What is the value of the expression shown when x = –4?6 + 3(x – 5) – (x + 3)

A.
–9

B.
4

C.
2

D.
–20

Answers

Answer 1
Answer: 6 + 3(x - 5) - ( x + 3) =

it is best to simplify the expression
6 + 3x - 15 - x - 3 =

2x + 6 - 18 =

2x - 12 = 

Now we put the value of    x = -4

2 * (-4) - 12 = -8 - 12 = -20

2. way

6 + 3*(x – 5) – (x + 3)

immediately we insert a value of x = -4

6 + 3* (-4 -5) - (-4 + 3) =

6 + 3 * (-9) -(-1)=

6 - 27 +1 = -27 + 7 = -20

Aswer D : -20




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Perform the indicated operation. Answers.a. 10ab/3

b. 3/10ab

c. 10/3ab

Answers

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Find an expression for the function f(x) whose graph is a line passing through the points (6,-1) and (-3,-2). F(x) =

Answers

Answer:

Step-by-step explanation:

f(x) = ax+b

passing through the point (6,-1) : when    x = 6      f(x) = -1

means : -1 = a (6)+b

passing through the point (-3,-2) : when  x = -3     f(x) = -2

means : --2 = a (-3)+b

you have the system ::    6a +b = - 1......(1)

                                          -3a +b = -2........(2)

by (1) : b = -1 - 6a

by (2) : b = -2+3a

so : -2+3a  = -1 - 6a

3a+6a =2 -1

9a =1      a =1/9 put  the value of a in (1) or (2) : -3(1/9)+b = - 2

-1/3 +b = - 2

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Please someone help me and do not just write anything explain thank you . use the information provided to write the vertex form equation of each parabola. y= -2x^2-12x-28 I ended up with (6,-64) is that correct? And remember to add 28 to both sides first PPPPPPPPPPPLLLLLZZZ SOOOOOMMMMONE HEEEELP ME

Answers

ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c

the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating


y=-2x^2-12x-28
a=-2
b=-12

xvalue of vertex is -(-12)/(2*-2)=12/-4=-3

x value of vertex is -3

plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10

yvalue is -10
x value is -3

vertex is (-3,-10)

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Answers

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Step-by-step explanation:

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