PHYSICS HIGH SCHOOL

Dan was running and he tripped and hurt his knee. the pain signals were carried to his brain by the?

Answers

Answer 1

Answer:

Answer:Central nervous system

Explanation:

Answer 2

Answer: the pain was triggered by the Nervous System

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Potential and kinetic energy 1. An apple falling from a tree 2. A stationary ball on the ground 3. A sleeping dog 4. A boy running across the street 5. A car traveling on the road 6. A stretched rubber band 7. A basketball being thrown 8. A girl biking at the park 9. A leaf lying on the ground 10. A planet revolving around a star

The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car’s motion? A. It’s not moving. B. It’s moving at a constant speed. C. It’s moving at a constant velocity. D. It’s speeding up. i dont know if ive asked this before if i have sorry

Answers

answer i think its d because the car is gradually going up

Final answer:

A horizontal line on a position-time graph represents a stationary object or, in this case, a parked car. The car is not moving since there's no change in position over time. Speed or velocity would be depicted by the slope of the line on the position-time graph.

Explanation:

Your question pertains to understanding what a horizontal line on a position-time graph indicates about a car's motion. In the context of a position-time graph, a horizontal line suggests that the position of the car is not changing with respect to time, indicating option A: The car is not moving. The car being stationary means there is no change in position over time, hence the horizontal line on the graph.

Options B, C, and D suggest a change in position over time, which would be represented by a slanted line, not a horizontal one. Option B: 'moving at a constant speed' and Option C: 'moving at a constant velocity' would both produce a straight line with a slope, not a horizontal line. Option D: 'speeding up' would be represented by a curved line, showing acceleration.

In contrast, a stationary object or a car at rest is represented by a horizontal line on a position-time graph. Velocity or speed, on the other hand, is determined by the slope of the line on a position-time graph. Hence, a horizontal line, having no slope, signifies zero speed or velocity, indicating that the car is not moving.

Learn more about Position-Time Graph here:

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A car drives west with a speed of 65 km/h. What is the car's speed? What is the car'svelocity?!

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Speed = 65 km/h
Velocity = 65 Km/h due west

The highest surface wind speeds occur when there is a

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The correct answer to the question above is 20 millibar pressure difference between two near locations. The highest surface winds speed occur when there is a 2- millibar pressure difference between two nearby locations. Wind speed or also called as wind velocity is caused by the higher air pressure going to low.

An oil tanker, initially traveling west at 18 km/h is accelerated uniformly until it is traveling east at 21.6 km/h. The acceleration is 0.20 m/s2 towards the east. Compute the total displacement from the tanker’s initial position.Answer in meters.

Answers

Answer:

27.5 m

Explanation:

Given:

u = 18 km/h = 5 m/s

v = 21.6 km/h = 6 m/s

a = 0.20 m/s²

Find: s

v² = u² + 2as

(6 m/s)² = (5 m/s)² + 2 (0.20 m/s²) s

s = 27.5 m

When an object is at a distance of twice the focal length from a concave lens, the image produced is virtual and smaller than the object. What happens to the image if the object is shifted closer to the lens to a point one focal length away from it?The image produced is virtual and enlarged.
The image produced is virtual and smaller than the object.
The image produced is real and enlarged.
The image produced is real and smaller than the object.
The image produced is virtual and of the same size as the object.

Answers

Answer:

The image produced is virtual and smaller than the object.

Explanation:

For concave lens we know that

$(1)/(d_i) + (1)/(d_o) = (1)/(f)$

here we have

$(1)/(d_i) + (1)/(2f) = -(1)/(f)$

$(1)/(d_i) = - (3)/(2f)$

$d_i = -(2f)/(3)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -2/3$

so image will be virtual and formed behind the lens

Now the object position is shifted to new position at distance of focal length

now again we will have

here we have

$(1)/(d_i) + (1)/(f) = -(1)/(f)$

$(1)/(d_i) = - (2)/(f)$

$d_i = -(f)/(2)$

Magnification will be given as

$M = (d_i)/(d_o)$

$M = -1/2$

So again we will have virtual image with magnification 1/2

so here size of image is less than object size by factor of 1/2 and it is virtual

The right answer for the question that is being asked and shown above is that: "The image produced is virtual and of the same size as the object." the image if the object is shifted closer to the lens to a point one focal length away from it is that The image produced is virtual and of the same size as the object.

The distribution of total body protein in healthy adult men is approximately Normal, with mean 12.3 kg and standard deviation 0.1 kg. If you take a random sample of 25 healthy adult men, what is the probability that their average total body protein is between 12.25 and 12.35 kg?