Use this image to answer the following question. If there are only enough strawberries to produce 2 gallons of strawberry ice cream, how many gallons of chocolate ice cream can the shop efficiently produce?
Use this image to answer the following question. If there - 1

Answers

Answer 1
Answer:

15 gallons of chocolate ice cream the shop can efficiently produce.

What is a Graph?

Graph is a mathematical representation of relation between two objects.

The graph in the image shows relation between strawberry ice cream and chocolate ice cream.

There are only enough strawberries to produce 2 gallons of strawberry ice cream, then the chocolate ice cream that can be produced is determined by seeing the graph.

The graph shows 15 gallon of chocolate ice cream

To know more about Graph

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Answer 2
Answer: If there are only enough strawberries to produce 2 gallons of strawberry ice cream, the shop can efficiently produce 15 gallons of chocolate ice cream as shown in the figure above.

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Which of the following options correctly factorizes the algebraic expression x^2 + 16x - 36? A) (x + 18)(x - 2) B) (x + 6)(x + 6) C) (x + 12)(x - 3) D) (x + 9)(x - 4)

Answers

Answer:

A) (x + 18)(x -2)

Step-by-step explanation:

Factorizing the algebraic expression:

x² + 16x -36

Sum = 16

Product = -36

Factors: 18, (-2)

When we add the factors 18 + (-2), we get 16 and when we multiply the factors 18 * (-2), we get (-36).

Rewrite the middle term using the factors.

x² + 18x - 2x - 36

From the first two terms, take out the common term x and from the third and fourth terms, take out the common factor (-2).

x*(x + 18) - 2*(x + 18) = (x +18)(x - 2)

Answer: A) (x + 18)(x - 2)

Find the quadratic function y = a(x-h)^2whose graph passes through the given points (6, -1) and (4, 0). a) y = 1/4(x-5)^2 b) y = 1/4(x-5)^2 c) y = -1/4(x-6)^2 d) y = 1/4(x-6)^2

Answers

Answer: -1/2x - 2.

Step-by-step explanation:

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is

AI-generated answer

To find the quadratic function y = a(x-h) that passes through the points (6, -1) and (4, 0), we can substitute the given points into the equation and solve for a and h. Let's go through the steps:

1. Substitute the coordinates of the first point (6, -1) into the equation:

-1 = a(6 - h)

2. Substitute the coordinates of the second point (4, 0) into the equation:

0 = a(4 - h)

3. Now we have a system of two equations with two unknowns. We can solve this system to find the values of a and h.

From the equation -1 = a(6 - h), we can rewrite it as:

-a(6 - h) = 1

From the equation 0 = a(4 - h), we can rewrite it as:

-a(4 - h) = 0

4. Simplifying the equations, we get:

-6a + ah = 1 (equation 1)

-4a + ah = 0 (equation 2)

5. Subtracting equation 2 from equation 1 eliminates the ah term:

-6a + ah - (-4a + ah) = 1 - 0

-6a + ah + 4a - ah = 1

-2a = 1

6. Solving for a, we divide both sides by -2:

a = -1/2

7. Substitute the value of a back into either equation (let's use equation 2) to solve for h:

-4(-1/2) + h(-1/2) = 0

2 + h/2 = 0

h/2 = -2

h = -4

8. Now we have the values of a = -1/2 and h = -4. We can substitute these values back into the original equation y = a(x-h) to find the quadratic function:

y = -1/2(x - (-4))

y = -1/2(x + 4)

y = -1/2x - 2

Therefore, the quadratic function that passes through the points (6, -1) and (4, 0) is y = -1/2x - 2.

You deposit $4000 in an account earning 6% interest compounded continuously. How much money will you have in the account in 15 years?

Answers

Answer:

9586.232772

$4000×1.06( to the power of 15)=9586.232772

The quotient of 14t^5-10t^4-14t^3 divided by 2t^2

Answers

7t^3-5t^2-7t

Subtract the exponents when dividing.

The number of hours (H) that a candle will burn increases when the length of the candle (L) increases. Write the correct equation for this scenario, and solve for the number of hours when the length is 2.

Answers

H is directly proportional to l
H\alphaL
H=kL
when L=2, H=2k

The city park in which Allen plays is a square and measures exactly one million square feet. Which side dimensions produce the most accurate measurement of the park? A) 998.8 x 997.7 B) 998.84 x 997.73 C) 998.843 x 997.731 D) 999 x 998

Answers

A- 998.8×997.7=996502.76
B- 998.84×997.73=996572.6332
C- 998.843×997.731=996576.6252
D - 999×998=997002

So D is the answer