Why are solids good at transferring heat through conduction? A.The particles are close together. B.The particles do not move. C.The particles give off electromagnetic waves. D.The particles can slide past one another.

Answers

Answer 1
Answer:

Answer: the particles are close together

Explanation:

Answer 2
Answer: i think it's B. because in heat conduction particles doesn't move and the heat transfer from the high energetic power to less energetic particle

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A wave travels at a speed of 34 cm/s. It’s wavelength is 18 cm. What is the period of the wave?0.75 s

1.2 s

0.66 s

0.53 s

Regions of compression and rarefaction help define _______.

Electromagnetic waves

Longitudinal waves, but not transverse waves

Transverse waves, but not longitudinal waves

All mechanical waves

Answers

0.53 seconds
(Comment if you need calculations/explanation)

Longitudinal waves but not transverse waves

The acceleration due to gravity for an object on the surface of the Earth is g. The distance from the Earth to the Moon is roughly 60 RE, where RE is the radius of the Earth. What is the centripetal acceleration of the moon during its (roughly circular) revolution around the Earth

Answers

Answer:

The centripetal acceleration that the moon experiences will be almost equal to the gravitational force that the Earth does in the moon,

Now, remember these two things:

F = m*a

and Fg = G*M1*M2/r^2

the first equation says that the force applied to something is equal to the mass of the object times the acceleration.

The second equation is for the gravitational force, where G is a constant, M1 and M2 are the masses of both objects, in this case, the Earth and the moon, and r is the distance.

We know that the acceleration in the surface of the Earth is:

a = Fg/M2 = g = G*M1/(RE)^2

now, for the moon we will have:

a = G*M1/(60RE)^2 = (G*M1/(RE)^2) *(1/60^2)

Here the term in the left is equal to g, so we have:

(G*M1/(RE)^2) *(1/60^2) = g*(1/60^2)

So the centripetal acceleration of the moon is 60^2 = 3600 times smaller than g.

The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.00 106 J of work on the car. The car starts from rest at sea level and has a speed of 25.0 m/s at an altitude of 1.90 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are non conservative forces.

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Answer:

car. The car starts from rest at sea level and has a speed of 29.0 m/s at an altitude of 2.20x10^2 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.

Explanation:

When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above

Answers

Answer:

Please find the answer in the explanation

Explanation:

When you calculate the SLOPE of a line segment, what does the SLOPE represent? (Choose all that apply) the Distance traveled the Displacement the Velocity the Acceleration None of the above

The slope of any time graph can not give you distance or displacement except for position - time graph.

When you plot either distance or displacement against time, that is, distance time graph or displacement time graph, you can get speed or velocity as the slope of the line segment.

You can only acceleration as a slope in a line of best fit if velocity is plotted against time. That is, in a velocity time graph.

A fishing boat using sonar to locate fish is employing

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A fishing boat using sonar to locate fish is employing reflection.

DESPERATE WILL GIVE BRAILISTWhich of the following is NOT an agent of change in the rock cycle?
A. Cooling and crystallization
B. Weathering and erosion
C. Cementation and compaction
D. Drying and decaying

Answers

Answer:

A

Explanation: I don't think I ever heard of Crystalization being apart of the rock Cycle but I could be wrong hope this helps