. A quadrilateral has four right angles. What figure could it be? Select All That Applyparallelogram
square
rectangle
rhombus

Answers

Answer 1
Answer: It has to be a square and a rectangle because they are the only ones with for right angles.
Answer 2
Answer: The answers are square and rectangle and rhombus because a parallelogram has a different angle for its corners 

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Which of the following statements best defines independent events?A. Two events are independent events if it is impossible for the two events to occur simultaneously. B. Two events are independent events if the occurrence of one event has no effect on the probability of the other. C. Two events are independent events if the intersection between the sample spaces of the two events is not empty. D. Two events are independent events if the union of the sample spaces of the two events is not empty.
Anyone know it’s middle school work
Write three powers with whole-number bases that have values greater than 120 and less than 130. The three powers, in order from least to greatest, are , , and .

A certain bacteria population is known to quadruples every 150 minutes. Suppose that there are initially 200 bacteria. What is the size of the population after t hours?

Answers

This is a geometric progression
The size of the population afeter t hours will be=a₁*r^n

a₁= the first term =200
r=common ratio=4

150 minutes=150 minutes * (1 hour /60 minutes)=2.5 hours.

In this case:
the size of the populatation after t hours=200*4^t/2.5=200*4^0.4t

To check
 t=0⇒ the size will be=200*4⁰=200*1=200
t=2.5 hours=150 minutes; the size will be =200*4¹=800
t=5 hours; the size will be=200*4²=200*16=3200

Answer: the size will be= 200*4^(0.4t)

Final answer:

The growth of the bacteria is represented by the exponential growth equation. Given the initial population, the four-fold increase, and the time interval for the increase, we can find the population after any given time by using the equation P = 200 * 4^(t/2.5).

Explanation:

The problem given is an example of an exponential growth problem. For these types of problems, we use the formula P = P0 * e^(kt), where P is the final population, P0 is the initial population, k is the growth rate, and t is time. However, in this case, we were given that the bacteria quadruples, meaning 'quadrupling' is not a continuous rate, so we use a slightly different form of the equation: P = P0 * (b)^(t/t0), where b is the times increase and t0 is the time interval for the b-fold increase.

Given that the initial population P0 is 200 bacteria, b is 4 because the population quadruples every 150 minutes, and time t0 is 150 minutes or 2.5 hours. We need to find the population P after t hours. Substituting these values into our equation gives us: P = 200 * 4^(t/2.5).

So, after t hours, the population of the bacteria will be given by the equation P = 200 * 4^(t/2.5).

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5 t-shirts and a hat costs £27.00 2 t-shirts and a hat costs £12.00.
How much does a t-shirt cost?
How much does a hat cost?

Answers

Answer:

£2

Step-by-step explanation:

Let T represent T-shirt and H represent hat

5T + H = £27.00

2T + H = £12.00 Subtract two equation

5T + H - 2T - H = £27 - £12 ➡ 3T = £15 and T = £5 this is the cost for a t-shirt

If a t-shirt costs £5 and 2 t-shirt + a hat costs £12 then a hat costs £2

Let say that t-shirt is X and hat is Y
We get: 5X+Y=27.00
2X+Y=12.00
solve for X in the first equation
5X+Y= 27
5X=27-Y
X=27-Y/5
Replace X= 27-Y/5 in equation 1 or 2
I use equation 2:
2*27-Y/5+Y=12
54-2Y/5+Y=12
make the denominator equal
54-2Y/5+5Y/5=12
54+3Y/5=12
Multiply 5 both side
54+3Y = 60
3Y = 60-54
3Y= 6
Y=6/3
Y=2
Replace Y= 2 in equation 1 or 2
I use 2:
2X+2=12
2X=10
X=5
Thus the answer is T-shirt cost : £5 and hat cost : £2

determine if the sequence is geometric or arithmetic and find the ratio or difference. -1, 6, -36, 216

Answers

The sequence is an geometric progression;
Nth=a₁r^(n-1)
a₁ is the first term=-1
r=ratio=a₂/a₁=6/-1=-6

Nth=-1(-6^(n-1)

NTh=an

a
₁=-1(-6⁰)=-1
a₂=-1(-6¹)=6
a₃=-1(-6²)=-36
a₄=-1(-6³)=216

therefore this serie is rising at an increasing fast speed, it is an geometric progression.


8-m/7=18 ................

Answers

Answer:

m= -84

Step-by-step explanation:

Step 1- Multiply both sides by 7

42-m= 126

Step 2- Move constant to the right hand side and change its sign

-m= 126-42

Step 3- Subtract the numbers

-m= 84

Step 4- Change the signs on both sides of the equation

m= -84

If it is 3:00 pm here and Australia is 13 hours ahead of us. What time is it in Australia?

Answers

Okay so....
if it is 3 a.m. at your location, then it would be 1600 hours or 4 p.m. at the location in Australia 
if it is 3 p.m. at your location, then it would be 0400 hours or 4 a.m the next day at that location in Australia. 
my best answer is that it would be at least 3:00am or 4:00am

Which of the following represents the probability of 3 successes in 5 trials?a. 3C5P(S)*P(775
c. 3C5P(S)?P(A15
b. 5C3P(S)3P(F2
d. 5C3P(S)3P(F)5

Answers

Final answer:

The probability of 3 successes in 5 trials is represented by '5C3P(S)³P(F)²'. This equation reflects the combination of possible successful events, multiplied by the probability of success raised to the number of successes, and the probability of failure raised to the number of failures.

Explanation:

The correct answer is d. 5C3P(S)³P(F)².

Probability of success in binomial problems is given by the equation P(S) = nCr * (p)ⁿ * (q)ⁿ-r where n is the number of trials, r is the number of successful trials, p is the probability of success, and q is the probability of failure (1-p). In this case, there are 5 trials and 3 successes, so your p to the power of 3 (P(S)³) represents the probability of success and the your q to the power 2 (P(F)²) represents the probability of failure. The 5C3 in front is a combination which shows how many ways 3 successes can occur in 5 trials.

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Answer: option B: 5C3P(S)3P(F)2

Step-by-step explanation:

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