Karen measured an Orange and a tangerine. The orange Weighed 3/4 pounds. The tangerine weighed 4/6 pounds.which was heavier? Write an inequality to show how their weights compare

75 percent of the number 140 is 105.

Let the unknown number be x.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Here, 75% of x is 105

75% of x= 105

75/100 ×x= 105

0.75x=105

x=105/0.75

x= 140

Therefore, 75 percent of the number 140 is 105.

To learn more about the percentage visit:

brainly.com/question/24159063.

#SPJ6

I cant see all the question but this  is how you find the derivative of your function using the product rule.

Here you use the extension of the product rule to 3 factors which we'll write as:-

f(x), g(x) and h(x):-

Derivative =  f'(x) g(x) h(x) + f(x) g'(x) h(x) + f(x) g(x) h'(x)

(3x - 1)(x + 4)(2x - 1)

derivative =  3(x + 4)(2x - 1) + (3x + 1)(1)(2x - 1) + (3x - 1)(x + 4)(2)

=  3(x + 4)(2x - 1) + (3x + 1)(2x - 1) + 2(3x - 1)(x + 4)

Using the normal distribution, it is found that the z-scores are:

1) z = -0.8

2) z = 2.4

3) z = 0

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

• It measures how many standard deviations the measure is from the mean, either above the mean(positive z-score), or below(negative z-score).

Item 1:

0.8 standard deviations below the mean, hence z = -0.8.

Item 2:

2.4 standard deviations above the mean, hence z = 2.4.

Item 3:

The mean is 0 standard deviations from itself, hence z = 0.

A similar problem is given at brainly.com/question/24663213

Final answer:

A standard score (z-score) signifies how many standard deviations a data point is away from the mean. A data value 0.8 standard deviations below the mean has a z-score of -0.8, meanwhile, if it is 2.4 standard deviations above the mean, its z-score is 2.4. The mean in a normal distribution has a z-score of 0.

Explanation:

In the field of statistics, a standard score (also known as a z-score) represents how many standard deviations an element is from the mean. In a normal distribution, a data value located 0.8 standard deviations below the mean has a Standard Score: z = -0.8. This is because the z-score is negative when the data value is below the mean. Conversely, a data value located 2.4 standard deviations above the mean has a Standard Score: z = 2.4. As the data value is above the mean, the z-score is positive. Finally, for the mean value itself in a normal distribution, the Standard Score: z = 0 because the mean value is the center of distribution, hence no deviation from itself.

Learn more about Standard Score here:

brainly.com/question/24210074

#SPJ3