Jason has two bags with 6 tiles each. The tiles in each bag are shown below:1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

Answers

Answer 1
Answer:

The probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

Given;

numbers of tiles in each bag, 1, 2, 3, 4, 5, 6

To find:

the probability of drawing a tile numbered 5 from the first bag and;

an odd tile from the second bag

The first draw: there is only one tile numbered 5

The \ probability = (1)/(6)

The second draw: there are 3 odd numbers (1, 3, 5)

The \ probability = (3)/(6) = (1)/(2)

The combined probabilities:

The \ probability = (1)/(6) * (1)/(2) = (1)/(12)

Therefore, the probability of drawing a tile numbered 5 from the first bag and an odd tile from the second bag is ¹/₁₂

To learn more about probability, please visit: brainly.com/question/24141156

Answer 2
Answer: To answer this question, you can use basic probability: The chance of getting tile number 5 from the first bag is 1/6 as it is for all other tiles in the same bag. The chance of getting an odd tile from the second bag is 3/6 as it is for getting an even tile. By multiplying the two, we get a total probability of 1/12.

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9. to find angle 6 just do 180-95 because a straight line is 180 degrees
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Answers

Answer:

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Step-by-step explanation:

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Answers

336 - (71+71) = 194
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Hope this helped :)

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Answers

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The pressure at sea level is 11 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of 2323 meters, the pressure around her is 3.33.3 atmospheres. The pressure pp in atmospheres is a function of xx, the depth in meters. Write the function's formula.

Answers

Answer:

p(x) = 0.1x + 1

Step-by-step explanation:

Pressure at sea level = 1 atmosphere

Depth dove by Sydney = 23 meters

Pressure at a depth of 23 meters = 3.3 atmospheres

So,

Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney

where k is  the diving rate constant

=> 3.3 = 1 + k(23)

=> 3.3 = 23k + 1

Subtracting 1 from both the sides, we get

3.3 - 1 = 23k + 1 -1

Cancelling out the +1 and -1 from the right side, we get

2.3 = 23k

=> 23k = 2.3

Dividing both sides by 23, we get

(23k)/(23) = (2.3)/(23)

Cancelling out the 23's from the top and bottom of the left side, we have

k = 0.1

Plugging in the value of k in the equation, we get

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=> p(x) = 1 + 0.1(x)

=> p(x) = 0.1x + 1

Answer:

0.1x + 1

Step-by-step explanation:

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Answers

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