The amount of carbon in the atmosphere is about _____ of the total amount of carbon on Earth.a. 0.01%
b. 0.1%
c. 1%
d. 10%
Answers
Answer:
a) 0.01 %
Explanation:
The carbon in the atmosphere is mainly in the form of carbon dioxide (CO2).
The ammount of carbon is arround 700 gigatons and they represent the 0.01 % of the carbon on Earth.
Related Questions
Element X has five valence electrons, element Y has one valence electron, and element Z has five valence electrons. Which two of these elements are most likely to have similar properties? Explain your answer
The rare earth elements include
Measuring Physical Properties Lab ReportInstructions: In the Physical Properties lab, you will test the physical properties of different building materials in order to pick the appropriate materials for a new home in Tiny World. Record your observations and test measurements in the lab report below in the areas shaded in purple. You will submit your completed report to your instructor. Student Name Instructor Date Lab Objectives In this lab you will: • help the aliens, called Tinyians, build the best house on their planet called Tiny World. • experiment with different building materials to collect data to see which ones best meet the criteria for building a home on Tiny World. • test each building material for density, thermal and electrical conductivity, flexibility, and magnetism. Background Research: You will need to gather background research from the virtual lab to form a good hypothesis. Read the Welcome to Tiny World part of the lab. Use the background information you learn to answer the questions below. Describe the gravity of Tiny World. Part 1: Describe the reason your house will need magnets. Describe the climate of Tiny World. Hypothesis: In this section, include the IF/THEN statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment. A If we use _______ to build the roof of the house, then the temperature inside the house will remain cooler. B If we use_______ to build the walls and floors of the house, then the temperature inside the house will remain cooler. C If we use ______ to bring electricity into the home, then it will allow electricity to flow into the home at a faster rate. D If we use_______ to construct the latches on the windows and doors, then the magnetism will keep the latches secure. Part 2 Procedure: 1. You will test each building material for density, thermal and electrical conductivity, flexibility, and magnetism. 2. Record your observations in the data table provided below. 3. Repeat steps with all test materials. Data: Record the results of each of your physical property tests in the table below. Wood Clay Brick Iron Aluminum Copper Nickel Flexibility (?/10) Magnetism (number of paper clips) Thermal Conductivity (W/(m·K)) Electrical Conductivity (x107 S/m) Mass (g) 10g 10g 10g 10g 10g 10g Volume (cm3) Formula: L x W x H Density (g/cm3) Formula: D=M/V part 3 Conclusion Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words. 1 Using two to three sentences, summarize what you investigated and observed in this lab. 2 What was the independent variable in the lab? 3 What was the dependent variable in the lab? 4 Did each of your experiment results support, or fail to support your four hypotheses? A. B C. D. 5 Why do you think a building material's density is important when building homes or architectural structures? 6 Why wouldn’t you choose wood or aluminum for the latches on your house? 7 Which material has the highest thermal conductivity? 8 Which material has the highest electrical conductivity 9 Based on your data, explain why these materials have the highest thermal and electrical conductivity? 10 Think about where you live now or where you have lived in the past; use complete sentences to describe this environment and the weather.
An energy value of 3.313 × 10^{-19} joules is needed to break a chemical bond. What is the wavelength of energy needed to break the bond? (The speed of light = 3.00 × 10¹⁰ cm/sec; Planck’s constant = 6.626 × 10^{–34} J ⋅sec).A. 5.00 × 10¹⁸ cm B. 1.00 × 10¹⁵ cm C. 2.00 × 10⁵ cm D. 6.00 × 10^{–5}cm E. 1.20 × 10^{–8} cm Can someone explain me how to make this one step by step?
Answers
To calculate the mass percent of hydrogen in diethyl ether, we need to know the molar mass of hydrogen and the molar mass of diethyl ether. The molar mass of hydrogen is approximately 1 g/mol, while the molar mass of diethyl ether is approximately 74 g/mol.
