A storage closet holds twelve boxes stacked upon each other, with each box being 10 inches high. How many feet are there between the top of the third box and the bottom of the tenth box?

Answer:5

Step-by-step explanation:there are 6 boxes between the top of the 3rd box and the bottom of the 10th box.

Since each box is 10 inches tall, the length of the 6 boxes sum up to 60 inches.

and since 12 inches =1 feet,

Then 60 inches = 5 feet

How to solve

Let "y" = the unknown number of feet's

12 inches = 1 feet

60 inches = y

Cross multiply

> 12×y =60×1

> 12y =60

Divide both sides by 12 since you want the value of "y".

> 12y÷12=60÷12

So 12 cancels out leaving the final answer to be:

> y=5

Answer:

There are 5 feet between the top of the third box and the bottom of the tenth box.

Step-by-step explanation:

We just have to count how many boxes is between the top of the third one and the bottom of the tenth box, then we transform from inches to feet.

So, the problem says "from the top of the third box" this means that the inches that matters is form the fourth box. "the bottom of the tenth box" means that it's until the ninth box. In total, there are 6 boxes. If each box is 10 inches high, the total distance would be 6(10 inches) = 60 inches.

Now we have the total distance, we transform it to feet. We know that one feet is 12 inches, using the rule of three we have:

60 inches are equivalent to 5 feet.

Therefore, there are 5 feet between the top of the third box and the bottom of the tenth box.