In this equation, what should be the coefficients of the reactants and products?I2 + O2 ---> I4 O9

72.7%  is the percent by mass of oxygen in carbon dioxide. A percent is obtained by multiplying the result by 100.

One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.

Molar mass of oxygen = 32 g/mole

Molar mass of carbon dioxide = 44 g/mole

mass percentage of oxygen =(molar mass of oxygen/molar mass of carbon dioxide)×  100

=(32/44)×  100

=72.7%

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Answer : The percent by mass of oxygen in carbon dioxide is, 72.72%

Solution : Given,

Molar mass of oxygen = 16 g/mole

Molar mass of carbon dioxide = 44 g/mole

As we know that there are 2 atoms of oxygen and 1 atom of carbon present in the carbon dioxide.

So, the molar mass of oxygen, = 2 × 16 = 32 g/mole

Now we have to calculate the percent by mass of oxygen in carbon dioxide.

Now put all the given values in this expression, we get

Therefore, the percent by mass of oxygen in carbon dioxide is, 72.72%

a) They are solid at ambient temperatures of 25 ° C and pressure of 1 atm.

b) Ionic compounds represent high temperature melting and boiling.

 c) They are hard and brittle and then subjected to the impact, break easily, creating planar faces.

d) When dissolved in water, or pure liquid, carry electrical current due to the existence of ions that move freely and can be attracted by the electrodes, closing the electric circuit.

e) His solvent is water. 

Answer:

Just go out there and be yourself brother!

Explanation:

If she doesn't like you, she doesn't like the real you, therefore you don't deserve her! lol

The balanced reaction is: 

2Mg + O2 = 2MgO 

We are given the amount of  magnesium to be reacted with O2. This will be the starting point of the calculations.

4.00 g C3H8 ( 1 mol Mg/ 24.31 g Mg ) ( 1 mol O2 / 2 mol Mg ) ( 32.0 g O2 / 1 mol O2 ) = 2.63 g O2

Answer:

64.0 grams!

Explanation:

Use the mole ratios

To determine whether a chemical formula represents a compound or element that will not combust, you need to consider the elements present in the formula and their respective properties.

How we can determine combustibility?

First, check if the formula contains only one type of element. If it does, then it represents an element, and the question of whether it will combust or not is irrelevant, as elements do not combust.

If the formula contains two or more different elements, then it represents a compound. To determine if the compound will combust, you need to look at the properties of its constituent elements.

Some elements, such as noble gases (e.g., helium, neon, argon), have very low reactivity and are unlikely to combust under normal conditions. Therefore, if the compound contains only noble gases, it is unlikely to combust.

Other elements, such as metals, are more reactive and can combust under certain conditions, such as exposure to heat or oxygen. Therefore, if the compound contains a metal, you need to check the reactivity of that metal to determine if the compound will combust.

Similarly, non-metals can also be combustible under certain conditions, such as exposure to heat or other reactive substances. Therefore, if the compound contains a non-metal, you need to check the reactivity of that non-metal to determine if the compound will combust.

Overall, to determine if a compound or element will combust, you need to consider the properties of its constituent elements and any external conditions that may affect its reactivity.

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