The mass percent of hydrogen can be calculated using the following formula:
mass percent of hydrogen = (mass of hydrogen / total mass of compound) x 100%
Substituting the values for diethyl ether, we get:
mass percent of hydrogen = (2 x 1 g/mol / 74 g/mol) x 100% = 2.7%
Therefore, the mass percent of hydrogen in diethyl ether is approximately 2.7%.
Final answer:
The mass percent of hydrogen in diethyl ether is 1.36%.
Explanation:
To calculate the mass percent of hydrogen in diethyl ether, we need to determine the mass of hydrogen in the compound and divide it by the total mass of diethyl ether. The formula of diethyl ether is C4H10O, so the molar mass is 74.12 g/mol. The molar mass of hydrogen is 1.008 g/mol.
Mass percent of hydrogen = (mass of hydrogen / mass of diethyl ether) × 100%
Mass percent of hydrogen = (1.008 g/mol / 74.12 g/mol) × 100% = 1.36%
Learn more about mass percent of hydrogen here:
#SPJ2
(2) Pb-206 (4) Co-60
Answers
Final answer:
I-131 (Iodine-131) is the radioisotope used for diagnosing thyroid disorders. It is selectively taken up by the thyroid gland and its emissions allow for imaging of the gland.
Explanation:
The radioisotope used for diagnosing thyroid disorders is I-131 (Iodine-131). This radioisotope is used in medical procedures due to its unique characteristics. When consumed, it is selectively taken up by the thyroid gland. I-131 emits beta particles and gamma radiation which allows for imaging of the thyroid gland. This in turn helps health professionals diagnose if the thyroid is functioning normally or if disorders such as hyperthyroidism or tumors are present.
Learn more about I-131 Radioisotope here:
#SPJ11
Answers
Answers
In chromium-52 there are 28 neutrons, because 28 + 24 = 52.
In chromium-53 there are 29 neutrons, because 29 + 24 = 53
Remember the atomic number, identifies elements it is different for every element and it is the number of protons in that element. So by adding that to the number of neutrons you can get the mass number.
Final answer:
Chromium-50 has 26 neutrons, chromium-52 has 28 neutrons, and chromium-53 has 29 neutrons.
Explanation:
Chromium has an atomic number of 24, which means it has 24 protons. To determine the number of neutrons in each chromium isotope, subtract the atomic number from the mass number. For chromium-50, subtracting 24 from 50 gives you 26 neutrons. For chromium-52, subtracting 24 from 52 gives you 28 neutrons. And for chromium-53, subtracting 24 from 53 gives you 29 neutrons.
Learn more about Isotopes of Chromium here:
#SPJ12
The molar mass of NaBr is 102.9 grams and that of Pb(NO3)2 is 331.21 grams.
Answers
Answer: 193.4 grams
Explanation: According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
To calculate the moles, we use the equation:
According to stoichiometry
1 mole of reacts with 2 moles of
0.94 moles of will react with=
of
Mass of
Answer:
193.24g
Explanation:
Step 1:
The balanced equation for the reaction. This is illustrated below:
Pb(NO3)2(aq) + 2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)
Step 2:
Determination of the masses of Pb(NO3)2 and NaBr that reacted from the balanced equation. This is illustrated below:
Molar Mass of Pb(NO3)2 = 331.21g/mol
Molar Mass of NaBr = 102.9g/mol
Mass of NaBr from the balanced equation = 2 x 102.9 = 205.8g.
From the balanced equation,
Mass of Pb(NO3)2 that reacted = 331.21g
Mass of NaBr that reacted = 205.8g
Step 3:
Determination of the mass of NaBr that reacted with 311g of Pb(NO3)2. This is illustrated below:
From the balanced equation above,
331.21g of Pb(NO3)2 reacted with 205.8g of NaBr.
Therefore, 311g of Pb(NO3)2 will react with = (311x205.8)/331.21 = 193.24g of NaBr.
From the calculations made above, 193.24g of NaBr will react with 311g of Pb(NO3)2
Answers
Answer: The reactivity of a metal depends on how easily it loses electrons
The reactivity of metals is due to the difference in stability of their electron configurations as atoms and as ions. As they are all metals they will form positive ions when they react.