by wind and water. Due to this, there occurs a high absorption of incoming solar energy that increases the temperature of that area.

In addition to this, trees are the main source from which the oxygen is provided. The absence of trees also leads to an increase in the amount of carbon dioxide because the carbon dioxide will not be absorbed by the trees and in return, it won't be able to provide us oxygen. Due to this, the amount of carbon dioxide also increases.

Thus, the above changes are caused due to the deforestation of woodlands.

Hence, the correct answer is option (C).

Answer 2

Answer:

Explanation:

deforestation of woodland

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A spoon can sound like bell no this is not a riddle it science prove it

Answers

Metals have a property of being sonorous, that is they make ringing sounds when stuck hard and dpoon and bell both are made of metals.

An artificial satellite circling the Earth completes each orbit in 129 min(a) Find the altitude of the satellite.

(b) What is the value of g at the location of this satellite?

Answers

(a) $2.09\cdot 10^6 m$ above Earth's surface

The orbital speed of a satellite orbiting the Earth can be found using the equation

$v=\sqrt{(GM)/(r)}$

where

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

r is the radius of the satellite's orbit

The orbital speed can also be rewritten as the ratio between the circumference of the orbit and the orbital period, T:

$(2\pi r)/(T)$

where

T = 129 min = 7740 s is the period

Combining the two equations,

$(2\pi r)/(T)=\sqrt{(GM)/(r)}$

And solving for r,

$((2\pi)^2 r^2)/(T^2)=(GM)/(r)\nr=\sqrt[3]{(GMT^2)/((2\pi)^2)}=\sqrt[3]{((6.67\cdot 10^(-11))(5.98\cdot 10^(24))(7740)^2)/((2\pi)^2)}=8.46\cdot 10^6 m$

This is, however, the orbital radius: this means we have to subtract the Earth's radius to find the altitude of the satellite, which is

$R=6.37\cdot 10^6 m$

therefore, the altitude of the satellite is

$h=r-R=8.46\cdot 10^6 - 6.37\cdot 10^6 =2.09\cdot 10^6 m$

b) $5.57 m/s^2$

The value of g at the location of the satellite is given by

$g=(GM)/(r^2)$

where:

G is the gravitational constant

$M=5.98\cdot 10^(24) kg$ is the Earth's mass

$r=8.46 \cdot 10^6 m$ is the radius of the satellite's orbit

Substituting into the equation, we find

$g=((6.67\cdot 10^(-11))(5.98\cdot 10^(24)))/((8.46\cdot 10^6)^2)=5.57 m/s^2$

Final answer:

The satellite orbits at an altitude of approximately 800 km. The gravitational constant, 'g', at this location is approximately 8.66 m/s^2.

Explanation:

The orbital period of an artificial satellite can be used to calculate the altitude at which it orbits. For a satellite that completes each orbit in 129 min (or approximately 2.15 hr), we can apply Kepler's third law which states that the square of the period of a satellite is proportional to the cube of its semi-major axis (distance from the center of the Earth to the satellite).

The formula for the altitude is given by: h = [(GMT^2)/(4π^2)]^(1/3) - R, where G is the gravitational constant, M the mass of Earth, T the orbital period, and R the Earth's radius. With the values G=6.67 x 10^-11 N(m/kg)^2, M=5.98 x 10^24 kg, T=2.15 hr = 7740s, and R=6.371 x 10^6 m, we get h approximately equals 800 km.

The value of 'g' at the satellite's location is given by g = GM/(R+h)^2. Substituting the aforementioned values, we get g to be approximately 8.66 m/s^2. This is less than the 9.81 m/s^2 at Earth's surface due to the increased distance from the Earth's center.

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A scientific study is repeated by four different groups. Only two groups get the same results. Are the data reproducible?

Answers

No, one more group must get the same result as the other group. This will make it more reliable and reproducible.

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Answers

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Answers

force of gravitation between two different masses is given by

$F = (Gm_1m_2)/(r^2)$

here in first case we will have

$F_1 = (G(1kg)(2kg))/((1m)^2)$

$F_1 = 2G$ Newton

another case we have

$F_2 = (G(1kg)(2kg))/((2m)^2)$

$F_2 = (G)/(2)$ Newton

another case we have

$F_3 =(G(2kg)(2kg))/((1m)^2)$

$F_3 = 4G$ Newton

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Answers

You're question should really be "what pushes current through a circuit". Current is simply the flow of electrons in a circuit. Electricity is a quite difficult concept to grasp. If you imagine the current as the water in a pipe then the voltage would be the pressure forcing it through the pipe.

Final answer:

The force that pushes electrons along in a circuit is called the electric field.

Explanation:

The force that pushes electrons along in a circuit is called the electric field. The electric field in a wire points from the higher potential end to the lower potential end and provides the force necessary to keep the electrons moving. The electrons, carrying a negative charge, move on average in the opposite direction of the electric field.

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