Sebanyak 0,2 mol gas ideal berada dalam wadah yang volumenya 10 liter dan tekanan 1 atm . berapakah suhu gas tersebut

Answers

Answer 1
Answer:

The temperature of the gas is about 600 K

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Further explanation

The Ideal Gas Law that needs to be recalled is:

\large {\boxed {PV = nRT} }

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Let us now tackle the problem !

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Question (Translation):

A total of 0.2 moles of ideal gas are in containers with volume of 10 liters and a pressure of 1 atm. What is the temperature of the gas?

Given:

number of moles = n = 0.2 moles

volume of gas = V = 10 liters

pressure of gas = P = 1 atm

gas contant = R = 0.0821 L.atm/mol.K

Unknown:

temperature of gas = T = ?

Solution:

PV = nRT

1 * 10 = 0.2 * 0.0821 * T

10 = 0.01642 * T

T = 10 / 0.01642

T \approx 600 \texttt{ K}

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Learn more

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Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure


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Answers

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Answers

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Answers

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If this answer is not correct I am truly sorry.