All of the following are equivalent except _____.a.33%

b.0.3

c.1/3

d.33.3

Answers

Answer 1

Answer: D is not right. So your answer is D

Answer 2

Answer: yeah your answer is 33.3 because its equalent so when you do pemdas you get that answer

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Which answer shows 2.13786x10^4 written in standard form

What is the slope and y-intercept of this equation?
2x+4y=14

Answers

Equations don't have slopes or y-intercepts, but their graphs might.
Let's solve this equation for 'y', and see whether its graph has them.

2x + 4y = 14

Subtract 2x from each side: 4y = -2x + 14

Divide each side by 4 : y = -1/2x + 7/2 .

In this form, we can look at the equation, and see immediately that
if we were to draw its graph, then the graph would be a straight line
with slope= -1/2 and y-intercept= 7/2 .

What is a common factor of 34

Answers

You need to give 2/more numbers to obtain a common factor.

sorry you need 1 more to find the common factor

John, Sally, and Natalie would all like to save some money. John decides that itwould be best to save money in a jar in his closet every single month. He decides
to start with $300, and then save $100 each month. Sally has $6000 and decides
to put her money in the bank in an account that has a 7% interest rate that is
compounded annually. Natalie has $5000 and decides to put her money in the
bank in an account that has a 10% interest rate that is compounded continuously.

How much money have after 2 years?

How much money will sally have in 10 years?

What type of exponential model is Natalie’s situation?

Write the model equation for Natalie’s situation

How much money will Natalie have after 2 years?

How much money will Natalie have after 10 years

Answers

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^(t)$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+(r)/(n))^(nt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\n r=7\%=0.07\nn=1$

substitute in the formula above

$A=6,000(1+(0.07)/(1))^(1*t)\n A=6,000(1.07)^(t)$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(10)=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(2)=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^(rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\nr=10\%=0.10$

substitute in the formula above

$A=5,000(e)^(0.10t)$

Applying property of exponents

$A=5,000(1.1052)^(t)$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^(0.10*10)=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^(0.10*2)=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

PLEASE ANSWER QUIC, forget the answer I put

Answers

answer is 0.75

0.75 x 100= 75

.75 since 75 is 3/4 (or .75) of 100
Since 1 meter equals 100 centimeters and there is 75 centimeters your answer is .75

State the additive property of zero, and provide an example using any other number

Answers

The sum of any number and zero is the original number. 0+4=0

8v-3v-3+7v simplified

Answers

Your answer is 12v-3.

Steps:

1. Group Like Terms. (8v-3v+7v-3)

2. Add Similar Elements. (8v-3v+7v=12v)

3. Finished. (=12v-3)

Hope this helped :)

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All of the following are equivalent except _____.a.33% b.0.3 c.1/3 d.33.3

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All of the following are equivalent except _____.a.33%

b.0.3

c.1/3

d.33.3